let M be UltraMetricSpace; ( M is triangle & M is discerning )
now for x, y, z being Element of M holds
( ( dist (x,y) = 0 implies x = y ) & ( x = y implies dist (x,y) = 0 ) & dist (x,y) = dist (y,x) & dist (x,z) <= (dist (x,y)) + (dist (y,z)) )let x,
y,
z be
Element of
M;
( ( dist (x,y) = 0 implies x = y ) & ( x = y implies dist (x,y) = 0 ) & dist (x,y) = dist (y,x) & dist (x,z) <= (dist (x,y)) + (dist (y,z)) )thus
(
dist (
x,
y)
= 0 iff
x = y )
by Th25, Th1;
( dist (x,y) = dist (y,x) & dist (x,z) <= (dist (x,y)) + (dist (y,z)) )thus
dist (
x,
y)
= dist (
y,
x)
;
dist (x,z) <= (dist (x,y)) + (dist (y,z))
(
0 <= dist (
x,
y) &
0 <= dist (
y,
z) )
by Th26;
then A1:
max (
(dist (x,y)),
(dist (y,z)))
<= (dist (x,y)) + (dist (y,z))
by SQUARE_1:2;
dist (
x,
z)
<= max (
(dist (x,y)),
(dist (y,z)))
by Def19;
hence
dist (
x,
z)
<= (dist (x,y)) + (dist (y,z))
by A1, XXREAL_0:2;
verum end;
hence
( M is triangle & M is discerning )
by Th6; verum