let k, l, n be Nat; for K being comRing
for A being Matrix of n,K st l in dom (1. (K,n)) & k in dom (1. (K,n)) holds
(ILine ((1. (K,n)),l,k)) * A = ILine (A,l,k)
let K be comRing; for A being Matrix of n,K st l in dom (1. (K,n)) & k in dom (1. (K,n)) holds
(ILine ((1. (K,n)),l,k)) * A = ILine (A,l,k)
let A be Matrix of n,K; ( l in dom (1. (K,n)) & k in dom (1. (K,n)) implies (ILine ((1. (K,n)),l,k)) * A = ILine (A,l,k) )
assume that
A1:
l in dom (1. (K,n))
and
A2:
k in dom (1. (K,n))
; (ILine ((1. (K,n)),l,k)) * A = ILine (A,l,k)
set B = ILine ((1. (K,n)),l,k);
A3:
( len (ILine ((1. (K,n)),l,k)) = len (1. (K,n)) & len (ILine ((1. (K,n)),l,k)) = n )
by Def1, MATRIX_0:24;
then A4:
l in Seg n
by A1, FINSEQ_1:def 3;
A5:
k in Seg n
by A2, A3, FINSEQ_1:def 3;
A6:
width (ILine ((1. (K,n)),l,k)) = n
by MATRIX_0:24;
A7:
Indices ((ILine ((1. (K,n)),l,k)) * A) = [:(Seg n),(Seg n):]
by MATRIX_0:24;
A8:
width A = n
by MATRIX_0:24;
A9:
len A = n
by MATRIX_0:24;
A10:
width (ILine ((1. (K,n)),l,k)) = width (1. (K,n))
by Th1;
A11:
for i, j being Nat st j in Seg n & i in dom (1. (K,n)) & i <> l & i <> k holds
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
proof
let i,
j be
Nat;
( j in Seg n & i in dom (1. (K,n)) & i <> l & i <> k implies ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
assume that A12:
j in Seg n
and A13:
i in dom (1. (K,n))
;
( not i <> l or not i <> k or ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
A14:
i in Seg n
by A3, A13, FINSEQ_1:def 3;
then A15:
[i,i] in Indices (1. (K,n))
by A10, A6, A13, ZFMISC_1:87;
thus
(
i <> l &
i <> k implies
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j) )
verumproof
A16:
(
(Line ((1. (K,n)),i)) . i = 1_ K & ( for
t being
Nat st
t in dom (Line ((1. (K,n)),i)) &
t <> i holds
(Line ((1. (K,n)),i)) . t = 0. K ) )
proof
thus
(Line ((1. (K,n)),i)) . i = 1_ K
by A15, MATRIX_3:15;
for t being Nat st t in dom (Line ((1. (K,n)),i)) & t <> i holds
(Line ((1. (K,n)),i)) . t = 0. K
let t be
Nat;
( t in dom (Line ((1. (K,n)),i)) & t <> i implies (Line ((1. (K,n)),i)) . t = 0. K )
assume that A17:
t in dom (Line ((1. (K,n)),i))
and A18:
t <> i
;
(Line ((1. (K,n)),i)) . t = 0. K
t in Seg (len (Line ((1. (K,n)),i)))
by A17, FINSEQ_1:def 3;
then
t in Seg (width (1. (K,n)))
by MATRIX_0:def 7;
then
[i,t] in Indices (1. (K,n))
by A13, ZFMISC_1:87;
hence
(Line ((1. (K,n)),i)) . t = 0. K
by A18, MATRIX_3:15;
verum
end;
len (Col (A,j)) = len A
by MATRIX_0:def 8;
then A19:
i in dom (Col (A,j))
by A9, A14, FINSEQ_1:def 3;
A20:
dom (1. (K,n)) =
Seg (len (1. (K,n)))
by FINSEQ_1:def 3
.=
Seg (len A)
by A9, MATRIX_0:24
.=
dom A
by FINSEQ_1:def 3
;
len (Line ((1. (K,n)),i)) = width (1. (K,n))
by MATRIX_0:def 7;
then A21:
i in dom (Line ((1. (K,n)),i))
by A10, A6, A14, FINSEQ_1:def 3;
assume A22:
(
i <> l &
i <> k )
;
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
[i,j] in Indices ((ILine ((1. (K,n)),l,k)) * A)
by A7, A12, A14, ZFMISC_1:87;
then ((ILine ((1. (K,n)),l,k)) * A) * (
i,
j) =
(Line ((ILine ((1. (K,n)),l,k)),i)) "*" (Col (A,j))
by A6, A9, MATRIX_3:def 4
.=
Sum (mlt ((Line ((1. (K,n)),i)),(Col (A,j))))
by A1, A2, A13, A22, Th2
.=
(Col (A,j)) . i
by A21, A19, A16, MATRIX_3:17
.=
A * (
i,
j)
by A13, A20, MATRIX_0:def 8
.=
(ILine (A,l,k)) * (
i,
j)
by A8, A12, A13, A22, A20, Def1
;
hence
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j)
;
verum
end;
end;
A23:
l in Seg (width (1. (K,n)))
by A1, A10, A3, A6, FINSEQ_1:def 3;
then A24:
[l,l] in Indices (1. (K,n))
by A1, ZFMISC_1:87;
A25:
for i, j being Nat st j in Seg n & i in dom (1. (K,n)) & i = k holds
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
proof
let i,
j be
Nat;
( j in Seg n & i in dom (1. (K,n)) & i = k implies ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
assume that A26:
j in Seg n
and A27:
i in dom (1. (K,n))
;
( not i = k or ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
thus
(
i = k implies
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j) )
verumproof
A28:
(
(Line ((1. (K,n)),l)) . l = 1_ K & ( for
t being
Nat st
t in dom (Line ((1. (K,n)),l)) &
t <> l holds
(Line ((1. (K,n)),l)) . t = 0. K ) )
proof
thus
(Line ((1. (K,n)),l)) . l = 1_ K
by A24, MATRIX_3:15;
for t being Nat st t in dom (Line ((1. (K,n)),l)) & t <> l holds
(Line ((1. (K,n)),l)) . t = 0. K
let t be
Nat;
( t in dom (Line ((1. (K,n)),l)) & t <> l implies (Line ((1. (K,n)),l)) . t = 0. K )
assume that A29:
t in dom (Line ((1. (K,n)),l))
and A30:
t <> l
;
(Line ((1. (K,n)),l)) . t = 0. K
t in Seg (len (Line ((1. (K,n)),l)))
by A29, FINSEQ_1:def 3;
then
t in Seg (width (1. (K,n)))
by MATRIX_0:def 7;
then
[l,t] in Indices (1. (K,n))
by A1, ZFMISC_1:87;
hence
(Line ((1. (K,n)),l)) . t = 0. K
by A30, MATRIX_3:15;
verum
end;
len (Line ((1. (K,n)),l)) = width (1. (K,n))
by MATRIX_0:def 7;
then A31:
l in dom (Line ((1. (K,n)),l))
by A23, FINSEQ_1:def 3;
(
len (Col (A,j)) = len A &
l in Seg n )
by A1, A3, FINSEQ_1:def 3, MATRIX_0:def 8;
then A32:
l in dom (Col (A,j))
by A9, FINSEQ_1:def 3;
A33:
dom (1. (K,n)) =
Seg (len (1. (K,n)))
by FINSEQ_1:def 3
.=
Seg (len A)
by A9, MATRIX_0:24
.=
dom A
by FINSEQ_1:def 3
;
assume A34:
i = k
;
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
then
[i,j] in Indices ((ILine ((1. (K,n)),l,k)) * A)
by A5, A7, A26, ZFMISC_1:87;
then ((ILine ((1. (K,n)),l,k)) * A) * (
i,
j) =
(Line ((ILine ((1. (K,n)),l,k)),i)) "*" (Col (A,j))
by A6, A9, MATRIX_3:def 4
.=
Sum (mlt ((Line ((1. (K,n)),l)),(Col (A,j))))
by A1, A2, A34, Th2
.=
(Col (A,j)) . l
by A31, A32, A28, MATRIX_3:17
.=
A * (
l,
j)
by A1, A33, MATRIX_0:def 8
.=
(ILine (A,l,k)) * (
i,
j)
by A8, A26, A27, A34, A33, Def1
;
hence
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j)
;
verum
end;
end;
A35:
k in Seg (width (1. (K,n)))
by A2, A10, A3, A6, FINSEQ_1:def 3;
then A36:
[k,k] in Indices (1. (K,n))
by A2, ZFMISC_1:87;
A37:
for i, j being Nat st j in Seg n & i in dom (1. (K,n)) & i = l holds
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
proof
let i,
j be
Nat;
( j in Seg n & i in dom (1. (K,n)) & i = l implies ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
assume that A38:
j in Seg n
and A39:
i in dom (1. (K,n))
;
( not i = l or ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
thus
(
i = l implies
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j) )
verumproof
A40:
(
(Line ((1. (K,n)),k)) . k = 1_ K & ( for
t being
Nat st
t in dom (Line ((1. (K,n)),k)) &
t <> k holds
(Line ((1. (K,n)),k)) . t = 0. K ) )
proof
thus
(Line ((1. (K,n)),k)) . k = 1_ K
by A36, MATRIX_3:15;
for t being Nat st t in dom (Line ((1. (K,n)),k)) & t <> k holds
(Line ((1. (K,n)),k)) . t = 0. K
let t be
Nat;
( t in dom (Line ((1. (K,n)),k)) & t <> k implies (Line ((1. (K,n)),k)) . t = 0. K )
assume that A41:
t in dom (Line ((1. (K,n)),k))
and A42:
t <> k
;
(Line ((1. (K,n)),k)) . t = 0. K
t in Seg (len (Line ((1. (K,n)),k)))
by A41, FINSEQ_1:def 3;
then
t in Seg (width (1. (K,n)))
by MATRIX_0:def 7;
then
[k,t] in Indices (1. (K,n))
by A2, ZFMISC_1:87;
hence
(Line ((1. (K,n)),k)) . t = 0. K
by A42, MATRIX_3:15;
verum
end;
len (Line ((1. (K,n)),k)) = width (1. (K,n))
by MATRIX_0:def 7;
then A43:
k in dom (Line ((1. (K,n)),k))
by A35, FINSEQ_1:def 3;
(
len (Col (A,j)) = len A &
k in Seg n )
by A2, A3, FINSEQ_1:def 3, MATRIX_0:def 8;
then A44:
k in dom (Col (A,j))
by A9, FINSEQ_1:def 3;
A45:
dom (1. (K,n)) =
Seg (len (1. (K,n)))
by FINSEQ_1:def 3
.=
Seg (len A)
by A9, MATRIX_0:24
.=
dom A
by FINSEQ_1:def 3
;
assume A46:
i = l
;
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
then
[i,j] in Indices ((ILine ((1. (K,n)),l,k)) * A)
by A4, A7, A38, ZFMISC_1:87;
then ((ILine ((1. (K,n)),l,k)) * A) * (
i,
j) =
(Line ((ILine ((1. (K,n)),l,k)),i)) "*" (Col (A,j))
by A6, A9, MATRIX_3:def 4
.=
Sum (mlt ((Line ((1. (K,n)),k)),(Col (A,j))))
by A1, A2, A46, Th2
.=
(Col (A,j)) . k
by A43, A44, A40, MATRIX_3:17
.=
A * (
k,
j)
by A2, A45, MATRIX_0:def 8
.=
(ILine (A,l,k)) * (
i,
j)
by A8, A38, A39, A46, A45, Def1
;
hence
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j)
;
verum
end;
end;
A47:
for i, j being Nat st [i,j] in Indices ((ILine ((1. (K,n)),l,k)) * A) holds
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
proof
let i,
j be
Nat;
( [i,j] in Indices ((ILine ((1. (K,n)),l,k)) * A) implies ((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j) )
assume A48:
[i,j] in Indices ((ILine ((1. (K,n)),l,k)) * A)
;
((ILine ((1. (K,n)),l,k)) * A) * (i,j) = (ILine (A,l,k)) * (i,j)
dom (1. (K,n)) =
Seg (len (1. (K,n)))
by FINSEQ_1:def 3
.=
Seg n
by MATRIX_0:24
;
then A49:
i in dom (1. (K,n))
by A7, A48, ZFMISC_1:87;
A50:
j in Seg n
by A7, A48, ZFMISC_1:87;
then
(
i = l implies
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j) )
by A37, A49;
hence
((ILine ((1. (K,n)),l,k)) * A) * (
i,
j)
= (ILine (A,l,k)) * (
i,
j)
by A25, A11, A49, A50;
verum
end;
A51:
( len ((ILine ((1. (K,n)),l,k)) * A) = n & width ((ILine ((1. (K,n)),l,k)) * A) = n )
by MATRIX_0:24;
( len (ILine (A,l,k)) = len A & width (ILine (A,l,k)) = width A )
by Def1, Th1;
hence
(ILine ((1. (K,n)),l,k)) * A = ILine (A,l,k)
by A9, A8, A51, A47, MATRIX_0:21; verum