let C be non empty set ; for f being PartFunc of C,ExtREAL
for c being Real st c <= 0 holds
( max+ (c (#) f) = (- c) (#) (max- f) & max- (c (#) f) = (- c) (#) (max+ f) )
let f be PartFunc of C,ExtREAL; for c being Real st c <= 0 holds
( max+ (c (#) f) = (- c) (#) (max- f) & max- (c (#) f) = (- c) (#) (max+ f) )
let c be Real; ( c <= 0 implies ( max+ (c (#) f) = (- c) (#) (max- f) & max- (c (#) f) = (- c) (#) (max+ f) ) )
assume A1:
c <= 0
; ( max+ (c (#) f) = (- c) (#) (max- f) & max- (c (#) f) = (- c) (#) (max+ f) )
A2: dom (max+ (c (#) f)) =
dom (c (#) f)
by MESFUNC2:def 2
.=
dom f
by MESFUNC1:def 6
.=
dom (max- f)
by MESFUNC2:def 3
.=
dom ((- c) (#) (max- f))
by MESFUNC1:def 6
;
for x being Element of C st x in dom (max+ (c (#) f)) holds
(max+ (c (#) f)) . x = ((- c) (#) (max- f)) . x
hence
max+ (c (#) f) = (- c) (#) (max- f)
by A2, PARTFUN1:5; max- (c (#) f) = (- c) (#) (max+ f)
A7: dom (max- (c (#) f)) =
dom (c (#) f)
by MESFUNC2:def 3
.=
dom f
by MESFUNC1:def 6
.=
dom (max+ f)
by MESFUNC2:def 2
.=
dom ((- c) (#) (max+ f))
by MESFUNC1:def 6
;
for x being Element of C st x in dom (max- (c (#) f)) holds
(max- (c (#) f)) . x = ((- c) (#) (max+ f)) . x
proof
let x be
Element of
C;
( x in dom (max- (c (#) f)) implies (max- (c (#) f)) . x = ((- c) (#) (max+ f)) . x )
assume A8:
x in dom (max- (c (#) f))
;
(max- (c (#) f)) . x = ((- c) (#) (max+ f)) . x
then A9:
x in dom (c (#) f)
by MESFUNC2:def 3;
then
x in dom f
by MESFUNC1:def 6;
then A10:
x in dom (max+ f)
by MESFUNC2:def 2;
A11:
(max- (c (#) f)) . x =
max (
(- ((c (#) f) . x)),
0)
by A8, MESFUNC2:def 3
.=
max (
(- (c * (f . x))),
0)
by A9, MESFUNC1:def 6
;
A12:
((- c) (#) (max+ f)) . x =
(- c) * ((max+ f) . x)
by A7, A8, MESFUNC1:def 6
.=
(- c) * (max ((f . x),0))
by A10, MESFUNC2:def 2
.=
max (
((- c) * (f . x)),
((- c) * 0))
by A1, MESFUNC5:6
.=
max (
((- c) * (f . x)),
0)
;
- (c * (f . x)) = (- c) * (f . x)
hence
(max- (c (#) f)) . x = ((- c) (#) (max+ f)) . x
by A11, A12;
verum
end;
hence
max- (c (#) f) = (- c) (#) (max+ f)
by A7, PARTFUN1:5; verum