let X be non empty set ; for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is E -measurable ) & f is nonnegative & A c= B holds
Integral (M,(f | A)) <= Integral (M,(f | B))
let S be SigmaField of X; for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is E -measurable ) & f is nonnegative & A c= B holds
Integral (M,(f | A)) <= Integral (M,(f | B))
let M be sigma_Measure of S; for f being PartFunc of X,ExtREAL
for A, B being Element of S st ex E being Element of S st
( E = dom f & f is E -measurable ) & f is nonnegative & A c= B holds
Integral (M,(f | A)) <= Integral (M,(f | B))
let f be PartFunc of X,ExtREAL; for A, B being Element of S st ex E being Element of S st
( E = dom f & f is E -measurable ) & f is nonnegative & A c= B holds
Integral (M,(f | A)) <= Integral (M,(f | B))
let A, B be Element of S; ( ex E being Element of S st
( E = dom f & f is E -measurable ) & f is nonnegative & A c= B implies Integral (M,(f | A)) <= Integral (M,(f | B)) )
assume that
A1:
ex E being Element of S st
( E = dom f & f is E -measurable )
and
A2:
f is nonnegative
and
A3:
A c= B
; Integral (M,(f | A)) <= Integral (M,(f | B))
consider E being Element of S such that
A4:
E = dom f
and
A5:
f is E -measurable
by A1;
A6:
ex C being Element of S st
( C = dom (f | A) & f | A is C -measurable )
proof
take C =
E /\ A;
( C = dom (f | A) & f | A is C -measurable )
thus
dom (f | A) = C
by A4, RELAT_1:61;
f | A is C -measurable
A7:
C = (dom f) /\ C
by A4, XBOOLE_1:17, XBOOLE_1:28;
A8:
dom (f | A) =
C
by A4, RELAT_1:61
.=
dom (f | C)
by A7, RELAT_1:61
;
A9:
for
x being
object st
x in dom (f | A) holds
(f | A) . x = (f | C) . x
f is
C -measurable
by A5, MESFUNC1:30, XBOOLE_1:17;
then
f | C is
C -measurable
by A7, Th42;
hence
f | A is
C -measurable
by A8, A9, FUNCT_1:2;
verum
end;
A11:
ex C being Element of S st
( C = dom (f | B) & f | B is C -measurable )
proof
take C =
E /\ B;
( C = dom (f | B) & f | B is C -measurable )
thus
dom (f | B) = C
by A4, RELAT_1:61;
f | B is C -measurable
A12:
C = (dom f) /\ C
by A4, XBOOLE_1:17, XBOOLE_1:28;
A13:
dom (f | B) =
C
by A4, RELAT_1:61
.=
dom (f | C)
by A12, RELAT_1:61
;
A14:
for
x being
object st
x in dom (f | B) holds
(f | B) . x = (f | C) . x
f is
C -measurable
by A5, MESFUNC1:30, XBOOLE_1:17;
then
f | C is
C -measurable
by A12, Th42;
hence
f | B is
C -measurable
by A13, A14, FUNCT_1:2;
verum
end;
integral+ (M,(f | A)) <= integral+ (M,(f | B))
by A1, A2, A3, Th83;
then
Integral (M,(f | A)) <= integral+ (M,(f | B))
by A2, A6, Th15, Th88;
hence
Integral (M,(f | A)) <= Integral (M,(f | B))
by A2, A11, Th15, Th88; verum