let i, j, h be natural Number ; ( i <> 0 & h = j * i implies j <= h )
assume
i <> 0
; ( not h = j * i or j <= h )
then consider k being Nat such that
A1:
i = k + 1
by Th6;
assume
h = j * i
; j <= h
then
h = (j * k) + (j * 1)
by A1;
hence
j <= h
by Th11; verum