defpred S1[ FinSequence of NAT , Nat, Nat, Matrix of F2(),F3(),F1()] means ( $4 * ($2,($1 /. $2)) <> 0. F1() & ( $3 in dom $1 & $2 < $3 implies $1 /. $2 < $1 /. $3 ) & ( $3 in (dom $1) \ {$2} implies $4 * ($3,($1 /. $2)) = 0. F1() ) & ( $3 in Seg (width $4) & $3 < $1 /. $2 implies $4 * ($2,$3) = 0. F1() ) );
set r = the_rank_of F5();
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
proof
per cases
( F2() = 0 or F2() > 0 )
;
suppose A3:
F2()
= 0
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )take A9 =
F5();
ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )take B9 =
F6();
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
(
dom A9 = Seg (len A9) &
len A9 = 0 )
by A3, FINSEQ_1:def 3, MATRIX_0:def 2;
hence
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 & ( for
i being
Nat st
i in dom A9 &
i > the_rank_of F5() holds
Line (
A9,
i)
= F3()
|-> (0. F1()) ) )
by A1;
ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )take
<*> NAT
;
( len (<*> NAT) = the_rank_of A9 & <*> NAT is one-to-one & rng (<*> NAT) c= Seg (width A9) & ( for i, j being Nat st i in dom (<*> NAT) holds
S1[ <*> NAT,i,j,A9] ) )
len A9 = 0
by A3, MATRIX_0:22;
hence
(
len (<*> NAT) = the_rank_of A9 &
<*> NAT is
one-to-one &
rng (<*> NAT) c= Seg (width A9) & ( for
i,
j being
Nat st
i in dom (<*> NAT) holds
S1[
<*> NAT,
i,
j,
A9] ) )
by MATRIX13:74;
verum end; suppose A4:
F2()
> 0
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )defpred S2[
Nat]
means ( $1
<= F3() implies ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 & ex
f being
FinSequence of
NAT st
( ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= $1 holds
A9 * (
i,
j)
= 0. F1() ) &
f is
one-to-one &
len f <= $1 &
len f <= F2() &
rng f c= Seg $1 & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) ) ) );
A5:
for
n being
Nat st
S2[
n] holds
S2[
n + 1]
proof
let n be
Nat;
( S2[n] implies S2[n + 1] )
assume A6:
S2[
n]
;
S2[n + 1]
set n1 =
n + 1;
assume A7:
n + 1
<= F3()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n + 1 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= n + 1 & len f <= F2() & rng f c= Seg (n + 1) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
then consider A9 being
Matrix of
F2(),
F3(),
F1(),
B9 being
Matrix of
F2(),
F4(),
F1()
such that A8:
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 )
and A9:
ex
f being
FinSequence of
NAT st
( ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) &
f is
one-to-one &
len f <= n &
len f <= F2() &
rng f c= Seg n & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) )
by A6, NAT_1:13;
consider f being
FinSequence of
NAT such that A10:
for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1()
and A11:
f is
one-to-one
and A12:
len f <= n
and A13:
len f <= F2()
and A14:
rng f c= Seg n
and A15:
for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9]
by A9;
per cases
( for i, j being Nat st [i,j] in Indices A9 & i > len f & j = n + 1 holds
A9 * (i,j) = 0. F1() or ex i, j being Nat st
( [i,j] in Indices A9 & i > len f & j = n + 1 & A9 * (i,j) <> 0. F1() ) )
;
suppose A16:
for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j = n + 1 holds
A9 * (
i,
j)
= 0. F1()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n + 1 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= n + 1 & len f <= F2() & rng f c= Seg (n + 1) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
n <= n + 1
by NAT_1:13;
then
Seg n c= Seg (n + 1)
by FINSEQ_1:5;
then A20:
rng f c= Seg (n + 1)
by A14;
len f <= n + 1
by A12, NAT_1:12;
hence
ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 & ex
f being
FinSequence of
NAT st
( ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n + 1 holds
A9 * (
i,
j)
= 0. F1() ) &
f is
one-to-one &
len f <= n + 1 &
len f <= F2() &
rng f c= Seg (n + 1) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) ) )
by A8, A11, A13, A15, A17, A20;
verum end; suppose
ex
i,
j being
Nat st
(
[i,j] in Indices A9 &
i > len f &
j = n + 1 &
A9 * (
i,
j)
<> 0. F1() )
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n + 1 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= n + 1 & len f <= F2() & rng f c= Seg (n + 1) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )then consider i0,
j0 being
Nat such that A21:
[i0,j0] in Indices A9
and A22:
i0 > len f
and A23:
j0 = n + 1
and A24:
A9 * (
i0,
j0)
<> 0. F1()
;
A25:
Indices A9 = [:(Seg F2()),(Seg F3()):]
by A4, MATRIX_0:23;
then A26:
n + 1
in Seg F3()
by A21, A23, ZFMISC_1:87;
A27:
i0 in Seg F2()
by A21, A25, ZFMISC_1:87;
then A28:
i0 <= F2()
by FINSEQ_1:1;
A29:
(len f) + 1
<= i0
by A22, NAT_1:13;
then
(
0 + 1
<= (len f) + 1 &
(len f) + 1
<= F2() )
by A28, XREAL_1:7, XXREAL_0:2;
then A30:
(len f) + 1
in Seg F2()
;
defpred S3[
Nat]
means ( $1
<= F2() implies ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 &
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) & ( for
j being
Nat st
j in (dom A9) \ {((len f) + 1)} &
j <= $1 holds
A9 * (
j,
(n + 1))
= 0. F1() ) ) );
A31:
dom f = Seg (len f)
by FINSEQ_1:def 3;
n <= F3()
by A7, NAT_1:13;
then A32:
Seg n c= Seg F3()
by FINSEQ_1:5;
A33:
Seg (len f) c= Seg F2()
by A13, FINSEQ_1:5;
A34:
for
k being
Nat st
S3[
k] holds
S3[
k + 1]
proof
let k be
Nat;
( S3[k] implies S3[k + 1] )
assume A35:
S3[
k]
;
S3[k + 1]
set k1 =
k + 1;
assume
k + 1
<= F2()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )
then consider AA being
Matrix of
F2(),
F3(),
F1(),
BB being
Matrix of
F2(),
F4(),
F1()
such that A36:
P1[
AA,
BB]
and A37:
the_rank_of F5()
= the_rank_of AA
and A38:
AA * (
((len f) + 1),
(n + 1))
<> 0. F1()
and A39:
for
i,
j being
Nat st
[i,j] in Indices AA &
i > len f &
j <= n holds
AA * (
i,
j)
= 0. F1()
and A40:
for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
AA]
and A41:
for
j being
Nat st
j in (dom AA) \ {((len f) + 1)} &
j <= k holds
AA * (
j,
(n + 1))
= 0. F1()
by A35, NAT_1:13;
now ex RA being Matrix of F2(),F3(),F1() ex RB being Matrix of F2(),F4(),F1() ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )per cases
( k + 1 = (len f) + 1 or k + 1 <> (len f) + 1 )
;
suppose A42:
k + 1
= (len f) + 1
;
ex RA being Matrix of F2(),F3(),F1() ex RB being Matrix of F2(),F4(),F1() ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )take RA =
AA;
ex RB being Matrix of F2(),F4(),F1() ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )take RB =
BB;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )hence
ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 &
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) & ( for
j being
Nat st
j in (dom A9) \ {((len f) + 1)} &
j <= k + 1 holds
A9 * (
j,
(n + 1))
= 0. F1() ) )
by A36, A37, A38, A39, A40;
verum end; suppose A45:
k + 1
<> (len f) + 1
;
ex RA being FinSequence of the carrier of F1() * ex RB being Matrix of F2(),F4(),F1() ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )set LA =
Line (
AA,
(k + 1));
set LAf =
Line (
AA,
((len f) + 1));
set a =
AA * (
((len f) + 1),
(n + 1));
set RA =
RLine (
AA,
(k + 1),
((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))));
A46:
width AA = F3()
by A4, MATRIX_0:23;
then A47:
len ((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))) = F3()
by CARD_1:def 7;
A48:
Indices A9 = Indices AA
by MATRIX_0:26;
then
[((len f) + 1),(n + 1)] in Indices AA
by A25, A30, A26, ZFMISC_1:87;
then A49:
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (
((len f) + 1),
(n + 1))
<> 0. F1()
by A38, A45, A46, A47, MATRIX11:def 3;
A50:
Indices A9 = Indices (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1)))))))
by MATRIX_0:26;
A51:
now for i, j being Nat st [i,j] in Indices (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) & i > len f & j <= n holds
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (i,j) = 0. F1()let i,
j be
Nat;
( [i,j] in Indices (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) & i > len f & j <= n implies (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (i,j) = 0. F1() )assume that A52:
[i,j] in Indices (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1)))))))
and A53:
i > len f
and A54:
j <= n
;
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (i,j) = 0. F1()now (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (i,j) = 0. F1()per cases
( i = k + 1 or i <> k + 1 )
;
suppose A55:
i = k + 1
;
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (i,j) = 0. F1()A56:
j in Seg F3()
by A25, A50, A52, ZFMISC_1:87;
then
(
(len f) + 1
> len f &
[((len f) + 1),j] in Indices A9 )
by A25, A30, NAT_1:13, ZFMISC_1:87;
then
AA * (
((len f) + 1),
j)
= 0. F1()
by A39, A48, A54;
then
(Line (AA,((len f) + 1))) . j = 0. F1()
by A46, A56, MATRIX_0:def 7;
then A57:
((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1)))) . j =
(- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (0. F1())
by A46, A56, FVSUM_1:51
.=
0. F1()
;
(Line (AA,(k + 1))) . j =
AA * (
(k + 1),
j)
by A46, A56, MATRIX_0:def 7
.=
0. F1()
by A39, A48, A50, A52, A53, A54, A55
;
then (0. F1()) + (0. F1()) =
((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))) . j
by A46, A56, A57, FVSUM_1:18
.=
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (
i,
j)
by A48, A50, A46, A47, A52, A55, MATRIX11:def 3
;
hence
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (
i,
j)
= 0. F1()
by RLVECT_1:def 4;
verum end; suppose
i <> k + 1
;
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (i,j) = 0. F1()hence (RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (
i,
j) =
AA * (
i,
j)
by A48, A50, A46, A47, A52, MATRIX11:def 3
.=
0. F1()
by A39, A48, A50, A52, A53, A54
;
verum end; end; end; hence
(RLine (AA,(k + 1),((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))))) * (
i,
j)
= 0. F1()
;
verum end; set RB =
F7(
BB,
(k + 1),
((len f) + 1),
(- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))));
take RA =
RLine (
AA,
(k + 1),
((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))));
ex RB being Matrix of F2(),F4(),F1() ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )take RB =
F7(
BB,
(k + 1),
((len f) + 1),
(- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))));
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= k + 1 holds
A9 * (j,(n + 1)) = 0. F1() ) )A58:
width RA = F3()
by A4, MATRIX_0:23;
A59:
len AA = F2()
by MATRIX_0:def 2;
A60:
now for j being Nat st j in (dom RA) \ {((len f) + 1)} & j <= k + 1 holds
RA * (j,(n + 1)) = 0. F1()A61:
dom AA = Seg (len AA)
by FINSEQ_1:def 3;
let j be
Nat;
( j in (dom RA) \ {((len f) + 1)} & j <= k + 1 implies RA * (j,(n + 1)) = 0. F1() )assume that A62:
j in (dom RA) \ {((len f) + 1)}
and A63:
j <= k + 1
;
RA * (j,(n + 1)) = 0. F1()
j in dom RA
by A62, XBOOLE_0:def 5;
then A64:
[j,(n + 1)] in Indices AA
by A26, A48, A50, A58, ZFMISC_1:87;
A65:
(
dom RA = Seg (len RA) &
len RA = F2() )
by FINSEQ_1:def 3, MATRIX_0:def 2;
now RA * (j,(n + 1)) = 0. F1()per cases
( j <= k or j = k + 1 )
by A63, NAT_1:8;
suppose A66:
j <= k
;
RA * (j,(n + 1)) = 0. F1()then
j < k + 1
by NAT_1:13;
hence RA * (
j,
(n + 1)) =
AA * (
j,
(n + 1))
by A46, A47, A64, MATRIX11:def 3
.=
0. F1()
by A41, A59, A62, A65, A61, A66
;
verum end; suppose A67:
j = k + 1
;
RA * (j,(n + 1)) = 0. F1()
(Line (AA,((len f) + 1))) . (n + 1) = AA * (
((len f) + 1),
(n + 1))
by A26, A46, MATRIX_0:def 7;
then A68:
((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1)))) . (n + 1) =
(- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (AA * (((len f) + 1),(n + 1)))
by A26, A46, FVSUM_1:51
.=
((- (AA * ((k + 1),(n + 1)))) * ((AA * (((len f) + 1),(n + 1))) ")) * (AA * (((len f) + 1),(n + 1)))
by VECTSP_1:9
.=
(- (AA * ((k + 1),(n + 1)))) * (((AA * (((len f) + 1),(n + 1))) ") * (AA * (((len f) + 1),(n + 1))))
by GROUP_1:def 3
.=
(- (AA * ((k + 1),(n + 1)))) * (1_ F1())
by A38, VECTSP_1:def 10
.=
- (AA * ((k + 1),(n + 1)))
;
(Line (AA,(k + 1))) . (n + 1) = AA * (
(k + 1),
(n + 1))
by A26, A46, MATRIX_0:def 7;
then ((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))) . (n + 1) =
(AA * ((k + 1),(n + 1))) + (- (AA * ((k + 1),(n + 1))))
by A26, A46, A68, FVSUM_1:18
.=
0. F1()
by VECTSP_1:19
;
hence
RA * (
j,
(n + 1))
= 0. F1()
by A46, A47, A64, A67, MATRIX11:def 3;
verum end; end; end; hence
RA * (
j,
(n + 1))
= 0. F1()
;
verum end; A69:
dom AA = Seg (len AA)
by FINSEQ_1:def 3;
A70:
now for i, j being Nat st i in dom f holds
( RA * (i,(f /. i)) <> 0. F1() & ( j in dom f & i < j implies f /. i < f /. j ) & ( j in (dom f) \ {i} implies RA * (j,(f /. i)) = 0. F1() ) & ( j in Seg (width RA) & j < f /. i implies RA * (i,j) = 0. F1() ) )let i,
j be
Nat;
( i in dom f implies ( RA * (i,(f /. i)) <> 0. F1() & ( j in dom f & i < j implies f /. i < f /. j ) & ( j in (dom f) \ {i} implies RA * (j,(f /. i)) = 0. F1() ) & ( j in Seg (width RA) & j < f /. i implies RA * (i,j) = 0. F1() ) ) )assume A71:
i in dom f
;
( RA * (i,(f /. i)) <> 0. F1() & ( j in dom f & i < j implies f /. i < f /. j ) & ( j in (dom f) \ {i} implies RA * (j,(f /. i)) = 0. F1() ) & ( j in Seg (width RA) & j < f /. i implies RA * (i,j) = 0. F1() ) )set fi =
f /. i;
A72:
(
f /. i = f . i &
f . i in rng f )
by A71, FUNCT_1:def 3, PARTFUN1:def 6;
then A73:
f /. i in Seg n
by A14;
A74:
(
(len f) + 1
> len f &
f /. i <= n )
by A14, A72, FINSEQ_1:1, NAT_1:13;
(
[((len f) + 1),(f /. i)] in Indices AA &
(Line (AA,((len f) + 1))) . (f /. i) = AA * (
((len f) + 1),
(f /. i)) )
by A25, A32, A30, A48, A46, A73, MATRIX_0:def 7, ZFMISC_1:87;
then
(Line (AA,((len f) + 1))) . (f /. i) = 0. F1()
by A39, A74;
then A75:
((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1)))) . (f /. i) =
(- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (0. F1())
by A32, A46, A73, FVSUM_1:51
.=
0. F1()
;
(Line (AA,(k + 1))) . (f /. i) = AA * (
(k + 1),
(f /. i))
by A32, A46, A73, MATRIX_0:def 7;
then A76:
((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))) . (f /. i) =
(AA * ((k + 1),(f /. i))) + (0. F1())
by A32, A46, A73, A75, FVSUM_1:18
.=
AA * (
(k + 1),
(f /. i))
by RLVECT_1:def 4
;
A77:
[i,(f /. i)] in Indices AA
by A25, A32, A33, A31, A48, A71, A73, ZFMISC_1:87;
hence
(
RA * (
i,
(f /. i))
<> 0. F1() & (
j in dom f &
i < j implies
f /. i < f /. j ) )
by A15, A71;
( ( j in (dom f) \ {i} implies RA * (j,(f /. i)) = 0. F1() ) & ( j in Seg (width RA) & j < f /. i implies RA * (i,j) = 0. F1() ) )thus
(
j in (dom f) \ {i} implies
RA * (
j,
(f /. i))
= 0. F1() )
( j in Seg (width RA) & j < f /. i implies RA * (i,j) = 0. F1() )proof
assume A78:
j in (dom f) \ {i}
;
RA * (j,(f /. i)) = 0. F1()
then
j in Seg (len f)
by A31, XBOOLE_0:def 5;
then A79:
[j,(f /. i)] in Indices AA
by A25, A32, A33, A48, A73, ZFMISC_1:87;
per cases
( j <> k + 1 or j = k + 1 )
;
suppose A80:
j = k + 1
;
RA * (j,(f /. i)) = 0. F1()hence RA * (
j,
(f /. i)) =
((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))) . (f /. i)
by A46, A47, A79, MATRIX11:def 3
.=
0. F1()
by A40, A71, A76, A78, A80
;
verum end; end;
end; thus
(
j in Seg (width RA) &
j < f /. i implies
RA * (
i,
j)
= 0. F1() )
verumproof
assume that A81:
j in Seg (width RA)
and A82:
j < f /. i
;
RA * (i,j) = 0. F1()
A83:
[((len f) + 1),j] in Indices AA
by A30, A59, A69, A46, A58, A81, ZFMISC_1:87;
A84:
[i,j] in Indices AA
by A33, A31, A59, A69, A46, A58, A71, A81, ZFMISC_1:87;
per cases
( i <> k + 1 or i = k + 1 )
;
suppose
i <> k + 1
;
RA * (i,j) = 0. F1()hence RA * (
i,
j) =
AA * (
i,
j)
by A46, A47, A84, MATRIX11:def 3
.=
0. F1()
by A40, A46, A58, A71, A81, A82
;
verum end; suppose A85:
i = k + 1
;
RA * (i,j) = 0. F1()
f /. i <= n
by A14, A72, FINSEQ_1:1;
then A86:
j <= n
by A82, XXREAL_0:2;
(len f) + 1
> len f
by NAT_1:13;
then 0. F1() =
AA * (
((len f) + 1),
j)
by A39, A83, A86
.=
(Line (AA,((len f) + 1))) . j
by A46, A58, A81, MATRIX_0:def 7
;
then A87:
((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1)))) . j =
(- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (0. F1())
by A46, A58, A81, FVSUM_1:51
.=
0. F1()
;
(Line (AA,(k + 1))) . j =
AA * (
i,
j)
by A46, A58, A81, A85, MATRIX_0:def 7
.=
0. F1()
by A40, A46, A58, A71, A81, A82
;
then ((Line (AA,(k + 1))) + ((- ((AA * ((k + 1),(n + 1))) * ((AA * (((len f) + 1),(n + 1))) "))) * (Line (AA,((len f) + 1))))) . j =
(0. F1()) + (0. F1())
by A46, A58, A81, A87, FVSUM_1:18
.=
0. F1()
by RLVECT_1:def 4
;
hence
RA * (
i,
j)
= 0. F1()
by A46, A47, A84, A85, MATRIX11:def 3;
verum end; end;
end; end; A88:
(len f) + 1
in Seg (len AA)
by A4, A30, MATRIX_0:23;
then A89:
the_rank_of F5()
= the_rank_of RA
by A37, A45, MATRIX13:92;
P1[
RA,
RB]
by A2, A36, A45, A88, A69;
hence
ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 &
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) & ( for
j being
Nat st
j in (dom A9) \ {((len f) + 1)} &
j <= k + 1 holds
A9 * (
j,
(n + 1))
= 0. F1() ) )
by A89, A49, A51, A70, A60;
verum end; end; end;
hence
ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 &
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) & ( for
j being
Nat st
j in (dom A9) \ {((len f) + 1)} &
j <= k + 1 holds
A9 * (
j,
(n + 1))
= 0. F1() ) )
;
verum
end; A90:
j0 in Seg F3()
by A21, A25, ZFMISC_1:87;
ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 &
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) )
proof
per cases
( A9 * (((len f) + 1),(n + 1)) <> 0. F1() or A9 * (((len f) + 1),(n + 1)) = 0. F1() )
;
suppose
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )hence
ex
A9 being
Matrix of
F2(),
F3(),
F1() ex
B9 being
Matrix of
F2(),
F4(),
F1() st
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 &
A9 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= n holds
A9 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) )
by A8, A10, A15;
verum end; suppose A91:
A9 * (
((len f) + 1),
(n + 1))
= 0. F1()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )set RB =
F7(
B9,
((len f) + 1),
i0,
(1_ F1()));
set LA =
Line (
A9,
i0);
set LAf =
Line (
A9,
((len f) + 1));
set RA =
RLine (
A9,
((len f) + 1),
((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))));
take
RLine (
A9,
((len f) + 1),
((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))
;
ex B9 being Matrix of F2(),F4(),F1() st
( P1[ RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0))))),B9] & the_rank_of F5() = the_rank_of (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & i > len f & j <= n holds
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))] ) )take
F7(
B9,
((len f) + 1),
i0,
(1_ F1()))
;
( P1[ RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0))))),F7(B9,((len f) + 1),i0,(1_ F1()))] & the_rank_of F5() = the_rank_of (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & i > len f & j <= n holds
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))] ) )
(
i0 in dom A9 &
dom A9 = Seg (len A9) )
by A21, FINSEQ_1:def 3, ZFMISC_1:87;
hence
(
P1[
RLine (
A9,
((len f) + 1),
((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0))))),
F7(
B9,
((len f) + 1),
i0,
(1_ F1()))] &
the_rank_of F5()
= the_rank_of (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) )
by A2, A8, A23, A24, A91, MATRIX13:92;
( (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & i > len f & j <= n holds
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))] ) )A92:
(
(1_ F1()) * (Line (A9,i0)) = Line (
A9,
i0) &
len ((Line (A9,((len f) + 1))) + (Line (A9,i0))) = width A9 )
by CARD_1:def 7, FVSUM_1:57;
[((len f) + 1),j0] in Indices A9
by A25, A30, A90, ZFMISC_1:87;
then A93:
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
((len f) + 1),
(n + 1))
= ((Line (A9,((len f) + 1))) + (Line (A9,i0))) . (n + 1)
by A23, A92, MATRIX11:def 3;
A94:
width A9 = F3()
by A4, MATRIX_0:23;
then A95:
(Line (A9,i0)) . (n + 1) = A9 * (
i0,
(n + 1))
by A23, A90, MATRIX_0:def 7;
(Line (A9,((len f) + 1))) . (n + 1) = 0. F1()
by A23, A90, A91, A94, MATRIX_0:def 7;
then (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
((len f) + 1),
(n + 1)) =
(0. F1()) + (A9 * (i0,(n + 1)))
by A26, A94, A93, A95, FVSUM_1:18
.=
A9 * (
i0,
(n + 1))
by RLVECT_1:def 4
;
hence
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
((len f) + 1),
(n + 1))
<> 0. F1()
by A23, A24;
( ( for i, j being Nat st [i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & i > len f & j <= n holds
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))] ) )A96:
Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) = Indices A9
by MATRIX_0:26;
now for i, j being Nat st [i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & i > len f & j <= n holds
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1()let i,
j be
Nat;
( [i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) & i > len f & j <= n implies (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() )assume that A97:
[i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0))))))
and A98:
i > len f
and A99:
j <= n
;
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1()A100:
j in Seg F3()
by A94, A96, A97, ZFMISC_1:87;
A101:
i >= (len f) + 1
by A98, NAT_1:13;
now (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1()per cases
( i > (len f) + 1 or i = (len f) + 1 )
by A101, XXREAL_0:1;
suppose
i > (len f) + 1
;
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1()hence (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
j) =
A9 * (
i,
j)
by A92, A96, A97, MATRIX11:def 3
.=
0. F1()
by A10, A96, A97, A98, A99
;
verum end; suppose A102:
i = (len f) + 1
;
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1()A103:
[i0,j] in Indices A9
by A25, A27, A100, ZFMISC_1:87;
A104:
(
(Line (A9,((len f) + 1))) . j = A9 * (
((len f) + 1),
j) &
(Line (A9,i0)) . j = A9 * (
i0,
j) )
by A94, A100, MATRIX_0:def 7;
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
j)
= ((Line (A9,((len f) + 1))) + (Line (A9,i0))) . j
by A92, A96, A97, A102, MATRIX11:def 3;
hence (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
j) =
(A9 * (((len f) + 1),j)) + (A9 * (i0,j))
by A94, A100, A104, FVSUM_1:18
.=
(0. F1()) + (A9 * (i0,j))
by A10, A96, A97, A98, A99, A102
.=
(0. F1()) + (0. F1())
by A10, A22, A99, A103
.=
0. F1()
by RLVECT_1:def 4
;
verum end; end; end; hence
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
j)
= 0. F1()
;
verum end; hence
for
i,
j being
Nat st
[i,j] in Indices (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) &
i > len f &
j <= n holds
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
j)
= 0. F1()
;
for i, j being Nat st i in dom f holds
S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))]let i,
j be
Nat;
( i in dom f implies S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))] )assume A105:
i in dom f
;
S1[f,i,j, RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))]
i <= len f
by A31, A105, FINSEQ_1:1;
then A106:
i < (len f) + 1
by NAT_1:13;
(
f /. i = f . i &
f . i in rng f )
by A105, FUNCT_1:def 3, PARTFUN1:def 6;
then A107:
f /. i in Seg n
by A14;
then
[i,(f /. i)] in Indices A9
by A25, A32, A33, A31, A105, ZFMISC_1:87;
then
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
(f /. i))
= A9 * (
i,
(f /. i))
by A92, A106, MATRIX11:def 3;
hence
(
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
(f /. i))
<> 0. F1() & (
j in dom f &
i < j implies
f /. i < f /. j ) )
by A15, A105;
( ( j in (dom f) \ {i} implies (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (j,(f /. i)) = 0. F1() ) & ( j in Seg (width (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0))))))) & j < f /. i implies (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() ) )thus
(
j in (dom f) \ {i} implies
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
j,
(f /. i))
= 0. F1() )
( j in Seg (width (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0))))))) & j < f /. i implies (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1() )proof
assume A108:
j in (dom f) \ {i}
;
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (j,(f /. i)) = 0. F1()
then A109:
j in dom f
by XBOOLE_0:def 5;
then
j <= len f
by A31, FINSEQ_1:1;
then A110:
j < (len f) + 1
by NAT_1:13;
[j,(f /. i)] in Indices A9
by A25, A32, A33, A31, A107, A109, ZFMISC_1:87;
hence (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
j,
(f /. i)) =
A9 * (
j,
(f /. i))
by A92, A110, MATRIX11:def 3
.=
0. F1()
by A15, A105, A108
;
verum
end; assume that A111:
j in Seg (width (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))))
and A112:
j < f /. i
;
(RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (i,j) = 0. F1()A113:
width (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) = width A9
by A92, MATRIX11:def 3;
then
[i,j] in Indices A9
by A25, A33, A31, A94, A105, A111, ZFMISC_1:87;
hence (RLine (A9,((len f) + 1),((Line (A9,((len f) + 1))) + ((1_ F1()) * (Line (A9,i0)))))) * (
i,
j) =
A9 * (
i,
j)
by A92, A106, MATRIX11:def 3
.=
0. F1()
by A15, A105, A111, A112, A113
;
verum end; end;
end; then consider A0 being
Matrix of
F2(),
F3(),
F1(),
B0 being
Matrix of
F2(),
F4(),
F1()
such that A114:
(
P1[
A0,
B0] &
the_rank_of F5()
= the_rank_of A0 &
A0 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A0 &
i > len f &
j <= n holds
A0 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A0] ) )
;
A115:
S3[
0 ]
proof
assume
0 <= F2()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & A9 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= n holds
A9 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) & ( for j being Nat st j in (dom A9) \ {((len f) + 1)} & j <= 0 holds
A9 * (j,(n + 1)) = 0. F1() ) )
take
A0
;
ex B9 being Matrix of F2(),F4(),F1() st
( P1[A0,B9] & the_rank_of F5() = the_rank_of A0 & A0 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A0 & i > len f & j <= n holds
A0 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A0] ) & ( for j being Nat st j in (dom A0) \ {((len f) + 1)} & j <= 0 holds
A0 * (j,(n + 1)) = 0. F1() ) )
take
B0
;
( P1[A0,B0] & the_rank_of F5() = the_rank_of A0 & A0 * (((len f) + 1),(n + 1)) <> 0. F1() & ( for i, j being Nat st [i,j] in Indices A0 & i > len f & j <= n holds
A0 * (i,j) = 0. F1() ) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A0] ) & ( for j being Nat st j in (dom A0) \ {((len f) + 1)} & j <= 0 holds
A0 * (j,(n + 1)) = 0. F1() ) )
hence
(
P1[
A0,
B0] &
the_rank_of F5()
= the_rank_of A0 &
A0 * (
((len f) + 1),
(n + 1))
<> 0. F1() & ( for
i,
j being
Nat st
[i,j] in Indices A0 &
i > len f &
j <= n holds
A0 * (
i,
j)
= 0. F1() ) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A0] ) & ( for
j being
Nat st
j in (dom A0) \ {((len f) + 1)} &
j <= 0 holds
A0 * (
j,
(n + 1))
= 0. F1() ) )
by A114;
verum
end;
for
k being
Nat holds
S3[
k]
from NAT_1:sch 2(A115, A34);
then consider Aa being
Matrix of
F2(),
F3(),
F1(),
Bb being
Matrix of
F2(),
F4(),
F1()
such that A117:
(
P1[
Aa,
Bb] &
the_rank_of F5()
= the_rank_of Aa )
and A118:
Aa * (
((len f) + 1),
(n + 1))
<> 0. F1()
and A119:
for
i,
j being
Nat st
[i,j] in Indices Aa &
i > len f &
j <= n holds
Aa * (
i,
j)
= 0. F1()
and A120:
for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
Aa]
and A121:
for
j being
Nat st
j in (dom Aa) \ {((len f) + 1)} &
j <= F2() holds
Aa * (
j,
(n + 1))
= 0. F1()
;
take
Aa
;
ex B9 being Matrix of F2(),F4(),F1() st
( P1[Aa,B9] & the_rank_of F5() = the_rank_of Aa & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices Aa & i > len f & j <= n + 1 holds
Aa * (i,j) = 0. F1() ) & f is one-to-one & len f <= n + 1 & len f <= F2() & rng f c= Seg (n + 1) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,Aa] ) ) )take
Bb
;
( P1[Aa,Bb] & the_rank_of F5() = the_rank_of Aa & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices Aa & i > len f & j <= n + 1 holds
Aa * (i,j) = 0. F1() ) & f is one-to-one & len f <= n + 1 & len f <= F2() & rng f c= Seg (n + 1) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,Aa] ) ) )thus
(
P1[
Aa,
Bb] &
the_rank_of F5()
= the_rank_of Aa )
by A117;
ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices Aa & i > len f & j <= n + 1 holds
Aa * (i,j) = 0. F1() ) & f is one-to-one & len f <= n + 1 & len f <= F2() & rng f c= Seg (n + 1) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,Aa] ) )take f9 =
f ^ <*(n + 1)*>;
( ( for i, j being Nat st [i,j] in Indices Aa & i > len f9 & j <= n + 1 holds
Aa * (i,j) = 0. F1() ) & f9 is one-to-one & len f9 <= n + 1 & len f9 <= F2() & rng f9 c= Seg (n + 1) & ( for i, j being Nat st i in dom f9 holds
S1[f9,i,j,Aa] ) )A122:
len f9 = (len f) + 1
by FINSEQ_2:16;
A123:
(
len Aa = F2() &
dom Aa = Seg (len Aa) )
by A4, FINSEQ_1:def 3, MATRIX_0:23;
A130:
width Aa = F3()
by A4, MATRIX_0:23;
A131:
len f9 <= F2()
by A28, A29, A122, XXREAL_0:2;
A132:
now for i, j being Nat st i in dom f9 holds
( Aa * (i,(f9 /. i)) <> 0. F1() & ( j in dom f9 & i < j implies f9 /. i < f9 /. j ) & ( j in (dom f9) \ {i} implies Aa * (j,(f9 /. i)) = 0. F1() ) & ( j in Seg (width Aa) & j < f9 /. i implies Aa * (i,j) = 0. F1() ) )let i,
j be
Nat;
( i in dom f9 implies ( Aa * (i,(f9 /. i)) <> 0. F1() & ( j in dom f9 & i < j implies f9 /. i < f9 /. j ) & ( j in (dom f9) \ {i} implies Aa * (j,(f9 /. i)) = 0. F1() ) & ( j in Seg (width Aa) & j < f9 /. i implies Aa * (i,j) = 0. F1() ) ) )assume A133:
i in dom f9
;
( Aa * (i,(f9 /. i)) <> 0. F1() & ( j in dom f9 & i < j implies f9 /. i < f9 /. j ) & ( j in (dom f9) \ {i} implies Aa * (j,(f9 /. i)) = 0. F1() ) & ( j in Seg (width Aa) & j < f9 /. i implies Aa * (i,j) = 0. F1() ) )A134:
dom f9 =
Seg ((len f) + 1)
by A122, FINSEQ_1:def 3
.=
(dom f) \/ {((len f) + 1)}
by A31, FINSEQ_1:9
;
hence
Aa * (
i,
(f9 /. i))
<> 0. F1()
;
( ( j in dom f9 & i < j implies f9 /. i < f9 /. j ) & ( j in (dom f9) \ {i} implies Aa * (j,(f9 /. i)) = 0. F1() ) & ( j in Seg (width Aa) & j < f9 /. i implies Aa * (i,j) = 0. F1() ) )thus
(
j in dom f9 &
i < j implies
f9 /. i < f9 /. j )
( ( j in (dom f9) \ {i} implies Aa * (j,(f9 /. i)) = 0. F1() ) & ( j in Seg (width Aa) & j < f9 /. i implies Aa * (i,j) = 0. F1() ) )
dom f9 = Seg (len f9)
by FINSEQ_1:def 3;
then A148:
dom f9 c= dom Aa
by A123, A131, FINSEQ_1:5;
thus
(
j in (dom f9) \ {i} implies
Aa * (
j,
(f9 /. i))
= 0. F1() )
( j in Seg (width Aa) & j < f9 /. i implies Aa * (i,j) = 0. F1() )proof
assume A149:
j in (dom f9) \ {i}
;
Aa * (j,(f9 /. i)) = 0. F1()
per cases
( i = (len f) + 1 or i <> (len f) + 1 )
;
suppose A150:
i = (len f) + 1
;
Aa * (j,(f9 /. i)) = 0. F1()
(len f) + 1
in {((len f) + 1)}
by TARSKI:def 1;
then
(len f) + 1
in dom f9
by A134, XBOOLE_0:def 3;
then A151:
f9 . ((len f) + 1) = f9 /. i
by A150, PARTFUN1:def 6;
A152:
j in dom f9
by A149, ZFMISC_1:56;
j <> i
by A149, ZFMISC_1:56;
then A153:
j in (dom Aa) \ {i}
by A148, A152, ZFMISC_1:56;
j <= F2()
by A123, A148, A152, FINSEQ_1:1;
then
Aa * (
j,
(n + 1))
= 0. F1()
by A121, A150, A153;
hence
Aa * (
j,
(f9 /. i))
= 0. F1()
by A151, FINSEQ_1:42;
verum end; suppose A154:
i <> (len f) + 1
;
Aa * (j,(f9 /. i)) = 0. F1()A155:
j in dom f9
by A149, XBOOLE_0:def 5;
A156:
(
i in dom f or
i in {((len f) + 1)} )
by A133, A134, XBOOLE_0:def 3;
then A157:
f . i in rng f
by A154, FUNCT_1:def 3, TARSKI:def 1;
A158:
(
f /. i = f9 /. i &
f . i = f /. i )
by A135, A154, A156, PARTFUN1:def 6, TARSKI:def 1;
then A159:
1
<= f9 /. i
by A14, A157, FINSEQ_1:1;
A160:
f9 /. i <= n
by A14, A158, A157, FINSEQ_1:1;
n <= F3()
by A7, NAT_1:13;
then
f9 /. i <= F3()
by A160, XXREAL_0:2;
then
f9 /. i in Seg (width Aa)
by A130, A159;
then A161:
[j,(f9 /. i)] in Indices Aa
by A148, A155, ZFMISC_1:87;
per cases
( j = (len f) + 1 or j <> (len f) + 1 )
;
suppose A162:
j <> (len f) + 1
;
Aa * (j,(f9 /. i)) = 0. F1()
j in dom f9
by A149, XBOOLE_0:def 5;
then A163:
(
j in dom f or
j in {((len f) + 1)} )
by A134, XBOOLE_0:def 3;
j <> i
by A149, ZFMISC_1:56;
then
j in (dom f) \ {i}
by A162, A163, TARSKI:def 1, ZFMISC_1:56;
then
Aa * (
j,
(f /. i))
= 0. F1()
by A120, A154, A156, TARSKI:def 1;
hence
Aa * (
j,
(f9 /. i))
= 0. F1()
by A135, A154, A156, TARSKI:def 1;
verum end; end; end; end;
end; thus
(
j in Seg (width Aa) &
j < f9 /. i implies
Aa * (
i,
j)
= 0. F1() )
verumproof
assume that A164:
j in Seg (width Aa)
and A165:
j < f9 /. i
;
Aa * (i,j) = 0. F1()
per cases
( i in dom f or not i in dom f )
;
suppose A167:
not
i in dom f
;
Aa * (i,j) = 0. F1()
(
i in dom f or
i in {((len f) + 1)} )
by A133, A134, XBOOLE_0:def 3;
then A168:
i = (len f) + 1
by A167, TARSKI:def 1;
then A169:
f9 . i = n + 1
by FINSEQ_1:42;
f9 . i = f9 /. i
by A133, PARTFUN1:def 6;
then A170:
j <= n
by A165, A169, NAT_1:13;
A171:
i > len f
by A168, NAT_1:13;
[i,j] in Indices Aa
by A133, A148, A164, ZFMISC_1:87;
hence
Aa * (
i,
j)
= 0. F1()
by A119, A170, A171;
verum end; end;
end; end; A172:
(
rng <*(n + 1)*> = {(n + 1)} &
(rng f) \/ {(n + 1)} c= (Seg n) \/ {(n + 1)} )
by A14, FINSEQ_1:38, XBOOLE_1:9;
A173:
(Seg n) \/ {(n + 1)} = Seg (n + 1)
by FINSEQ_1:9;
(
rng f misses {(n + 1)} &
<*(n + 1)*> is
one-to-one )
by A14, FINSEQ_3:14, XBOOLE_1:63;
hence
( ( for
i,
j being
Nat st
[i,j] in Indices Aa &
i > len f9 &
j <= n + 1 holds
Aa * (
i,
j)
= 0. F1() ) &
f9 is
one-to-one &
len f9 <= n + 1 &
len f9 <= F2() &
rng f9 c= Seg (n + 1) & ( for
i,
j being
Nat st
i in dom f9 holds
S1[
f9,
i,
j,
Aa] ) )
by A11, A12, A28, A29, A122, A124, A172, A173, A132, FINSEQ_1:31, FINSEQ_3:91, XREAL_1:6, XXREAL_0:2;
verum end; end;
end; A174:
S2[
0 ]
proof
assume
0 <= F3()
;
ex A9 being Matrix of F2(),F3(),F1() ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= 0 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= 0 & len f <= F2() & rng f c= Seg 0 & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
take A9 =
F5();
ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= 0 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= 0 & len f <= F2() & rng f c= Seg 0 & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
take B9 =
F6();
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= 0 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= 0 & len f <= F2() & rng f c= Seg 0 & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )
thus
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 )
by A1;
ex f being FinSequence of NAT st
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= 0 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= 0 & len f <= F2() & rng f c= Seg 0 & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )
take f =
<*> NAT;
( ( for i, j being Nat st [i,j] in Indices A9 & i > len f & j <= 0 holds
A9 * (i,j) = 0. F1() ) & f is one-to-one & len f <= 0 & len f <= F2() & rng f c= Seg 0 & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )
hence
( ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= 0 holds
A9 * (
i,
j)
= 0. F1() ) &
f is
one-to-one &
len f <= 0 &
len f <= F2() &
rng f c= Seg 0 & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) )
;
verum
end;
for
n being
Nat holds
S2[
n]
from NAT_1:sch 2(A174, A5);
then consider A9 being
Matrix of
F2(),
F3(),
F1(),
B9 being
Matrix of
F2(),
F4(),
F1()
such that A177:
P1[
A9,
B9]
and A178:
the_rank_of F5()
= the_rank_of A9
and A179:
ex
f being
FinSequence of
NAT st
( ( for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= F3() holds
A9 * (
i,
j)
= 0. F1() ) &
f is
one-to-one &
len f <= F3() &
len f <= F2() &
rng f c= Seg F3() & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) )
;
consider f being
FinSequence of
NAT such that A180:
for
i,
j being
Nat st
[i,j] in Indices A9 &
i > len f &
j <= F3() holds
A9 * (
i,
j)
= 0. F1()
and A181:
f is
one-to-one
and
len f <= F3()
and A182:
len f <= F2()
and A183:
rng f c= Seg F3()
and A184:
for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9]
by A179;
A185:
len A9 = F2()
by A4, MATRIX_0:23;
take
A9
;
ex B9 being Matrix of F2(),F4(),F1() st
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )take
B9
;
( P1[A9,B9] & the_rank_of F5() = the_rank_of A9 & ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )thus
(
P1[
A9,
B9] &
the_rank_of F5()
= the_rank_of A9 )
by A177, A178;
( ( for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1()) ) & ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) ) )A186:
dom A9 = Seg (len A9)
by FINSEQ_1:def 3;
set L =
len f;
A187:
Seg (len f) c= Seg F2()
by A182, FINSEQ_1:5;
(
idseq (len f) is
FinSequence of
NAT &
len (idseq (len f)) = len f )
by CARD_1:def 7, FINSEQ_2:48;
then reconsider idL =
idseq (len f),
F9 =
f as
Element of
(len f) -tuples_on NAT by FINSEQ_2:92;
set S =
Segm (
A9,
idL,
F9);
A188:
dom f = Seg (len f)
by FINSEQ_1:def 3;
set D =
diagonal_of_Matrix (Segm (A9,idL,F9));
A189:
Indices (Segm (A9,idL,F9)) = [:(Seg (len f)),(Seg (len f)):]
by MATRIX_0:24;
for
k being
Nat st
k in dom (diagonal_of_Matrix (Segm (A9,idL,F9))) holds
(diagonal_of_Matrix (Segm (A9,idL,F9))) . k <> 0. F1()
proof
A190:
len (diagonal_of_Matrix (Segm (A9,idL,F9))) = len f
by MATRIX_3:def 10;
let k be
Nat;
( k in dom (diagonal_of_Matrix (Segm (A9,idL,F9))) implies (diagonal_of_Matrix (Segm (A9,idL,F9))) . k <> 0. F1() )
assume
k in dom (diagonal_of_Matrix (Segm (A9,idL,F9)))
;
(diagonal_of_Matrix (Segm (A9,idL,F9))) . k <> 0. F1()
then A191:
k in Seg (len f)
by A190, FINSEQ_1:def 3;
then
[k,k] in Indices (Segm (A9,idL,F9))
by A189, ZFMISC_1:87;
then (Segm (A9,idL,F9)) * (
k,
k) =
A9 * (
(idL . k),
(f . k))
by MATRIX13:def 1
.=
A9 * (
k,
(f . k))
by A191, FINSEQ_2:49
.=
A9 * (
k,
(f /. k))
by A188, A191, PARTFUN1:def 6
;
then
(Segm (A9,idL,F9)) * (
k,
k)
<> 0. F1()
by A184, A188, A191;
hence
(diagonal_of_Matrix (Segm (A9,idL,F9))) . k <> 0. F1()
by A191, MATRIX_3:def 10;
verum
end; then A192:
Product (diagonal_of_Matrix (Segm (A9,idL,F9))) <> 0. F1()
by FVSUM_1:82;
now for i, j being Nat st [i,j] in Indices (Segm (A9,idL,F9)) & i > j holds
(Segm (A9,idL,F9)) * (i,j) = 0. F1()let i,
j be
Nat;
( [i,j] in Indices (Segm (A9,idL,F9)) & i > j implies (Segm (A9,idL,F9)) * (i,j) = 0. F1() )assume A193:
[i,j] in Indices (Segm (A9,idL,F9))
;
( i > j implies (Segm (A9,idL,F9)) * (i,j) = 0. F1() )A194:
i in Seg (len f)
by A189, A193, ZFMISC_1:87;
assume
i > j
;
(Segm (A9,idL,F9)) * (i,j) = 0. F1()then A195:
i in (dom f) \ {j}
by A188, A194, ZFMISC_1:56;
reconsider i9 =
i,
j9 =
j as
Element of
NAT by ORDINAL1:def 12;
A196:
j in Seg (len f)
by A189, A193, ZFMISC_1:87;
thus (Segm (A9,idL,F9)) * (
i,
j) =
A9 * (
(idL . i9),
(f . j9))
by A193, MATRIX13:def 1
.=
A9 * (
i,
(f . j))
by A194, FINSEQ_2:49
.=
A9 * (
i,
(f /. j))
by A188, A196, PARTFUN1:def 6
.=
0. F1()
by A184, A188, A196, A195
;
verum end; then
Segm (
A9,
idL,
F9) is
upper_triangular Matrix of
len f,
F1()
by MATRIX_1:def 8;
then A197:
Det (Segm (A9,idL,F9)) <> 0. F1()
by A192, MATRIX13:7;
A198:
len (Segm (A9,(Seg (len f)),(Seg (width A9)))) = card (Seg (len f))
by MATRIX_0:def 2;
A199:
width A9 = F3()
by A4, MATRIX_0:23;
[:(rng idL),(rng F9):] c= Indices A9
by A183, A187, A185, A186, A199, ZFMISC_1:96;
then A200:
the_rank_of A9 >= len f
by A197, MATRIX13:76;
A201:
now for i being Nat st i in (dom A9) \ (Seg (len f)) holds
Line (A9,i) = (width A9) |-> (0. F1())set w0 =
(width A9) |-> (0. F1());
let i be
Nat;
( i in (dom A9) \ (Seg (len f)) implies Line (A9,i) = (width A9) |-> (0. F1()) )assume A202:
i in (dom A9) \ (Seg (len f))
;
Line (A9,i) = (width A9) |-> (0. F1())set LA =
Line (
A9,
i);
A203:
now for j being Nat st 1 <= j & j <= width A9 holds
(Line (A9,i)) . j = ((width A9) |-> (0. F1())) . j
not
i in Seg (len f)
by A202, XBOOLE_0:def 5;
then A204:
(
i > len f or
i < 1 )
;
let j be
Nat;
( 1 <= j & j <= width A9 implies (Line (A9,i)) . j = ((width A9) |-> (0. F1())) . j )assume that A205:
1
<= j
and A206:
j <= width A9
;
(Line (A9,i)) . j = ((width A9) |-> (0. F1())) . jA207:
j in Seg (width A9)
by A205, A206;
A208:
i in dom A9
by A202, XBOOLE_0:def 5;
then A209:
[i,j] in Indices A9
by A207, ZFMISC_1:87;
thus (Line (A9,i)) . j =
A9 * (
i,
j)
by A207, MATRIX_0:def 7
.=
0. F1()
by A180, A186, A199, A206, A208, A209, A204, FINSEQ_1:1
.=
((width A9) |-> (0. F1())) . j
by A207, FINSEQ_2:57
;
verum end;
(
len (Line (A9,i)) = width A9 &
len ((width A9) |-> (0. F1())) = width A9 )
by CARD_1:def 7;
hence
Line (
A9,
i)
= (width A9) |-> (0. F1())
by A203;
verum end; then
the_rank_of A9 = the_rank_of (Segm (A9,(Seg (len f)),(Seg (width A9))))
by A187, A185, A186, Th11;
then
the_rank_of A9 <= card (Seg (len f))
by A198, MATRIX13:74;
then A210:
the_rank_of A9 <= len f
by FINSEQ_1:57;
then A211:
the_rank_of F5()
= len f
by A178, A200, XXREAL_0:1;
thus
for
i being
Nat st
i in dom A9 &
i > the_rank_of F5() holds
Line (
A9,
i)
= F3()
|-> (0. F1())
ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )take
f
;
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )thus
(
len f = the_rank_of A9 &
f is
one-to-one &
rng f c= Seg (width A9) & ( for
i,
j being
Nat st
i in dom f holds
S1[
f,
i,
j,
A9] ) )
by A4, A181, A183, A184, A200, A210, MATRIX_0:23, XXREAL_0:1;
verum end; end;
end;
then consider A9 being Matrix of F2(),F3(),F1(), B9 being Matrix of F2(),F4(),F1() such that
A214:
P1[A9,B9]
and
A215:
the_rank_of F5() = the_rank_of A9
and
A216:
for i being Nat st i in dom A9 & i > the_rank_of F5() holds
Line (A9,i) = F3() |-> (0. F1())
and
A217:
ex f being FinSequence of NAT st
( len f = the_rank_of A9 & f is one-to-one & rng f c= Seg (width A9) & ( for i, j being Nat st i in dom f holds
S1[f,i,j,A9] ) )
;
consider f being FinSequence of NAT such that
A218:
len f = the_rank_of A9
and
A219:
f is one-to-one
and
A220:
rng f c= Seg (width A9)
and
A221:
for i, j being Nat st i in dom f holds
S1[f,i,j,A9]
by A217;
not 0 in rng f
by A220;
then reconsider rngf = rng f as finite without_zero Subset of NAT by A220, MEASURE6:def 2, XBOOLE_1:1;
A222:
( F2() = 0 or F2() > 0 )
;
set S = Segm (A9,(Seg (card rngf)),rngf);
A223:
dom f = Seg (the_rank_of F5())
by A215, A218, FINSEQ_1:def 3;
take
A9
; ex B9 being Matrix of F2(),F4(),F1() ex N being finite without_zero Subset of NAT st
( N c= Seg F3() & the_rank_of F5() = the_rank_of A9 & the_rank_of F5() = card N & P1[A9,B9] & Segm (A9,(Seg (card N)),N) is diagonal & ( for i being Nat st i in Seg (card N) holds
A9 * (i,((Sgm N) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card N holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card N) & j in Seg (width A9) & j < (Sgm N) . i holds
A9 * (i,j) = 0. F1() ) )
take
B9
; ex N being finite without_zero Subset of NAT st
( N c= Seg F3() & the_rank_of F5() = the_rank_of A9 & the_rank_of F5() = card N & P1[A9,B9] & Segm (A9,(Seg (card N)),N) is diagonal & ( for i being Nat st i in Seg (card N) holds
A9 * (i,((Sgm N) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card N holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card N) & j in Seg (width A9) & j < (Sgm N) . i holds
A9 * (i,j) = 0. F1() ) )
take
rngf
; ( rngf c= Seg F3() & the_rank_of F5() = the_rank_of A9 & the_rank_of F5() = card rngf & P1[A9,B9] & Segm (A9,(Seg (card rngf)),rngf) is diagonal & ( for i being Nat st i in Seg (card rngf) holds
A9 * (i,((Sgm rngf) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1() ) )
len A9 = F2()
by MATRIX_0:def 2;
then
( width A9 = 0 or width A9 = F3() )
by A222, MATRIX_0:23, MATRIX_0:def 3;
then
Seg (width A9) c= Seg F3()
;
hence
( rngf c= Seg F3() & the_rank_of F5() = the_rank_of A9 )
by A215, A220; ( the_rank_of F5() = card rngf & P1[A9,B9] & Segm (A9,(Seg (card rngf)),rngf) is diagonal & ( for i being Nat st i in Seg (card rngf) holds
A9 * (i,((Sgm rngf) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1() ) )
dom f,rngf are_equipotent
by A219, WELLORD2:def 4;
hence A224: card rngf =
card (dom f)
by CARD_1:5
.=
card (Seg (the_rank_of F5()))
by A215, A218, FINSEQ_1:def 3
.=
the_rank_of F5()
by FINSEQ_1:57
;
( P1[A9,B9] & Segm (A9,(Seg (card rngf)),rngf) is diagonal & ( for i being Nat st i in Seg (card rngf) holds
A9 * (i,((Sgm rngf) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1() ) )
then
f is increasing
by SEQM_3:def 1;
then A227:
Sgm rngf = f
by Th6;
thus
P1[A9,B9]
by A214; ( Segm (A9,(Seg (card rngf)),rngf) is diagonal & ( for i being Nat st i in Seg (card rngf) holds
A9 * (i,((Sgm rngf) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1() ) )
A228:
card (Seg (card rngf)) = card rngf
by FINSEQ_1:57;
then A229:
Indices (Segm (A9,(Seg (card rngf)),rngf)) = [:(Seg (the_rank_of F5())),(Seg (the_rank_of F5())):]
by A224, MATRIX_0:24;
now for i, j being Nat st i in Seg (the_rank_of F5()) & j in Seg (the_rank_of F5()) & i <> j holds
(Segm (A9,(Seg (card rngf)),rngf)) * (i,j) = 0. F1()let i,
j be
Nat;
( i in Seg (the_rank_of F5()) & j in Seg (the_rank_of F5()) & i <> j implies (Segm (A9,(Seg (card rngf)),rngf)) * (i,j) = 0. F1() )assume that A230:
i in Seg (the_rank_of F5())
and A231:
j in Seg (the_rank_of F5())
and A232:
i <> j
;
(Segm (A9,(Seg (card rngf)),rngf)) * (i,j) = 0. F1()A233:
i in (dom f) \ {j}
by A223, A230, A232, ZFMISC_1:56;
A234:
(idseq (the_rank_of F5())) . i = i
by A230, FINSEQ_2:49;
[i,j] in Indices (Segm (A9,(Seg (card rngf)),rngf))
by A229, A230, A231, ZFMISC_1:87;
then (Segm (A9,(Seg (card rngf)),rngf)) * (
i,
j) =
A9 * (
((Sgm (Seg (the_rank_of F5()))) . i),
(f . j))
by A224, A227, MATRIX13:def 1
.=
A9 * (
i,
(f . j))
by A234, FINSEQ_3:48
.=
A9 * (
i,
(f /. j))
by A223, A231, PARTFUN1:def 6
;
hence
(Segm (A9,(Seg (card rngf)),rngf)) * (
i,
j)
= 0. F1()
by A221, A223, A231, A233;
verum end;
hence
Segm (A9,(Seg (card rngf)),rngf) is diagonal
by A224, A228, MATRIX_7:def 2; ( ( for i being Nat st i in Seg (card rngf) holds
A9 * (i,((Sgm rngf) /. i)) <> 0. F1() ) & ( for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1() ) )
thus
for i being Nat st i in Seg (card rngf) holds
A9 * (i,((Sgm rngf) /. i)) <> 0. F1()
by A221, A224, A227, A223; ( ( for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1()) ) & ( for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1() ) )
thus
for i being Nat st i in dom A9 & i > card rngf holds
Line (A9,i) = F3() |-> (0. F1())
by A216, A224; for i, j being Nat st i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i holds
A9 * (i,j) = 0. F1()
let i, j be Nat; ( i in Seg (card rngf) & j in Seg (width A9) & j < (Sgm rngf) . i implies A9 * (i,j) = 0. F1() )
assume that
A235:
i in Seg (card rngf)
and
A236:
j in Seg (width A9)
and
A237:
j < (Sgm rngf) . i
; A9 * (i,j) = 0. F1()
j < f /. i
by A224, A227, A223, A235, A237, PARTFUN1:def 6;
hence
A9 * (i,j) = 0. F1()
by A221, A224, A223, A235, A236; verum