thus ( X is with_min implies ( X is bounded_below & lower_bound X in X ) ) :: thesis: ( X is bounded_below & lower_bound X in X implies X is with_min )
proof end;
assume A4: ( X is bounded_below & lower_bound X in X ) ; :: thesis: X is with_min
then reconsider X = X as non empty real-membered bounded_below set ;
lower_bound X in X by A4;
hence X is with_min ; :: thesis: verum