let M be MidSp; for a, b, c, d, x, y being Element of M st x,y @@ a,b & x,y @@ c,d holds
a,b @@ c,d
let a, b, c, d, x, y be Element of M; ( x,y @@ a,b & x,y @@ c,d implies a,b @@ c,d )
assume A1:
x,y @@ a,b
; ( not x,y @@ c,d or a,b @@ c,d )
assume A2:
x,y @@ c,d
; a,b @@ c,d
(y @ x) @ (a @ d) =
(y @ a) @ (x @ d)
by Def3
.=
(x @ b) @ (x @ d)
by A1
.=
(x @ b) @ (y @ c)
by A2
.=
(y @ x) @ (b @ c)
by Def3
;
hence
a @ d = b @ c
by Th8; MIDSP_1:def 4 verum