let n be Nat; for K being Field
for M1, M2 being Matrix of n,K st M1 is_congruent_Matrix_of M2 & n > 0 holds
M1 @ is_congruent_Matrix_of M2 @
let K be Field; for M1, M2 being Matrix of n,K st M1 is_congruent_Matrix_of M2 & n > 0 holds
M1 @ is_congruent_Matrix_of M2 @
let M1, M2 be Matrix of n,K; ( M1 is_congruent_Matrix_of M2 & n > 0 implies M1 @ is_congruent_Matrix_of M2 @ )
assume that
A1:
M1 is_congruent_Matrix_of M2
and
A2:
n > 0
; M1 @ is_congruent_Matrix_of M2 @
consider M4 being Matrix of n,K such that
A3:
M4 is invertible
and
A4:
M1 = ((M4 @) * M2) * M4
by A1;
A5:
width (M4 @) = n
by MATRIX_0:24;
A6:
( width (M2 * M4) = n & len (M2 * M4) = n )
by MATRIX_0:24;
A7:
len M2 = n
by MATRIX_0:24;
A8:
width M2 = n
by MATRIX_0:24;
take
M4
; MATRIX_8:def 6 ( M4 is invertible & M1 @ = ((M4 @) * (M2 @)) * M4 )
A9:
len M4 = n
by MATRIX_0:24;
A10:
width M4 = n
by MATRIX_0:24;
then ((M4 @) * (M2 @)) * M4 =
((M4 @) * (M2 @)) * ((M4 @) @)
by A2, A9, MATRIX_0:57
.=
((M2 * M4) @) * ((M4 @) @)
by A2, A10, A9, A8, MATRIX_3:22
.=
((M4 @) * (M2 * M4)) @
by A2, A5, A6, MATRIX_3:22
.=
M1 @
by A4, A9, A8, A7, A5, MATRIX_3:33
;
hence
( M4 is invertible & M1 @ = ((M4 @) * (M2 @)) * M4 )
by A3; verum