let X be Subset of REAL; for r3 being Real st r3 in Cl X holds
ex seq being Real_Sequence st
( rng seq c= X & seq is convergent & lim seq = r3 )
let r3 be Real; ( r3 in Cl X implies ex seq being Real_Sequence st
( rng seq c= X & seq is convergent & lim seq = r3 ) )
defpred S1[ object , object ] means ex n being Nat st
( $1 = n & $2 = the Element of X /\ ].(r3 - (1 / (n + 1))),(r3 + (1 / (n + 1))).[ );
assume A1:
r3 in Cl X
; ex seq being Real_Sequence st
( rng seq c= X & seq is convergent & lim seq = r3 )
A2:
now for x being object st x in NAT holds
ex u being object st
( u in REAL & S1[x,u] )let x be
object ;
( x in NAT implies ex u being object st
( u in REAL & S1[x,u] ) )assume
x in NAT
;
ex u being object st
( u in REAL & S1[x,u] )then reconsider n =
x as
Element of
NAT ;
set n1 =
n + 1;
set oi =
].(r3 - (1 / (n + 1))),(r3 + (1 / (n + 1))).[;
reconsider u = the
Element of
X /\ ].(r3 - (1 / (n + 1))),(r3 + (1 / (n + 1))).[ as
object ;
take u =
u;
( u in REAL & S1[x,u] )A3:
r3 < r3 + (1 / (n + 1))
by XREAL_1:29;
then
r3 - (1 / (n + 1)) < r3
by XREAL_1:19;
then
r3 in ].(r3 - (1 / (n + 1))),(r3 + (1 / (n + 1))).[
by A3;
then
not
X /\ ].(r3 - (1 / (n + 1))),(r3 + (1 / (n + 1))).[ is
empty
by A1, Th63;
then
u in X /\ ].(r3 - (1 / (n + 1))),(r3 + (1 / (n + 1))).[
;
hence
u in REAL
;
S1[x,u]thus
S1[
x,
u]
;
verum end;
consider seq being Function such that
A4:
( dom seq = NAT & rng seq c= REAL )
and
A5:
for x being object st x in NAT holds
S1[x,seq . x]
from FUNCT_1:sch 6(A2);
reconsider seq = seq as Real_Sequence by A4, FUNCT_2:def 1, RELSET_1:4;
take
seq
; ( rng seq c= X & seq is convergent & lim seq = r3 )
thus
rng seq c= X
( seq is convergent & lim seq = r3 )
A10:
now for p being Real st 0 < p holds
ex n being Nat st
for m being Nat st n <= m holds
|.((seq . m) - r3).| < plet p be
Real;
( 0 < p implies ex n being Nat st
for m being Nat st n <= m holds
|.((seq . m) - r3).| < p )set cp =
[/(1 / p)\];
A11:
1
/ p <= [/(1 / p)\]
by INT_1:def 7;
assume A12:
0 < p
;
ex n being Nat st
for m being Nat st n <= m holds
|.((seq . m) - r3).| < pthen A13:
0 < [/(1 / p)\]
by INT_1:def 7;
then reconsider cp =
[/(1 / p)\] as
Element of
NAT by INT_1:3;
reconsider n =
cp as
Nat ;
take n =
n;
for m being Nat st n <= m holds
|.((seq . m) - r3).| < p
n < n + 1
by NAT_1:13;
then A14:
1
/ (n + 1) < 1
/ n
by A13, XREAL_1:88;
1
/ (1 / p) >= 1
/ cp
by A12, A11, XREAL_1:85;
then A15:
1
/ (n + 1) < p
by A14, XXREAL_0:2;
let m be
Nat;
( n <= m implies |.((seq . m) - r3).| < p )assume
n <= m
;
|.((seq . m) - r3).| < pthen A16:
n + 1
<= m + 1
by XREAL_1:6;
set m1 =
m + 1;
1
/ (m + 1) <= 1
/ (n + 1)
by A16, XREAL_1:85;
then A17:
1
/ (m + 1) < p
by A15, XXREAL_0:2;
set oi =
].(r3 - (1 / (m + 1))),(r3 + (1 / (m + 1))).[;
A18:
r3 < r3 + (1 / (m + 1))
by XREAL_1:29;
then
r3 - (1 / (m + 1)) < r3
by XREAL_1:19;
then
r3 in ].(r3 - (1 / (m + 1))),(r3 + (1 / (m + 1))).[
by A18;
then A19:
not
X /\ ].(r3 - (1 / (m + 1))),(r3 + (1 / (m + 1))).[ is
empty
by A1, Th63;
m in NAT
by ORDINAL1:def 12;
then
ex
m9 being
Nat st
(
m9 = m &
seq . m = the
Element of
X /\ ].(r3 - (1 / (m9 + 1))),(r3 + (1 / (m9 + 1))).[ )
by A5;
then
seq . m in ].(r3 - (1 / (m + 1))),(r3 + (1 / (m + 1))).[
by A19, XBOOLE_0:def 4;
then consider s being
Real such that A20:
seq . m = s
and A21:
(
r3 - (1 / (m + 1)) < s &
s < r3 + (1 / (m + 1)) )
;
(
- (1 / (m + 1)) < s - r3 &
s - r3 < 1
/ (m + 1) )
by A21, XREAL_1:19, XREAL_1:20;
then
|.(s - r3).| < 1
/ (m + 1)
by SEQ_2:1;
hence
|.((seq . m) - r3).| < p
by A20, A17, XXREAL_0:2;
verum end;
hence
seq is convergent
; lim seq = r3
hence
lim seq = r3
by A10, SEQ_2:def 7; verum