let n be Nat; for K being Field
for M1 being Matrix of n,K st n > 0 & M1 is Nilpotent holds
not M1 is invertible
let K be Field; for M1 being Matrix of n,K st n > 0 & M1 is Nilpotent holds
not M1 is invertible
let M1 be Matrix of n,K; ( n > 0 & M1 is Nilpotent implies not M1 is invertible )
assume that
A1:
n > 0
and
A2:
M1 is Nilpotent
; not M1 is invertible
A3:
( len M1 = n & width M1 = n )
by MATRIX_0:24;
assume
M1 is invertible
; contradiction
then consider M2 being Matrix of n,K such that
A4:
M1 is_reverse_of M2
by MATRIX_6:def 3;
A5:
width M2 = n
by MATRIX_0:24;
A6:
len M2 = n
by MATRIX_0:24;
M1 =
M1 * (1. (K,n))
by MATRIX_3:19
.=
M1 * (M1 * M2)
by A4, MATRIX_6:def 2
.=
(M1 * M1) * M2
by A3, A6, MATRIX_3:33
.=
(0. (K,n)) * M2
by A2
.=
0. (K,n,n)
by A6, A5, MATRIX_6:1
;
then A7:
M1 * M2 = 0. (K,n)
by A6, A5, MATRIX_6:1;
M1 * M2 = 1. (K,n)
by A4, MATRIX_6:def 2;
hence
contradiction
by A1, A7, Th28; verum