let R be Ring; for n being Nat
for S being Subring of R
for b being Matrix of n,S
for B being Matrix of n,R st b = B holds
for j being Nat st j in Seg (width b) holds
Col (b,j) = Col (B,j)
let n be Nat; for S being Subring of R
for b being Matrix of n,S
for B being Matrix of n,R st b = B holds
for j being Nat st j in Seg (width b) holds
Col (b,j) = Col (B,j)
let S be Subring of R; for b being Matrix of n,S
for B being Matrix of n,R st b = B holds
for j being Nat st j in Seg (width b) holds
Col (b,j) = Col (B,j)
let b be Matrix of n,S; for B being Matrix of n,R st b = B holds
for j being Nat st j in Seg (width b) holds
Col (b,j) = Col (B,j)
let B be Matrix of n,R; ( b = B implies for j being Nat st j in Seg (width b) holds
Col (b,j) = Col (B,j) )
assume A1:
b = B
; for j being Nat st j in Seg (width b) holds
Col (b,j) = Col (B,j)
let j be Nat; ( j in Seg (width b) implies Col (b,j) = Col (B,j) )
assume A2:
j in Seg (width b)
; Col (b,j) = Col (B,j)
A3: dom (Col (b,j)) =
Seg (len (Col (b,j)))
by FINSEQ_1:def 3
.=
Seg (len b)
by MATRIX_0:def 8
;
A4: dom (Col (B,j)) =
Seg (len (Col (B,j)))
by FINSEQ_1:def 3
.=
Seg (len B)
by MATRIX_0:def 8
;
for i being Nat st i in dom (Col (b,j)) holds
(Col (b,j)) . i = (Col (B,j)) . i
proof
let i be
Nat;
( i in dom (Col (b,j)) implies (Col (b,j)) . i = (Col (B,j)) . i )
assume
i in dom (Col (b,j))
;
(Col (b,j)) . i = (Col (B,j)) . i
then A5:
i in dom b
by A3, FINSEQ_1:def 3;
then
[i,j] in [:(dom b),(Seg (width b)):]
by A2, ZFMISC_1:87;
then A6:
[i,j] in Indices b
by MATRIX_0:def 4;
Indices b =
[:(Seg n),(Seg n):]
by MATRIX_0:24
.=
Indices B
by MATRIX_0:24
;
then
[i,j] in [:(dom B),(Seg (width B)):]
by A6, MATRIX_0:def 4;
then A7:
(
i in dom B &
j in Seg (width B) )
by ZFMISC_1:87;
thus (Col (b,j)) . i =
b * (
i,
j)
by A5, MATRIX_0:def 8
.=
B * (
i,
j)
by A1, A6, Th83
.=
(Col (B,j)) . i
by A7, MATRIX_0:def 8
;
verum
end;
hence
Col (b,j) = Col (B,j)
by A1, A3, A4, FINSEQ_1:13; verum