let n be Nat; for K being Ring
for M1 being Matrix of n,K holds
( ( M1 * (M1 @) = 1. (K,n) & M1 is invertible ) iff M1 is Orthogonal )
let K be Ring; for M1 being Matrix of n,K holds
( ( M1 * (M1 @) = 1. (K,n) & M1 is invertible ) iff M1 is Orthogonal )
let M1 be Matrix of n,K; ( ( M1 * (M1 @) = 1. (K,n) & M1 is invertible ) iff M1 is Orthogonal )
A1:
( width M1 = n & len M1 = n )
by MATRIX_0:24;
A2:
len (M1 @) = n
by MATRIX_0:24;
A3:
width (M1 ~) = n
by MATRIX_0:24;
A4:
len (M1 ~) = n
by MATRIX_0:24;
thus
( M1 * (M1 @) = 1. (K,n) & M1 is invertible implies M1 is Orthogonal )
( M1 is Orthogonal implies ( M1 * (M1 @) = 1. (K,n) & M1 is invertible ) )proof
assume that A5:
M1 * (M1 @) = 1. (
K,
n)
and A6:
M1 is
invertible
;
M1 is Orthogonal
A7:
M1 ~ is_reverse_of M1
by A6, Def4;
then
(M1 ~) * (M1 * (M1 ~)) = (M1 ~) * (M1 * (M1 @))
by A5;
then
((M1 ~) * M1) * (M1 ~) = (M1 ~) * (M1 * (M1 @))
by A1, A3, A4, MATRIX_3:33;
then
((M1 ~) * M1) * (M1 ~) = ((M1 ~) * M1) * (M1 @)
by A1, A3, A2, MATRIX_3:33;
then
(1. (K,n)) * (M1 ~) = ((M1 ~) * M1) * (M1 @)
by A7;
then
(1. (K,n)) * (M1 ~) = (1. (K,n)) * (M1 @)
by A7;
then
M1 ~ = (1. (K,n)) * (M1 @)
by MATRIX_3:18;
then
M1 ~ = M1 @
by MATRIX_3:18;
hence
M1 is
Orthogonal
by A6;
verum
end;
assume A8:
M1 is Orthogonal
; ( M1 * (M1 @) = 1. (K,n) & M1 is invertible )
then A9:
M1 ~ is_reverse_of M1
by Def4;
M1 * (M1 @) = M1 * (M1 ~)
by A8;
hence
( M1 * (M1 @) = 1. (K,n) & M1 is invertible )
by A9; verum