let X, Y, Z be set ; ( ( X c= [:X,Y,Z:] or X c= [:Y,Z,X:] or X c= [:Z,X,Y:] ) implies X = {} )
assume that
A1:
( X c= [:X,Y,Z:] or X c= [:Y,Z,X:] or X c= [:Z,X,Y:] )
and
A2:
X <> {}
; contradiction
( [:X,Y,Z:] <> {} or [:Y,Z,X:] <> {} or [:Z,X,Y:] <> {} )
by A1, A2;
then reconsider X = X, Y = Y, Z = Z as non empty set by Th21;