let X1, X2 be non empty set ; for S1 being SigmaField of X1
for S2 being SigmaField of X2
for M1 being sigma_Measure of S1
for E being Element of sigma (measurable_rectangles (S1,S2))
for V being Element of S2
for f being b4 -measurable PartFunc of [:X1,X2:],ExtREAL st M1 is sigma_finite & E = dom f holds
Integral1 (M1,|.f.|) is V -measurable
let S1 be SigmaField of X1; for S2 being SigmaField of X2
for M1 being sigma_Measure of S1
for E being Element of sigma (measurable_rectangles (S1,S2))
for V being Element of S2
for f being b3 -measurable PartFunc of [:X1,X2:],ExtREAL st M1 is sigma_finite & E = dom f holds
Integral1 (M1,|.f.|) is V -measurable
let S2 be SigmaField of X2; for M1 being sigma_Measure of S1
for E being Element of sigma (measurable_rectangles (S1,S2))
for V being Element of S2
for f being b2 -measurable PartFunc of [:X1,X2:],ExtREAL st M1 is sigma_finite & E = dom f holds
Integral1 (M1,|.f.|) is V -measurable
let M1 be sigma_Measure of S1; for E being Element of sigma (measurable_rectangles (S1,S2))
for V being Element of S2
for f being b1 -measurable PartFunc of [:X1,X2:],ExtREAL st M1 is sigma_finite & E = dom f holds
Integral1 (M1,|.f.|) is V -measurable
let E be Element of sigma (measurable_rectangles (S1,S2)); for V being Element of S2
for f being E -measurable PartFunc of [:X1,X2:],ExtREAL st M1 is sigma_finite & E = dom f holds
Integral1 (M1,|.f.|) is V -measurable
let V be Element of S2; for f being E -measurable PartFunc of [:X1,X2:],ExtREAL st M1 is sigma_finite & E = dom f holds
Integral1 (M1,|.f.|) is V -measurable
let f be E -measurable PartFunc of [:X1,X2:],ExtREAL; ( M1 is sigma_finite & E = dom f implies Integral1 (M1,|.f.|) is V -measurable )
assume that
A1:
M1 is sigma_finite
and
A2:
E = dom f
; Integral1 (M1,|.f.|) is V -measurable
A3:
E = dom |.f.|
by A2, MESFUNC1:def 10;
|.f.| is E -measurable
by A2, MESFUNC2:27;
hence
Integral1 (M1,|.f.|) is V -measurable
by A1, A3, MESFUN12:59; verum