let n be Nat; for K being Ring
for M1 being Matrix of n,K holds
( ( M1 is invertible & (M1 @) * M1 = 1. (K,n) ) iff M1 is Orthogonal )
let K be Ring; for M1 being Matrix of n,K holds
( ( M1 is invertible & (M1 @) * M1 = 1. (K,n) ) iff M1 is Orthogonal )
let M1 be Matrix of n,K; ( ( M1 is invertible & (M1 @) * M1 = 1. (K,n) ) iff M1 is Orthogonal )
A1:
( width M1 = n & len M1 = n )
by MATRIX_0:24;
A2:
width (M1 @) = n
by MATRIX_0:24;
A3:
len (M1 ~) = n
by MATRIX_0:24;
A4:
width (M1 ~) = n
by MATRIX_0:24;
thus
( M1 is invertible & (M1 @) * M1 = 1. (K,n) implies M1 is Orthogonal )
( M1 is Orthogonal implies ( M1 is invertible & (M1 @) * M1 = 1. (K,n) ) )proof
assume that A5:
M1 is
invertible
and A6:
(M1 @) * M1 = 1. (
K,
n)
;
M1 is Orthogonal
A7:
M1 ~ is_reverse_of M1
by A5, Def4;
then
((M1 ~) * M1) * (M1 ~) = ((M1 @) * M1) * (M1 ~)
by A6;
then
(M1 ~) * (M1 * (M1 ~)) = ((M1 @) * M1) * (M1 ~)
by A1, A4, A3, MATRIX_3:33;
then
(M1 ~) * (M1 * (M1 ~)) = (M1 @) * (M1 * (M1 ~))
by A1, A3, A2, MATRIX_3:33;
then
(M1 ~) * (1. (K,n)) = (M1 @) * (M1 * (M1 ~))
by A7;
then
(M1 ~) * (1. (K,n)) = (M1 @) * (1. (K,n))
by A7;
then
M1 ~ = (M1 @) * (1. (K,n))
by MATRIX_3:19;
then
M1 ~ = M1 @
by MATRIX_3:19;
hence
M1 is
Orthogonal
by A5;
verum
end;
assume A8:
M1 is Orthogonal
; ( M1 is invertible & (M1 @) * M1 = 1. (K,n) )
then A9:
M1 ~ is_reverse_of M1
by Def4;
(M1 @) * M1 = (M1 ~) * M1
by A8;
hence
( M1 is invertible & (M1 @) * M1 = 1. (K,n) )
by A9; verum