let r1, r2 be Real; for k being Nat
for seq1 being Real_Sequence ex seq being Real_Sequence st
( seq . 0 = r1 & ( for n being Nat holds
( ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n > k implies seq . n = r2 ) ) ) )
let k be Nat; for seq1 being Real_Sequence ex seq being Real_Sequence st
( seq . 0 = r1 & ( for n being Nat holds
( ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n > k implies seq . n = r2 ) ) ) )
let seq1 be Real_Sequence; ex seq being Real_Sequence st
( seq . 0 = r1 & ( for n being Nat holds
( ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n > k implies seq . n = r2 ) ) ) )
ex seq being Real_Sequence st
for n being Nat holds
( ( n = 0 implies seq . n = r1 ) & ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n <> 0 & n > k implies seq . n = r2 ) )
proof
defpred S1[
object ,
object ]
means ex
n being
Nat st
(
n = $1 & (
n = 0 implies $2
= r1 ) & (
n <> 0 &
n <= k implies $2
= seq1 . n ) & (
n <> 0 &
n > k implies $2
= r2 ) );
A1:
for
x being
object st
x in NAT holds
ex
y being
object st
S1[
x,
y]
proof
let x be
object ;
( x in NAT implies ex y being object st S1[x,y] )
assume
x in NAT
;
ex y being object st S1[x,y]
then reconsider n =
x as
Nat ;
now ( ( n = 0 & S1[x,r1] ) or ( n <> 0 & n <= k & S1[x,seq1 . n] ) or ( n <> 0 & not n <= k & S1[x,r2] ) )end;
hence
ex
y being
object st
S1[
x,
y]
;
verum
end;
consider f1 being
Function such that A2:
(
dom f1 = NAT & ( for
x being
object st
x in NAT holds
S1[
x,
f1 . x] ) )
from CLASSES1:sch 1(A1);
then reconsider f1 =
f1 as
Real_Sequence by A2, SEQ_1:1;
take seq =
f1;
for n being Nat holds
( ( n = 0 implies seq . n = r1 ) & ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n <> 0 & n > k implies seq . n = r2 ) )
let n be
Nat;
( ( n = 0 implies seq . n = r1 ) & ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n <> 0 & n > k implies seq . n = r2 ) )
reconsider n =
n as
Element of
NAT by ORDINAL1:def 12;
ex
k1 being
Nat st
(
k1 = n & (
k1 = 0 implies
seq . n = r1 ) & (
k1 <> 0 &
k1 <= k implies
seq . n = seq1 . k1 ) & (
k1 <> 0 &
k1 > k implies
seq . n = r2 ) )
by A2;
hence
( (
n = 0 implies
seq . n = r1 ) & (
n <> 0 &
n <= k implies
seq . n = seq1 . n ) & (
n <> 0 &
n > k implies
seq . n = r2 ) )
;
verum
end;
then consider seq being Real_Sequence such that
A3:
for n being Nat holds
( ( n = 0 implies seq . n = r1 ) & ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n <> 0 & n > k implies seq . n = r2 ) )
;
take
seq
; ( seq . 0 = r1 & ( for n being Nat holds
( ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n > k implies seq . n = r2 ) ) ) )
thus
( seq . 0 = r1 & ( for n being Nat holds
( ( n <> 0 & n <= k implies seq . n = seq1 . n ) & ( n > k implies seq . n = r2 ) ) ) )
by A3; verum