let X be non empty set ; for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for E being Element of S
for n being Nat st E = dom f & f is nonnegative & f is E -measurable & Integral (M,f) = 0 holds
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0
let S be SigmaField of X; for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for E being Element of S
for n being Nat st E = dom f & f is nonnegative & f is E -measurable & Integral (M,f) = 0 holds
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0
let M be sigma_Measure of S; for f being PartFunc of X,ExtREAL
for E being Element of S
for n being Nat st E = dom f & f is nonnegative & f is E -measurable & Integral (M,f) = 0 holds
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0
let f be PartFunc of X,ExtREAL; for E being Element of S
for n being Nat st E = dom f & f is nonnegative & f is E -measurable & Integral (M,f) = 0 holds
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0
let E be Element of S; for n being Nat st E = dom f & f is nonnegative & f is E -measurable & Integral (M,f) = 0 holds
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0
let n be Nat; ( E = dom f & f is nonnegative & f is E -measurable & Integral (M,f) = 0 implies M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0 )
assume that
A1:
E = dom f
and
A2:
f is nonnegative
and
A3:
f is E -measurable
and
A4:
Integral (M,f) = 0
; M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) = 0
assume A5:
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) <> 0
; contradiction
E /\ (great_eq_dom (f,(1 / (n + 1)))) in S
by A1, A3, MESFUNC1:27;
then A6:
M . (E /\ (great_eq_dom (f,(1 / (n + 1))))) > 0
by A5, MEASURE1:def 2;
great_eq_dom (f,(1 / (n + 1))) c= E
by A1, MESFUNC1:def 14;
then A7:
M . (great_eq_dom (f,(1 / (n + 1)))) > 0
by A6, XBOOLE_1:28;
1 / (n + 1) > 0
by XREAL_1:139;
then
(1 / (n + 1)) * (M . (great_eq_dom (f,(1 / (n + 1))))) > 0
by A7;
hence
contradiction
by A3, A1, A2, A4, MESFUN13:16; verum