let R be Ring; for x, y being Element of R
for M1, M2 being Matrix of 1,R st M1 = <*<*x*>*> & M2 = <*<*y*>*> holds
M1 + M2 = <*<*(x + y)*>*>
let x, y be Element of R; for M1, M2 being Matrix of 1,R st M1 = <*<*x*>*> & M2 = <*<*y*>*> holds
M1 + M2 = <*<*(x + y)*>*>
let M1, M2 be Matrix of 1,R; ( M1 = <*<*x*>*> & M2 = <*<*y*>*> implies M1 + M2 = <*<*(x + y)*>*> )
assume A1:
M1 = <*<*x*>*>
; ( not M2 = <*<*y*>*> or M1 + M2 = <*<*(x + y)*>*> )
assume A2:
M2 = <*<*y*>*>
; M1 + M2 = <*<*(x + y)*>*>
A3:
( Indices (M1 + M2) = [:(Seg 1),(Seg 1):] & 1 in Seg 1 )
by FINSEQ_1:2, MATRIX_0:24, TARSKI:def 1;
for i, j being Nat st [i,j] in Indices (M1 + M2) holds
(M1 + M2) * (i,j) = <*<*(x + y)*>*> * (i,j)
proof
let i,
j be
Nat;
( [i,j] in Indices (M1 + M2) implies (M1 + M2) * (i,j) = <*<*(x + y)*>*> * (i,j) )
assume A4:
[i,j] in Indices (M1 + M2)
;
(M1 + M2) * (i,j) = <*<*(x + y)*>*> * (i,j)
then
(
i in Seg 1 &
j in Seg 1 )
by A3, ZFMISC_1:87;
then A5:
(
i = 1 &
j = 1 )
by FINSEQ_1:2, TARSKI:def 1;
[i,j] in Indices M1
by A3, A4, MATRIX_0:24;
hence (M1 + M2) * (
i,
j) =
(M1 * (i,j)) + (M2 * (i,j))
by MATRIX_1:def 8
.=
x + (<*<*y*>*> * (1,1))
by A1, A2, A5, MATRIX_0:49
.=
x + y
by MATRIX_0:49
.=
<*<*(x + y)*>*> * (
i,
j)
by A5, MATRIX_0:49
;
verum
end;
hence
M1 + M2 = <*<*(x + y)*>*>
by MATRIX_0:27; verum