let k be Nat; ( k < 25 implies for n being Nat st n * n <= k & n is prime & not n = 2 holds
n = 3 )
assume A1:
k < 25
; for n being Nat st n * n <= k & n is prime & not n = 2 holds
n = 3
let n be Nat; ( n * n <= k & n is prime & not n = 2 implies n = 3 )
assume that
A3:
n * n <= k
and
A4:
n is prime
; ( n = 2 or n = 3 )
n * n < 5 * 5
by A1, A3, XXREAL_0:2;
then
n < 5
by Th1;
hence
( n = 2 or n = 3 )
by A4, Lm2; verum