let D be non empty set ; for I, J being non empty set
for F being BinOp of D
for f being Function of [:I,J:],D
for g being Function of I,D
for X being Element of Fin I
for Y being Element of Fin J st ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative holds
F $$ ([:X,Y:],f) = F $$ (X,g)
let I, J be non empty set ; for F being BinOp of D
for f being Function of [:I,J:],D
for g being Function of I,D
for X being Element of Fin I
for Y being Element of Fin J st ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative holds
F $$ ([:X,Y:],f) = F $$ (X,g)
let F be BinOp of D; for f being Function of [:I,J:],D
for g being Function of I,D
for X being Element of Fin I
for Y being Element of Fin J st ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative holds
F $$ ([:X,Y:],f) = F $$ (X,g)
let f be Function of [:I,J:],D; for g being Function of I,D
for X being Element of Fin I
for Y being Element of Fin J st ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative holds
F $$ ([:X,Y:],f) = F $$ (X,g)
let g be Function of I,D; for X being Element of Fin I
for Y being Element of Fin J st ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative holds
F $$ ([:X,Y:],f) = F $$ (X,g)
let X be Element of Fin I; for Y being Element of Fin J st ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative holds
F $$ ([:X,Y:],f) = F $$ (X,g)
let Y be Element of Fin J; ( ( for i being Element of I holds g . i = F $$ (Y,((curry f) . i)) ) & F is having_a_unity & F is commutative & F is associative implies F $$ ([:X,Y:],f) = F $$ (X,g) )
assume that
A1:
for i being Element of I holds g . i = F $$ (Y,((curry f) . i))
and
A2:
( F is having_a_unity & F is commutative & F is associative )
; F $$ ([:X,Y:],f) = F $$ (X,g)
defpred S1[ Element of Fin I] means F $$ ([:$1,Y:],f) = F $$ ($1,g);
A3:
for X1 being Element of Fin I
for x being Element of I st S1[X1] holds
S1[X1 \/ {.x.}]
proof
let X1 be
Element of
Fin I;
for x being Element of I st S1[X1] holds
S1[X1 \/ {.x.}]let x be
Element of
I;
( S1[X1] implies S1[X1 \/ {.x.}] )
assume A4:
F $$ (
[:X1,Y:],
f)
= F $$ (
X1,
g)
;
S1[X1 \/ {.x.}]
reconsider s =
{.x.} as
Element of
Fin I ;
per cases
( x in X1 or not x in X1 )
;
suppose
not
x in X1
;
S1[X1 \/ {.x.}]then A5:
X1 misses {x}
by ZFMISC_1:50;
then A6:
[:X1,Y:] misses [:s,Y:]
by ZFMISC_1:104;
thus F $$ (
[:(X1 \/ {.x.}),Y:],
f) =
F $$ (
([:X1,Y:] \/ [:s,Y:]),
f)
by ZFMISC_1:97
.=
F . (
(F $$ ([:X1,Y:],f)),
(F $$ ([:s,Y:],f)))
by A2, A6, SETWOP_2:4
.=
F . (
(F $$ (X1,g)),
(F $$ (s,g)))
by A1, A2, A4, Th29
.=
F $$ (
(X1 \/ {.x.}),
g)
by A2, A5, SETWOP_2:4
;
verum end; end;
end;
A7:
S1[ {}. I]
for X1 being Element of Fin I holds S1[X1]
from SETWISEO:sch 4(A7, A3);
hence
F $$ ([:X,Y:],f) = F $$ (X,g)
; verum