let X1, X2 be non empty set ; for S1 being SigmaField of X1
for S2 being SigmaField of X2
for M2 being sigma_Measure of S2
for E being Element of sigma (measurable_rectangles (S1,S2))
for U being Element of S1
for f being b4 -measurable PartFunc of [:X1,X2:],ExtREAL st M2 is sigma_finite & E = dom f holds
Integral2 (M2,|.f.|) is U -measurable
let S1 be SigmaField of X1; for S2 being SigmaField of X2
for M2 being sigma_Measure of S2
for E being Element of sigma (measurable_rectangles (S1,S2))
for U being Element of S1
for f being b3 -measurable PartFunc of [:X1,X2:],ExtREAL st M2 is sigma_finite & E = dom f holds
Integral2 (M2,|.f.|) is U -measurable
let S2 be SigmaField of X2; for M2 being sigma_Measure of S2
for E being Element of sigma (measurable_rectangles (S1,S2))
for U being Element of S1
for f being b2 -measurable PartFunc of [:X1,X2:],ExtREAL st M2 is sigma_finite & E = dom f holds
Integral2 (M2,|.f.|) is U -measurable
let M2 be sigma_Measure of S2; for E being Element of sigma (measurable_rectangles (S1,S2))
for U being Element of S1
for f being b1 -measurable PartFunc of [:X1,X2:],ExtREAL st M2 is sigma_finite & E = dom f holds
Integral2 (M2,|.f.|) is U -measurable
let E be Element of sigma (measurable_rectangles (S1,S2)); for U being Element of S1
for f being E -measurable PartFunc of [:X1,X2:],ExtREAL st M2 is sigma_finite & E = dom f holds
Integral2 (M2,|.f.|) is U -measurable
let U be Element of S1; for f being E -measurable PartFunc of [:X1,X2:],ExtREAL st M2 is sigma_finite & E = dom f holds
Integral2 (M2,|.f.|) is U -measurable
let f be E -measurable PartFunc of [:X1,X2:],ExtREAL; ( M2 is sigma_finite & E = dom f implies Integral2 (M2,|.f.|) is U -measurable )
assume that
A1:
M2 is sigma_finite
and
A2:
E = dom f
; Integral2 (M2,|.f.|) is U -measurable
A3:
E = dom |.f.|
by A2, MESFUNC1:def 10;
|.f.| is E -measurable
by A2, MESFUNC2:27;
hence
Integral2 (M2,|.f.|) is U -measurable
by A1, A3, MESFUN12:60; verum