let r, s, t be Real; ( r >= 0 & s >= 0 & r + s < t implies ( r < t & s < t ) )
assume that
A1:
( r >= 0 & s >= 0 )
and
A2:
r + s < t
; ( r < t & s < t )
assume
( r >= t or s >= t )
; contradiction
then
( r + s >= t + 0 or s + r >= t + 0 )
by A1, XREAL_1:7;
hence
contradiction
by A2; verum