let A1, A2 be invertible Matrix of n,F_Real; ( A1 * (i,i) = - (1. F_Real) & ( for k, m being Nat st [k,m] in Indices A1 holds
( ( k = m & k <> i implies A1 * (k,k) = 1. F_Real ) & ( k <> m implies A1 * (k,m) = 0. F_Real ) ) ) & A2 * (i,i) = - (1. F_Real) & ( for k, m being Nat st [k,m] in Indices A2 holds
( ( k = m & k <> i implies A2 * (k,k) = 1. F_Real ) & ( k <> m implies A2 * (k,m) = 0. F_Real ) ) ) implies A1 = A2 )
assume that
A4:
A1 * (i,i) = - (1. F_Real)
and
A5:
for k, m being Nat st [k,m] in Indices A1 holds
( ( k = m & k <> i implies A1 * (k,k) = 1. F_Real ) & ( k <> m implies A1 * (k,m) = 0. F_Real ) )
and
A6:
A2 * (i,i) = - (1. F_Real)
and
A7:
for k, m being Nat st [k,m] in Indices A2 holds
( ( k = m & k <> i implies A2 * (k,k) = 1. F_Real ) & ( k <> m implies A2 * (k,m) = 0. F_Real ) )
; A1 = A2
for k, m being Nat st [k,m] in Indices A1 holds
A1 * (k,m) = A2 * (k,m)
proof
let k,
m be
Nat;
( [k,m] in Indices A1 implies A1 * (k,m) = A2 * (k,m) )
assume A8:
[k,m] in Indices A1
;
A1 * (k,m) = A2 * (k,m)
then A9:
[k,m] in Indices A2
by MATRIX_0:26;
per cases
( k <> m or ( k = m & k <> i ) or ( k = m & k = i ) )
;
suppose
(
k = m &
k = i )
;
A1 * (k,m) = A2 * (k,m)hence
A1 * (
k,
m)
= A2 * (
k,
m)
by A4, A6;
verum end; end;
end;
hence
A1 = A2
by MATRIX_0:27; verum