let K be Field; for i, n being Nat st 1 <= i & i <= n holds
(Base_FinSeq (K,n,i)) . i = 1. K
let i, n be Nat; ( 1 <= i & i <= n implies (Base_FinSeq (K,n,i)) . i = 1. K )
assume A1:
( 1 <= i & i <= n )
; (Base_FinSeq (K,n,i)) . i = 1. K
A2:
len (n |-> (0. K)) = n
by CARD_1:def 7;
len (Replace ((n |-> (0. K)),i,(1. K))) =
len (n |-> (0. K))
by FINSEQ_7:5
.=
n
by CARD_1:def 7
;
hence (Base_FinSeq (K,n,i)) . i =
(Replace ((n |-> (0. K)),i,(1. K))) /. i
by A1, FINSEQ_4:15
.=
1. K
by A1, A2, FINSEQ_7:8
;
verum