let k be Nat; P1[k]
defpred S1[ Nat] means for n being Nat st n < $1 holds
P1[n];
A2:
for k being Nat st S1[k] holds
S1[k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume A3:
for
n being
Nat st
n < k holds
P1[
n]
;
S1[k + 1]
let n be
Nat;
( n < k + 1 implies P1[n] )
assume
n < k + 1
;
P1[n]
then
n <= k
by Th8;
then
(
n < k or (
n = k &
n <= k ) )
by XXREAL_0:1;
hence
P1[
n]
by A1, A3;
verum
end;
A4:
S1[ 0 ]
by Th2;
for k being Nat holds S1[k]
from NAT_1:sch 2(A4, A2);
then
for n being Nat st n < k holds
P1[n]
;
hence
P1[k]
by A1; verum