let S be non empty set ; for BASSIGN being non empty Subset of (ModelSP (Inf_seq S))
for t being Element of Inf_seq S
for f, g being Assign of (Inf_seqModel (S,BASSIGN)) holds
( t |= f 'U' g iff ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) )
let BASSIGN be non empty Subset of (ModelSP (Inf_seq S)); for t being Element of Inf_seq S
for f, g being Assign of (Inf_seqModel (S,BASSIGN)) holds
( t |= f 'U' g iff ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) )
let t be Element of Inf_seq S; for f, g being Assign of (Inf_seqModel (S,BASSIGN)) holds
( t |= f 'U' g iff ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) )
let f, g be Assign of (Inf_seqModel (S,BASSIGN)); ( t |= f 'U' g iff ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) )
set S1 = Inf_seq S;
A1:
f 'U' g = Until_0 (f,g,S)
by Def53;
A2:
( ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) implies t |= f 'U' g )
proof
assume A3:
ex
m being
Nat st
( ( for
j being
Nat st
j < m holds
Shift (
t,
j)
|= f ) &
Shift (
t,
m)
|= g )
;
t |= f 'U' g
ex
m being
Nat st
( ( for
j being
Nat st
j < m holds
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE ) &
(Fid (g,(Inf_seq S))) . (Shift (t,m,S)) = TRUE )
proof
consider m being
Nat such that A4:
for
j being
Nat st
j < m holds
Shift (
t,
j)
|= f
and A5:
Shift (
t,
m)
|= g
by A3;
take
m
;
( ( for j being Nat st j < m holds
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE ) & (Fid (g,(Inf_seq S))) . (Shift (t,m,S)) = TRUE )
for
j being
Nat st
j < m holds
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE
proof
let j be
Nat;
( j < m implies (Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE )
assume
j < m
;
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE
then
Shift (
t,
j)
|= f
by A4;
hence
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE
;
verum
end;
hence
( ( for
j being
Nat st
j < m holds
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE ) &
(Fid (g,(Inf_seq S))) . (Shift (t,m,S)) = TRUE )
by A5;
verum
end;
then
Until_univ (
t,
(Fid (f,(Inf_seq S))),
(Fid (g,(Inf_seq S))),
S)
= TRUE
by Def51;
then
(Fid ((f 'U' g),(Inf_seq S))) . t = TRUE
by A1, Def52;
hence
t |= f 'U' g
;
verum
end;
( t |= f 'U' g implies ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) )
proof
assume
t |= f 'U' g
;
ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g )
then
(Fid ((Until_0 (f,g,S)),(Inf_seq S))) . t = TRUE
by A1;
then
Until_univ (
t,
(Fid (f,(Inf_seq S))),
(Fid (g,(Inf_seq S))),
S)
= TRUE
by Def52;
then consider m being
Nat such that A6:
for
j being
Nat st
j < m holds
(Fid (f,(Inf_seq S))) . (Shift (t,j,S)) = TRUE
and A7:
(Fid (g,(Inf_seq S))) . (Shift (t,m,S)) = TRUE
by Def51;
take
m
;
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g )
for
j being
Nat st
j < m holds
Shift (
t,
j)
|= f
by A6;
hence
( ( for
j being
Nat st
j < m holds
Shift (
t,
j)
|= f ) &
Shift (
t,
m)
|= g )
by A7;
verum
end;
hence
( t |= f 'U' g iff ex m being Nat st
( ( for j being Nat st j < m holds
Shift (t,j) |= f ) & Shift (t,m) |= g ) )
by A2; verum