let n be Nat; for K being Field
for M1, M2 being Matrix of n,K st M1 is invertible & M2 is invertible & M1 commutes_with M2 holds
( M1 * M2 is invertible & (M1 * M2) ~ = (M1 ~) * (M2 ~) )
let K be Field; for M1, M2 being Matrix of n,K st M1 is invertible & M2 is invertible & M1 commutes_with M2 holds
( M1 * M2 is invertible & (M1 * M2) ~ = (M1 ~) * (M2 ~) )
let M1, M2 be Matrix of n,K; ( M1 is invertible & M2 is invertible & M1 commutes_with M2 implies ( M1 * M2 is invertible & (M1 * M2) ~ = (M1 ~) * (M2 ~) ) )
assume that
A1:
M1 is invertible
and
A2:
M2 is invertible
and
A3:
M1 commutes_with M2
; ( M1 * M2 is invertible & (M1 * M2) ~ = (M1 ~) * (M2 ~) )
A4:
M2 ~ is_reverse_of M2
by A2, Def4;
A5:
width ((M1 ~) * (M2 ~)) = n
by MATRIX_0:24;
A6:
width (M2 ~) = n
by MATRIX_0:24;
A7:
len M2 = n
by MATRIX_0:24;
A8:
width M1 = n
by MATRIX_0:24;
A9:
( width M2 = n & len M1 = n )
by MATRIX_0:24;
A10:
M1 ~ is_reverse_of M1
by A1, Def4;
A11:
( width (M1 ~) = n & len (M2 ~) = n )
by MATRIX_0:24;
A12:
len (M1 ~) = n
by MATRIX_0:24;
width (M1 * M2) = n
by MATRIX_0:24;
then A13: (M1 * M2) * ((M1 ~) * (M2 ~)) =
((M1 * M2) * (M1 ~)) * (M2 ~)
by A11, A12, MATRIX_3:33
.=
((M2 * M1) * (M1 ~)) * (M2 ~)
by A3
.=
(M2 * (M1 * (M1 ~))) * (M2 ~)
by A8, A9, A12, MATRIX_3:33
.=
(M2 * (1. (K,n))) * (M2 ~)
by A10
.=
M2 * (M2 ~)
by MATRIX_3:19
.=
1. (K,n)
by A4
;
((M1 ~) * (M2 ~)) * (M1 * M2) =
((M1 ~) * (M2 ~)) * (M2 * M1)
by A3
.=
(((M1 ~) * (M2 ~)) * M2) * M1
by A7, A9, A5, MATRIX_3:33
.=
((M1 ~) * ((M2 ~) * M2)) * M1
by A7, A11, A6, MATRIX_3:33
.=
((M1 ~) * (1. (K,n))) * M1
by A4
.=
(M1 ~) * M1
by MATRIX_3:19
.=
1. (K,n)
by A10
;
then A14:
(M1 ~) * (M2 ~) is_reverse_of M1 * M2
by A13;
then
M1 * M2 is invertible
;
hence
( M1 * M2 is invertible & (M1 * M2) ~ = (M1 ~) * (M2 ~) )
by A14, Def4; verum