consider f being Function of [:F1(),F2(),F3():],F4() such that
A1:
for a being Element of F1()
for b being Element of F2()
for c being Element of F3() holds f . [a,b,c] = F5(a,b,c)
from MULTOP_1:sch 3();
take
f
; for a being Element of F1()
for b being Element of F2()
for c being Element of F3() holds f . (a,b,c) = F5(a,b,c)
let a be Element of F1(); for b being Element of F2()
for c being Element of F3() holds f . (a,b,c) = F5(a,b,c)
let b be Element of F2(); for c being Element of F3() holds f . (a,b,c) = F5(a,b,c)
let c be Element of F3(); f . (a,b,c) = F5(a,b,c)
thus
f . (a,b,c) = F5(a,b,c)
by A1; verum