let n be Nat; for A, B being Matrix of n,REAL st A is invertible & B is invertible holds
( A * B is invertible & Inv (A * B) = (Inv B) * (Inv A) )
let A, B be Matrix of n,REAL; ( A is invertible & B is invertible implies ( A * B is invertible & Inv (A * B) = (Inv B) * (Inv A) ) )
assume that
A1:
A is invertible
and
A2:
B is invertible
; ( A * B is invertible & Inv (A * B) = (Inv B) * (Inv A) )
A3: ((Inv B) * (Inv A)) * (A * B) =
(((Inv B) * (Inv A)) * A) * B
by Th28
.=
((Inv B) * ((Inv A) * A)) * B
by Th28
.=
((Inv B) * (1_Rmatrix n)) * B
by A1, Def6
.=
(Inv B) * B
by Th71
.=
1_Rmatrix n
by A2, Def6
;
A4: (A * B) * ((Inv B) * (Inv A)) =
A * (B * ((Inv B) * (Inv A)))
by Th28
.=
A * ((B * (Inv B)) * (Inv A))
by Th28
.=
A * ((1_Rmatrix n) * (Inv A))
by A2, Def6
.=
(A * (1_Rmatrix n)) * (Inv A)
by Th28
.=
A * (Inv A)
by Th71
.=
1_Rmatrix n
by A1, Def6
;
hence
A * B is invertible
by A3; Inv (A * B) = (Inv B) * (Inv A)
hence
Inv (A * B) = (Inv B) * (Inv A)
by A3, A4, Def6; verum