let n be Nat; for K being Field st n > 0 holds
0. (K,n) <> 1. (K,n)
let K be Field; ( n > 0 implies 0. (K,n) <> 1. (K,n) )
A1:
Indices (1. (K,n)) = [:(Seg n),(Seg n):]
by MATRIX_0:24;
assume
n > 0
; 0. (K,n) <> 1. (K,n)
then
n >= 0 + 1
by INT_1:7;
then
1 in Seg n
;
then A2:
[1,1] in [:(Seg n),(Seg n):]
by ZFMISC_1:87;
assume A3:
0. (K,n) = 1. (K,n)
; contradiction
Indices (0. (K,n)) = Indices (1. (K,n))
by MATRIX_0:26;
then
(0. (K,n)) * (1,1) = 0. K
by A2, A1, MATRIX_1:1;
then
0. K = 1. K
by A2, A3, A1, MATRIX_1:def 3;
hence
contradiction
; verum