let n be Nat; for K being Ring
for M1, M2 being Matrix of n,K st M1 is invertible & M2 is invertible holds
( M1 * M2 is invertible & (M1 * M2) ~ = (M2 ~) * (M1 ~) )
let K be Ring; for M1, M2 being Matrix of n,K st M1 is invertible & M2 is invertible holds
( M1 * M2 is invertible & (M1 * M2) ~ = (M2 ~) * (M1 ~) )
let M1, M2 be Matrix of n,K; ( M1 is invertible & M2 is invertible implies ( M1 * M2 is invertible & (M1 * M2) ~ = (M2 ~) * (M1 ~) ) )
assume that
A1:
M1 is invertible
and
A2:
M2 is invertible
; ( M1 * M2 is invertible & (M1 * M2) ~ = (M2 ~) * (M1 ~) )
A3:
M1 ~ is_reverse_of M1
by A1, Def4;
A4:
M2 ~ is_reverse_of M2
by A2, Def4;
A5:
len M1 = n
by MATRIX_0:24;
A6:
width (M1 ~) = n
by MATRIX_0:24;
A7:
( width M1 = n & len M2 = n )
by MATRIX_0:24;
A8:
width M2 = n
by MATRIX_0:24;
A9:
len (M2 ~) = n
by MATRIX_0:24;
A10:
( width (M2 ~) = n & len (M1 ~) = n )
by MATRIX_0:24;
width ((M2 ~) * (M1 ~)) = n
by MATRIX_0:24;
then A11: ((M2 ~) * (M1 ~)) * (M1 * M2) =
(((M2 ~) * (M1 ~)) * M1) * M2
by A7, A5, MATRIX_3:33
.=
((M2 ~) * ((M1 ~) * M1)) * M2
by A5, A6, A10, MATRIX_3:33
.=
((M2 ~) * (1. (K,n))) * M2
by A3
.=
(M2 ~) * M2
by MATRIX_3:19
.=
1. (K,n)
by A4
;
width (M1 * M2) = n
by MATRIX_0:24;
then (M1 * M2) * ((M2 ~) * (M1 ~)) =
((M1 * M2) * (M2 ~)) * (M1 ~)
by A9, A10, MATRIX_3:33
.=
(M1 * (M2 * (M2 ~))) * (M1 ~)
by A7, A8, A9, MATRIX_3:33
.=
(M1 * (1. (K,n))) * (M1 ~)
by A4
.=
M1 * (M1 ~)
by MATRIX_3:19
.=
1. (K,n)
by A3
;
then A12:
(M2 ~) * (M1 ~) is_reverse_of M1 * M2
by A11;
then
M1 * M2 is invertible
;
hence
( M1 * M2 is invertible & (M1 * M2) ~ = (M2 ~) * (M1 ~) )
by A12, Def4; verum