let f, g be sequence of ExtREAL; for i, j being Nat st f is nonnegative & i >= j & ( for n being Nat st n <> i & n <> j holds
f . n = g . n ) & f . i = g . j & f . j = g . i holds
(Ser f) . i = (Ser g) . i
let i, j be Nat; ( f is nonnegative & i >= j & ( for n being Nat st n <> i & n <> j holds
f . n = g . n ) & f . i = g . j & f . j = g . i implies (Ser f) . i = (Ser g) . i )
assume that
A1:
f is nonnegative
and
A2:
i >= j
and
A3:
for n being Nat st n <> i & n <> j holds
f . n = g . n
and
A4:
f . i = g . j
and
A5:
f . j = g . i
; (Ser f) . i = (Ser g) . i
A6:
for k being Element of NAT holds 0 <= g . k
then A7:
g is nonnegative
by SUPINF_2:39;
per cases
( j = 0 or j <> 0 )
;
suppose A8:
j = 0
;
(Ser f) . i = (Ser g) . idefpred S1[
Nat]
means ( $1
< i implies
((Ser f) . $1) + (f . i) = ((Ser g) . $1) + (g . i) );
then A9:
S1[
0 ]
;
A10:
for
m being
Nat st
S1[
m] holds
S1[
m + 1]
proof
let m be
Nat;
( S1[m] implies S1[m + 1] )
assume A11:
S1[
m]
;
S1[m + 1]
assume A12:
m + 1
< i
;
((Ser f) . (m + 1)) + (f . i) = ((Ser g) . (m + 1)) + (g . i)
A13:
(
0 <= f . m &
0 <= f . (m + 1) &
0 <= f . i )
by A1, SUPINF_2:51;
then A14:
0 <= (Ser f) . m
by A1, MEASURE7:2;
A15:
(
0 <= g . m &
0 <= g . (m + 1) &
0 <= g . i )
by A6, SUPINF_2:39, SUPINF_2:51;
then A16:
0 <= (Ser g) . m
by A7, MEASURE7:2;
A17:
f . (m + 1) = g . (m + 1)
by A3, A8, A12;
then A18:
(
(Ser f) . (m + 1) = (g . (m + 1)) + ((Ser f) . m) &
(Ser g) . (m + 1) = (f . (m + 1)) + ((Ser g) . m) )
by SUPINF_2:def 11;
then
((Ser f) . (m + 1)) + (f . i) = (g . (m + 1)) + (((Ser f) . m) + (f . i))
by A13, A14, A15, XXREAL_3:44;
hence
((Ser f) . (m + 1)) + (f . i) = ((Ser g) . (m + 1)) + (g . i)
by A11, A12, A15, A16, A17, A18, XXREAL_3:44, NAT_1:13;
verum
end; A19:
for
m being
Nat holds
S1[
m]
from NAT_1:sch 2(A9, A10);
end; suppose A22:
j <> 0
;
(Ser f) . i = (Ser g) . ithen reconsider m =
j - 1 as
Nat by NAT_1:20;
A23:
j = m + 1
;
then A24:
m < j
by NAT_1:13;
for
n being
Nat st
n < j holds
f . n = g . n
by A2, A3;
then A25:
(Ser f) . m = (Ser g) . m
by A24, Th48;
per cases
( j = i or j <> i )
;
suppose
j <> i
;
(Ser f) . i = (Ser g) . ithen A27:
j < i
by A2, XXREAL_0:1;
defpred S1[
Nat]
means (
j <= $1 & $1
< i implies
((Ser f) . $1) + (f . i) = ((Ser g) . $1) + (g . i) );
A28:
S1[
0 ]
by A22;
A29:
for
k being
Nat st
S1[
k] holds
S1[
k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume A30:
S1[
k]
;
S1[k + 1]
assume A31:
(
j <= k + 1 &
k + 1
< i )
;
((Ser f) . (k + 1)) + (f . i) = ((Ser g) . (k + 1)) + (g . i)
per cases
( j = k + 1 or j <> k + 1 )
;
suppose A32:
j = k + 1
;
((Ser f) . (k + 1)) + (f . i) = ((Ser g) . (k + 1)) + (g . i)A33:
(
0 <= f . i &
0 <= g . i &
0 <= g . k )
by A1, A6, SUPINF_2:39, SUPINF_2:51;
then A34:
0 <= (Ser g) . k
by A7, MEASURE7:2;
((Ser f) . (k + 1)) + (f . i) = (((Ser f) . k) + (f . (k + 1))) + (f . i)
by SUPINF_2:def 11;
then
((Ser f) . (k + 1)) + (f . i) = (((Ser g) . k) + (f . i)) + (g . i)
by A5, A25, A32, A33, A34, XXREAL_3:44;
hence
((Ser f) . (k + 1)) + (f . i) = ((Ser g) . (k + 1)) + (g . i)
by A4, A32, SUPINF_2:def 11;
verum end; suppose
j <> k + 1
;
((Ser f) . (k + 1)) + (f . i) = ((Ser g) . (k + 1)) + (g . i)then A35:
j < k + 1
by A31, XXREAL_0:1;
A36:
(
0 <= f . (k + 1) &
0 <= f . i &
0 <= f . k )
by A1, SUPINF_2:51;
then A37:
0 <= (Ser f) . k
by A1, MEASURE7:2;
A38:
(
0 <= g . (k + 1) &
0 <= g . i &
0 <= g . k )
by A6, SUPINF_2:39, SUPINF_2:51;
then A39:
0 <= (Ser g) . k
by A7, MEASURE7:2;
(Ser f) . (k + 1) = (f . (k + 1)) + ((Ser f) . k)
by SUPINF_2:def 11;
then
((Ser f) . (k + 1)) + (f . i) = (f . (k + 1)) + (((Ser f) . k) + (f . i))
by A36, A37, XXREAL_3:44;
then
((Ser f) . (k + 1)) + (f . i) = (g . (k + 1)) + (((Ser g) . k) + (g . i))
by A3, A30, A31, A35, NAT_1:13;
then
((Ser f) . (k + 1)) + (f . i) = ((g . (k + 1)) + ((Ser g) . k)) + (g . i)
by A38, A39, XXREAL_3:44;
hence
((Ser f) . (k + 1)) + (f . i) = ((Ser g) . (k + 1)) + (g . i)
by SUPINF_2:def 11;
verum end; end;
end; A40:
for
k being
Nat holds
S1[
k]
from NAT_1:sch 2(A28, A29);
reconsider k =
i - 1 as
Nat by A27, NAT_1:20;
A41:
i = k + 1
;
then
(
j <= k &
k < i )
by A27, NAT_1:13;
then
((Ser f) . k) + (f . i) = ((Ser g) . k) + (g . i)
by A40;
then
(Ser f) . i = ((Ser g) . k) + (g . i)
by A41, SUPINF_2:def 11;
hence
(Ser f) . i = (Ser g) . i
by A41, SUPINF_2:def 11;
verum end; end; end; end;