let A be non empty Interval; ( A is closed_interval implies A = [.(inf A),(sup A).] )
assume
A is closed_interval
; A = [.(inf A),(sup A).]
then consider a, b being Real such that
A1:
A = [.a,b.]
by MEASURE5:def 3;
A2:
a <= b
by A1, XXREAL_1:29;
reconsider b = b as R_eal by XXREAL_0:def 1;
sup A = b
by A1, A2, XXREAL_2:29;
hence
A = [.(inf A),(sup A).]
by A1, A2, XXREAL_2:25; verum