let a, b be Real; for f being PartFunc of REAL,REAL st [.a,b.[ c= dom f & f is_right_improper_integrable_on a,b holds
for E being Element of L-Field st E c= [.a,b.[ holds
f is E -measurable
let f be PartFunc of REAL,REAL; ( [.a,b.[ c= dom f & f is_right_improper_integrable_on a,b implies for E being Element of L-Field st E c= [.a,b.[ holds
f is E -measurable )
assume that
A1:
[.a,b.[ c= dom f
and
A2:
f is_right_improper_integrable_on a,b
; for E being Element of L-Field st E c= [.a,b.[ holds
f is E -measurable
per cases
( a < b or a >= b )
;
suppose A3:
a < b
;
for E being Element of L-Field st E c= [.a,b.[ holds
f is E -measurable reconsider A =
[.a,b.[ as
Element of
L-Field by MEASUR12:72, MEASUR12:75;
set dif =
b - a;
consider K being
SetSequence of
L-Field such that A4:
( ( for
n being
Nat holds
(
K . n = [.a,(b - ((b - a) / (n + 1))).] &
K . n c= [.a,b.[ &
K . n is non
empty closed_interval Subset of
REAL ) ) &
K is
non-descending &
K is
convergent &
Union K = A )
by A3, Th23;
rng K c= L-Field
;
then reconsider K1 =
K as
sequence of
L-Field by FUNCT_2:6;
for
n being
Nat holds
R_EAL f is
K1 . n -measurable
proof
let n be
Nat;
R_EAL f is K1 . n -measurable
not
K . n is
empty
by A4;
then
[.a,(b - ((b - a) / (n + 1))).] <> {}
by A4;
then A5:
a <= b - ((b - a) / (n + 1))
by XXREAL_1:29;
K . n c= [.a,b.[
by A4;
then
[.a,(b - ((b - a) / (n + 1))).] c= [.a,b.[
by A4;
then A6:
(
a <= b - ((b - a) / (n + 1)) &
b - ((b - a) / (n + 1)) < b )
by A5, XXREAL_1:54;
reconsider Kn =
K . n as non
empty closed_interval Subset of
REAL by A4;
Kn = [.a,(b - ((b - a) / (n + 1))).]
by A4;
then
Kn = ['a,(b - ((b - a) / (n + 1)))']
by XXREAL_1:29, INTEGRA5:def 3;
then A7:
(
f is_integrable_on Kn &
f || Kn is
bounded )
by A6, A2, INTEGR24:def 2;
Kn c= [.a,b.[
by A4;
then
Kn c= dom f
by A1;
hence
R_EAL f is
K1 . n -measurable
by A7, MESFUN14:49, MESFUNC6:def 1;
verum
end; then
f is
Union K1 -measurable
by Th21, MESFUNC6:def 1;
hence
for
E being
Element of
L-Field st
E c= [.a,b.[ holds
f is
E -measurable
by A4, MESFUNC6:16;
verum end; end;