let X be non empty set ; for f, g being PartFunc of X,ExtREAL holds
( - (f + g) = (- f) + (- g) & - (f - g) = (- f) + g & - (f - g) = g - f & - ((- f) + g) = f - g & - ((- f) + g) = f + (- g) )
let f, g be PartFunc of X,ExtREAL; ( - (f + g) = (- f) + (- g) & - (f - g) = (- f) + g & - (f - g) = g - f & - ((- f) + g) = f - g & - ((- f) + g) = f + (- g) )
A1:
( f " {-infty} = (- f) " {+infty} & f " {+infty} = (- f) " {-infty} & g " {-infty} = (- g) " {+infty} & g " {+infty} = (- g) " {-infty} )
by LEM10;
A2:
( dom f = dom (- f) & dom g = dom (- g) )
by MESFUNC1:def 7;
A3:
( dom (- (f + g)) = dom (f + g) & dom (- f) = dom f & dom (- g) = dom g & dom (- (f - g)) = dom (f - g) )
by MESFUNC1:def 7;
then A4:
dom (- (f + g)) = ((dom f) /\ (dom g)) \ (((f " {-infty}) /\ (g " {+infty})) \/ ((f " {+infty}) /\ (g " {-infty})))
by MESFUNC1:def 3;
then A5:
dom (- (f + g)) = dom ((- f) + (- g))
by A1, A2, MESFUNC1:def 3;
A6:
dom (- (f - g)) = ((dom f) /\ (dom g)) \ (((f " {+infty}) /\ (g " {+infty})) \/ ((f " {-infty}) /\ (g " {-infty})))
by A3, MESFUNC1:def 4;
then A7:
dom (- (f - g)) = dom ((- f) + g)
by A1, A2, MESFUNC1:def 3;
then C1:
dom (- ((- f) + g)) = dom (- (f - g))
by MESFUNC1:def 7;
then A10:
dom (- ((- f) + g)) = dom (f - g)
by MESFUNC1:def 7;
then
dom (- ((- f) + g)) = ((dom f) /\ (dom g)) \ (((f " {+infty}) /\ (g " {+infty})) \/ ((f " {-infty}) /\ (g " {-infty})))
by MESFUNC1:def 4;
then A12:
dom (- ((- f) + g)) = dom (f + (- g))
by A1, A2, MESFUNC1:def 3;
A8:
dom (- (f - g)) = dom (g - f)
by A6, MESFUNC1:def 4;
A9:
dom (- ((- f) + g)) = dom ((- f) + g)
by MESFUNC1:def 7;
B3:
( dom (- (f + g)) c= dom f & dom (- (f + g)) c= dom g )
by A4, XBOOLE_1:18, XBOOLE_1:36;
B4:
( dom (- (f - g)) c= dom f & dom (- (f - g)) c= dom g )
by A6, XBOOLE_1:18, XBOOLE_1:36;
B5:
( dom (- ((- f) + g)) c= dom (- f) & dom (- ((- f) + g)) c= dom g )
by C1, A3, A6, XBOOLE_1:18, XBOOLE_1:36;
now for x being Element of X st x in dom (- (f + g)) holds
(- (f + g)) . x = ((- f) + (- g)) . xlet x be
Element of
X;
( x in dom (- (f + g)) implies (- (f + g)) . x = ((- f) + (- g)) . x )assume B2:
x in dom (- (f + g))
;
(- (f + g)) . x = ((- f) + (- g)) . xthen (- (f + g)) . x =
- ((f + g) . x)
by MESFUNC1:def 7
.=
- ((f . x) + (g . x))
by A3, B2, MESFUNC1:def 3
.=
(- (f . x)) + (- (g . x))
by XXREAL_3:9
.=
((- f) . x) + (- (g . x))
by A2, B2, B3, MESFUNC1:def 7
.=
((- f) . x) + ((- g) . x)
by A2, B2, B3, MESFUNC1:def 7
;
hence
(- (f + g)) . x = ((- f) + (- g)) . x
by B2, A5, MESFUNC1:def 3;
verum end;
hence
- (f + g) = (- f) + (- g)
by A5, PARTFUN1:5; ( - (f - g) = (- f) + g & - (f - g) = g - f & - ((- f) + g) = f - g & - ((- f) + g) = f + (- g) )
hence
- (f - g) = (- f) + g
by A7, PARTFUN1:5; ( - (f - g) = g - f & - ((- f) + g) = f - g & - ((- f) + g) = f + (- g) )
hence
- (f - g) = g - f
by A8, PARTFUN1:5; ( - ((- f) + g) = f - g & - ((- f) + g) = f + (- g) )
hence
- ((- f) + g) = f - g
by A10, PARTFUN1:5; - ((- f) + g) = f + (- g)
hence
- ((- f) + g) = f + (- g)
by A12, PARTFUN1:5; verum