let X, Y be non empty set ; for S being SigmaField of X
for T being Function of X,Y
for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for g being PartFunc of Y,ExtREAL st T is bijective & g = f * (T ") & f is_simple_func_in S & f is nonnegative holds
integral ((CopyMeasure (T,M)),g) = integral (M,f)
let S be SigmaField of X; for T being Function of X,Y
for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for g being PartFunc of Y,ExtREAL st T is bijective & g = f * (T ") & f is_simple_func_in S & f is nonnegative holds
integral ((CopyMeasure (T,M)),g) = integral (M,f)
let T be Function of X,Y; for M being sigma_Measure of S
for f being PartFunc of X,ExtREAL
for g being PartFunc of Y,ExtREAL st T is bijective & g = f * (T ") & f is_simple_func_in S & f is nonnegative holds
integral ((CopyMeasure (T,M)),g) = integral (M,f)
let M be sigma_Measure of S; for f being PartFunc of X,ExtREAL
for g being PartFunc of Y,ExtREAL st T is bijective & g = f * (T ") & f is_simple_func_in S & f is nonnegative holds
integral ((CopyMeasure (T,M)),g) = integral (M,f)
let f be PartFunc of X,ExtREAL; for g being PartFunc of Y,ExtREAL st T is bijective & g = f * (T ") & f is_simple_func_in S & f is nonnegative holds
integral ((CopyMeasure (T,M)),g) = integral (M,f)
let g be PartFunc of Y,ExtREAL; ( T is bijective & g = f * (T ") & f is_simple_func_in S & f is nonnegative implies integral ((CopyMeasure (T,M)),g) = integral (M,f) )
assume that
A1:
T is bijective
and
A2:
g = f * (T ")
and
A3:
f is_simple_func_in S
and
A4:
f is nonnegative
; integral ((CopyMeasure (T,M)),g) = integral (M,f)
A5:
( g is_simple_func_in CopyField (T,S) & g is nonnegative )
by A1, A2, A3, A4, Th23, Th22;
consider F being Finite_Sep_Sequence of S, a, x being FinSequence of ExtREAL such that
A6:
( F,a are_Re-presentation_of f & a . 1 = 0. & ( for n being Nat st 2 <= n & n in dom a holds
( 0. < a . n & a . n < +infty ) ) & dom x = dom F & ( for n being Nat st n in dom x holds
x . n = (a . n) * ((M * F) . n) ) & integral (M,f) = Sum x )
by A3, A4, MESFUNC3:def 2;
consider G being Finite_Sep_Sequence of CopyField (T,S) such that
A7:
( G = ((.: T) | S) * F & G,a are_Re-presentation_of g )
by A1, A2, A6, Th24;
set L = CopyMeasure (T,M);
set H = (.: T) | S;
for n being Nat st n in dom x holds
x . n = (a . n) * (((CopyMeasure (T,M)) * G) . n)
proof
let n be
Nat;
( n in dom x implies x . n = (a . n) * (((CopyMeasure (T,M)) * G) . n) )
assume A8:
n in dom x
;
x . n = (a . n) * (((CopyMeasure (T,M)) * G) . n)
then A9:
x . n = (a . n) * ((M * F) . n)
by A6;
A10:
(M * F) . n = M . (F . n)
by A8, A6, FUNCT_1:13;
A11:
((CopyMeasure (T,M)) * G) . n = (CopyMeasure (T,M)) . (G . n)
by A8, A6, A7, FUNCT_1:13;
reconsider Gn =
G . n as
Element of
CopyField (
T,
S) ;
consider Kn being
Element of
S such that A12:
(
Gn = T .: Kn &
(CopyMeasure (T,M)) . Gn = M . Kn )
by A1, Def4;
A13:
Gn = (.: T) . Kn
by A12, A1, Th1;
A14:
.: T is
one-to-one
by A1;
A15:
dom (.: T) = bool X
by FUNCT_2:def 1;
G . n = ((.: T) | S) . (F . n)
by A7, A8, A6, FUNCT_1:13;
then
G . n = (.: T) . (F . n)
by FUNCT_1:49;
hence
x . n = (a . n) * (((CopyMeasure (T,M)) * G) . n)
by A9, A10, A11, A12, A13, A14, A15;
verum
end;
hence
integral ((CopyMeasure (T,M)),g) = integral (M,f)
by A5, A6, A7, MESFUNC3:def 2; verum