let R be Ring; for n being Nat
for x, y being Element of R holds (x * (1. (R,n))) * y = (x * y) * (1. (R,n))
let n be Nat; for x, y being Element of R holds (x * (1. (R,n))) * y = (x * y) * (1. (R,n))
let x, y be Element of R; (x * (1. (R,n))) * y = (x * y) * (1. (R,n))
set LHS = (x * (1. (R,n))) * y;
set RHS = (x * y) * (1. (R,n));
A1:
( len ((x * (1. (R,n))) * y) = len ((x * y) * (1. (R,n))) & width ((x * (1. (R,n))) * y) = width ((x * y) * (1. (R,n))) )
proof
thus len ((x * (1. (R,n))) * y) =
len (x * (1. (R,n)))
by MATRIX_3:def 6
.=
len (1. (R,n))
by MATRIX_3:def 5
.=
len ((x * y) * (1. (R,n)))
by MATRIX_3:def 5
;
width ((x * (1. (R,n))) * y) = width ((x * y) * (1. (R,n)))
thus width ((x * (1. (R,n))) * y) =
width (x * (1. (R,n)))
by MATRIX_3:def 6
.=
width (1. (R,n))
by MATRIX_3:def 5
.=
width ((x * y) * (1. (R,n)))
by MATRIX_3:def 5
;
verum
end;
for i, j being Nat st [i,j] in Indices ((x * (1. (R,n))) * y) holds
((x * (1. (R,n))) * y) * (i,j) = ((x * y) * (1. (R,n))) * (i,j)
proof
let i,
j be
Nat;
( [i,j] in Indices ((x * (1. (R,n))) * y) implies ((x * (1. (R,n))) * y) * (i,j) = ((x * y) * (1. (R,n))) * (i,j) )
assume A2:
[i,j] in Indices ((x * (1. (R,n))) * y)
;
((x * (1. (R,n))) * y) * (i,j) = ((x * y) * (1. (R,n))) * (i,j)
A3:
(
[i,j] in Indices (x * (1. (R,n))) &
[i,j] in Indices (1. (R,n)) )
proof
A4:
Indices ((x * (1. (R,n))) * y) =
[:(dom ((x * (1. (R,n))) * y)),(Seg (width ((x * (1. (R,n))) * y))):]
by MATRIX_0:def 4
.=
[:(Seg (len ((x * (1. (R,n))) * y))),(Seg (width ((x * (1. (R,n))) * y))):]
by FINSEQ_1:def 3
.=
[:(Seg (len (x * (1. (R,n))))),(Seg (width ((x * (1. (R,n))) * y))):]
by MATRIX_3:def 6
.=
[:(Seg (len (x * (1. (R,n))))),(Seg (width (x * (1. (R,n))))):]
by MATRIX_3:def 6
;
then
Indices ((x * (1. (R,n))) * y) = [:(dom (x * (1. (R,n)))),(Seg (width (x * (1. (R,n))))):]
by FINSEQ_1:def 3;
hence
[i,j] in Indices (x * (1. (R,n)))
by A2, MATRIX_0:def 4;
[i,j] in Indices (1. (R,n))
Indices ((x * (1. (R,n))) * y) =
[:(Seg (len (1. (R,n)))),(Seg (width (x * (1. (R,n))))):]
by A4, MATRIX_3:def 5
.=
[:(Seg (len (1. (R,n)))),(Seg (width (1. (R,n)))):]
by MATRIX_3:def 5
.=
[:(dom (1. (R,n))),(Seg (width (1. (R,n)))):]
by FINSEQ_1:def 3
.=
Indices (1. (R,n))
by MATRIX_0:def 4
;
hence
[i,j] in Indices (1. (R,n))
by A2;
verum
end;
per cases
( i = j or i <> j )
;
suppose A5:
i = j
;
((x * (1. (R,n))) * y) * (i,j) = ((x * y) * (1. (R,n))) * (i,j)thus ((x * (1. (R,n))) * y) * (
i,
j) =
((x * (1. (R,n))) * (i,j)) * y
by A3, MATRIX_3:def 6
.=
(x * ((1. (R,n)) * (i,j))) * y
by A3, MATRIX_3:def 5
.=
(x * (1. R)) * y
by A3, A5, MATRIX_1:def 3
.=
(x * y) * (1. R)
.=
(x * y) * ((1. (R,n)) * (i,j))
by A3, A5, MATRIX_1:def 3
.=
((x * y) * (1. (R,n))) * (
i,
j)
by A3, MATRIX_3:def 5
;
verum end; suppose A6:
i <> j
;
((x * (1. (R,n))) * y) * (i,j) = ((x * y) * (1. (R,n))) * (i,j)thus ((x * (1. (R,n))) * y) * (
i,
j) =
((x * (1. (R,n))) * (i,j)) * y
by A3, MATRIX_3:def 6
.=
(x * ((1. (R,n)) * (i,j))) * y
by A3, MATRIX_3:def 5
.=
(x * (0. R)) * y
by A3, A6, MATRIX_1:def 3
.=
(x * y) * (0. R)
.=
(x * y) * ((1. (R,n)) * (i,j))
by A3, A6, MATRIX_1:def 3
.=
((x * y) * (1. (R,n))) * (
i,
j)
by A3, MATRIX_3:def 5
;
verum end; end;
end;
hence
(x * (1. (R,n))) * y = (x * y) * (1. (R,n))
by A1, MATRIX_0:21; verum