let X be non empty set ; for S being SigmaField of X
for F being Finite_Sep_Sequence of S ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) )
let S be SigmaField of X; for F being Finite_Sep_Sequence of S ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) )
let F be Finite_Sep_Sequence of S; ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) )
defpred S1[ Nat] means for F being Finite_Sep_Sequence of S st len F = $1 holds
ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) );
A1:
for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume A2:
S1[
n]
;
S1[n + 1]
let F be
Finite_Sep_Sequence of
S;
( len F = n + 1 implies ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) ) )
assume A3:
len F = n + 1
;
ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) )
reconsider n =
n as
Element of
NAT by ORDINAL1:def 12;
reconsider F1 =
F | (Seg n) as
Finite_Sep_Sequence of
S by MESFUNC2:33;
A4:
n <= len F
by A3, NAT_1:11;
then A5:
len F1 = n
by FINSEQ_1:17;
then consider G1 being
Finite_Sep_Sequence of
S such that A6:
union (rng F1) = union (rng G1)
and A7:
for
n being
Nat st
n in dom G1 holds
(
G1 . n <> {} & ex
m being
Nat st
(
m in dom F1 &
F1 . m = G1 . n ) )
by A2;
A8:
(
dom F = dom (F1 ^ <*(F . (n + 1))*>) & ( for
k being
Nat st
k in dom F holds
F . k = (F1 ^ <*(F . (n + 1))*>) . k ) )
proof
thus dom (F1 ^ <*(F . (n + 1))*>) =
Seg ((len F1) + (len <*(F . (n + 1))*>))
by FINSEQ_1:def 7
.=
Seg (n + 1)
by A5, FINSEQ_1:39
.=
dom F
by A3, FINSEQ_1:def 3
;
for k being Nat st k in dom F holds
F . k = (F1 ^ <*(F . (n + 1))*>) . k
let k be
Nat;
( k in dom F implies F . k = (F1 ^ <*(F . (n + 1))*>) . k )
assume A9:
k in dom F
;
F . k = (F1 ^ <*(F . (n + 1))*>) . k
now ( ( k in dom F1 & F . k = (F1 ^ <*(F . (n + 1))*>) . k ) or ( not k in dom F1 & F . k = (F1 ^ <*(F . (n + 1))*>) . k ) )per cases
( k in dom F1 or not k in dom F1 )
;
case A12:
not
k in dom F1
;
F . k = (F1 ^ <*(F . (n + 1))*>) . kA13:
k in Seg (n + 1)
by A3, A9, FINSEQ_1:def 3;
not
k in Seg n
by A4, A12, FINSEQ_1:17;
then
( not 1
<= k or not
k <= n )
by FINSEQ_1:1;
then A14:
not
k < n + 1
by A13, FINSEQ_1:1, NAT_1:13;
dom <*(F . (n + 1))*> = Seg 1
by FINSEQ_1:def 8;
then A15:
1
in dom <*(F . (n + 1))*>
by FINSEQ_1:2, TARSKI:def 1;
A16:
k <= n + 1
by A13, FINSEQ_1:1;
then (F1 ^ <*(F . (n + 1))*>) . k =
(F1 ^ <*(F . (n + 1))*>) . ((len F1) + 1)
by A5, A14, XXREAL_0:1
.=
<*(F . (n + 1))*> . 1
by A15, FINSEQ_1:def 7
.=
F . (n + 1)
;
hence
F . k = (F1 ^ <*(F . (n + 1))*>) . k
by A14, A16, XXREAL_0:1;
verum end; end; end;
hence
F . k = (F1 ^ <*(F . (n + 1))*>) . k
;
verum
end;
then A17:
F = F1 ^ <*(F . (n + 1))*>
by FINSEQ_1:13;
ex
G being
Finite_Sep_Sequence of
S st
(
union (rng F) = union (rng G) & ( for
k being
Nat st
k in dom G holds
(
G . k <> {} & ex
m being
Nat st
(
m in dom F &
F . m = G . k ) ) ) )
proof
now ( ( F . (n + 1) = {} & ex G, G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for k being Nat st k in dom G holds
( G . k <> {} & ex m being Nat st
( m in dom F & F . m = G . k ) ) ) ) ) or ( F . (n + 1) <> {} & ex G, G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for k being Nat st k in dom G holds
( G . k <> {} & ex m being Nat st
( m in dom F & F . m = G . k ) ) ) ) ) )per cases
( F . (n + 1) = {} or F . (n + 1) <> {} )
;
case A24:
F . (n + 1) <> {}
;
ex G, G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for k being Nat st k in dom G holds
( G . k <> {} & ex m being Nat st
( m in dom F & F . m = G . k ) ) ) )A25:
for
k,
m being
object st
k <> m holds
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
proof
let k,
m be
object ;
( k <> m implies (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m )
assume A26:
k <> m
;
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
now ( ( k in dom (G1 ^ <*(F . (n + 1))*>) & m in dom (G1 ^ <*(F . (n + 1))*>) & (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m ) or ( ( not k in dom (G1 ^ <*(F . (n + 1))*>) or not m in dom (G1 ^ <*(F . (n + 1))*>) ) & (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m ) )per cases
( ( k in dom (G1 ^ <*(F . (n + 1))*>) & m in dom (G1 ^ <*(F . (n + 1))*>) ) or not k in dom (G1 ^ <*(F . (n + 1))*>) or not m in dom (G1 ^ <*(F . (n + 1))*>) )
;
case A27:
(
k in dom (G1 ^ <*(F . (n + 1))*>) &
m in dom (G1 ^ <*(F . (n + 1))*>) )
;
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . mthen reconsider k =
k,
m =
m as
Element of
NAT ;
now ( ( k = len (G1 ^ <*(F . (n + 1))*>) & (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m ) or ( k <> len (G1 ^ <*(F . (n + 1))*>) & (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m ) )per cases
( k = len (G1 ^ <*(F . (n + 1))*>) or k <> len (G1 ^ <*(F . (n + 1))*>) )
;
case
k = len (G1 ^ <*(F . (n + 1))*>)
;
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . mthen
k = (len G1) + (len <*(F . (n + 1))*>)
by FINSEQ_1:22;
then A28:
k = (len G1) + 1
by FINSEQ_1:39;
1
<= len <*(F . (n + 1))*>
by FINSEQ_1:39;
then A29:
(G1 ^ <*(F . (n + 1))*>) . k =
<*(F . (n + 1))*> . 1
by A28, FINSEQ_1:65
.=
F . (n + 1)
;
A30:
m in Seg (len (G1 ^ <*(F . (n + 1))*>))
by A27, FINSEQ_1:def 3;
then
m in Seg ((len G1) + (len <*(F . (n + 1))*>))
by FINSEQ_1:22;
then
m in Seg ((len G1) + 1)
by FINSEQ_1:39;
then
m <= (len G1) + 1
by FINSEQ_1:1;
then
m < (len G1) + 1
by A26, A28, XXREAL_0:1;
then A31:
m <= len G1
by NAT_1:13;
1
<= m
by A30, FINSEQ_1:1;
then A32:
m in dom G1
by A31, FINSEQ_3:25;
then consider m1 being
Nat such that A33:
m1 in dom F1
and A34:
F1 . m1 = G1 . m
by A7;
m1 in Seg (len F1)
by A33, FINSEQ_1:def 3;
then
m1 <= n
by A5, FINSEQ_1:1;
then A35:
m1 <> n + 1
by NAT_1:13;
(G1 ^ <*(F . (n + 1))*>) . m = G1 . m
by A32, FINSEQ_1:def 7;
then
(G1 ^ <*(F . (n + 1))*>) . m = F . m1
by A17, A33, A34, FINSEQ_1:def 7;
hence
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
by A29, A35, PROB_2:def 2;
verum end; case
k <> len (G1 ^ <*(F . (n + 1))*>)
;
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . mthen
k <> (len G1) + (len <*(F . (n + 1))*>)
by FINSEQ_1:22;
then A36:
k <> (len G1) + 1
by FINSEQ_1:39;
A37:
k in Seg (len (G1 ^ <*(F . (n + 1))*>))
by A27, FINSEQ_1:def 3;
then
k in Seg ((len G1) + (len <*(F . (n + 1))*>))
by FINSEQ_1:22;
then
k in Seg ((len G1) + 1)
by FINSEQ_1:39;
then
k <= (len G1) + 1
by FINSEQ_1:1;
then
k < (len G1) + 1
by A36, XXREAL_0:1;
then A38:
k <= len G1
by NAT_1:13;
1
<= k
by A37, FINSEQ_1:1;
then A39:
k in dom G1
by A38, FINSEQ_3:25;
then A40:
(G1 ^ <*(F . (n + 1))*>) . k = G1 . k
by FINSEQ_1:def 7;
now ( ( m = len (G1 ^ <*(F . (n + 1))*>) & (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m ) or ( m <> len (G1 ^ <*(F . (n + 1))*>) & (G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m ) )per cases
( m = len (G1 ^ <*(F . (n + 1))*>) or m <> len (G1 ^ <*(F . (n + 1))*>) )
;
case
m = len (G1 ^ <*(F . (n + 1))*>)
;
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . mthen
m = (len G1) + (len <*(F . (n + 1))*>)
by FINSEQ_1:22;
then A41:
m = (len G1) + 1
by FINSEQ_1:39;
1
<= len <*(F . (n + 1))*>
by FINSEQ_1:39;
then A42:
(G1 ^ <*(F . (n + 1))*>) . m =
<*(F . (n + 1))*> . 1
by A41, FINSEQ_1:65
.=
F . (n + 1)
;
consider k1 being
Nat such that A43:
k1 in dom F1
and A44:
F1 . k1 = G1 . k
by A7, A39;
k1 in Seg (len F1)
by A43, FINSEQ_1:def 3;
then
k1 <= n
by A5, FINSEQ_1:1;
then A45:
k1 <> n + 1
by NAT_1:13;
(G1 ^ <*(F . (n + 1))*>) . k = F . k1
by A17, A40, A43, A44, FINSEQ_1:def 7;
hence
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
by A42, A45, PROB_2:def 2;
verum end; end; end; hence
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
;
verum end; end; end; hence
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
;
verum end; end; end;
hence
(G1 ^ <*(F . (n + 1))*>) . k misses (G1 ^ <*(F . (n + 1))*>) . m
;
verum
end;
1
<= n + 1
by NAT_1:11;
then
n + 1
in Seg (n + 1)
by FINSEQ_1:1;
then
n + 1
in dom F
by A3, FINSEQ_1:def 3;
then
F . (n + 1) in rng F
by FUNCT_1:3;
then
<*(F . (n + 1))*> is
FinSequence of
S
by FINSEQ_1:74;
then reconsider G =
G1 ^ <*(F . (n + 1))*> as
Finite_Sep_Sequence of
S by A25, FINSEQ_1:75, PROB_2:def 2;
A49:
len G =
(len G1) + (len <*(F . (n + 1))*>)
by FINSEQ_1:22
.=
(len G1) + 1
by FINSEQ_1:39
;
A50:
for
k being
Nat st
k in dom G holds
(
G . k <> {} & ex
m being
Nat st
(
m in dom F &
F . m = G . k ) )
take G =
G;
ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for k being Nat st k in dom G holds
( G . k <> {} & ex m being Nat st
( m in dom F & F . m = G . k ) ) ) )
rng F = (rng F1) \/ (rng <*(F . (n + 1))*>)
by A17, FINSEQ_1:31;
then union (rng F) =
(union (rng F1)) \/ (union (rng <*(F . (n + 1))*>))
by ZFMISC_1:78
.=
union ((rng G1) \/ (rng <*(F . (n + 1))*>))
by A6, ZFMISC_1:78
.=
union (rng G)
by FINSEQ_1:31
;
hence
ex
G being
Finite_Sep_Sequence of
S st
(
union (rng F) = union (rng G) & ( for
k being
Nat st
k in dom G holds
(
G . k <> {} & ex
m being
Nat st
(
m in dom F &
F . m = G . k ) ) ) )
by A50;
verum end; end; end;
hence
ex
G being
Finite_Sep_Sequence of
S st
(
union (rng F) = union (rng G) & ( for
k being
Nat st
k in dom G holds
(
G . k <> {} & ex
m being
Nat st
(
m in dom F &
F . m = G . k ) ) ) )
;
verum
end;
hence
ex
G being
Finite_Sep_Sequence of
S st
(
union (rng F) = union (rng G) & ( for
n being
Nat st
n in dom G holds
(
G . n <> {} & ex
m being
Nat st
(
m in dom F &
F . m = G . n ) ) ) )
;
verum
end;
A59:
len F = len F
;
A60:
S1[ 0 ]
for n being Nat holds S1[n]
from NAT_1:sch 2(A60, A1);
hence
ex G being Finite_Sep_Sequence of S st
( union (rng F) = union (rng G) & ( for n being Nat st n in dom G holds
( G . n <> {} & ex m being Nat st
( m in dom F & F . m = G . n ) ) ) )
by A59; verum