let f, f1 be FinSequence of LTLB_WFF ; for g being Function of LTLB_WFF,BOOLEAN holds (VAL g) . ((con (f ^ f1)) /. (len (con (f ^ f1)))) = ((VAL g) . ((con f) /. (len (con f)))) '&' ((VAL g) . ((con f1) /. (len (con f1))))
let g be Function of LTLB_WFF,BOOLEAN; (VAL g) . ((con (f ^ f1)) /. (len (con (f ^ f1)))) = ((VAL g) . ((con f) /. (len (con f)))) '&' ((VAL g) . ((con f1) /. (len (con f1))))
set fp = (f ^ f1) | (len f);
set fk = (f ^ f1) /^ (len f);
set v = VAL g;
A1:
(f ^ f1) /^ (len f) = f1
by FINSEQ_5:37;
A2:
for n being Element of NAT
for f being FinSequence of LTLB_WFF holds (VAL g) . H2(f) = ((VAL g) . H2(f | n)) '&' ((VAL g) . H2(f /^ n))
proof
let n be
Element of
NAT ;
for f being FinSequence of LTLB_WFF holds (VAL g) . H2(f) = ((VAL g) . H2(f | n)) '&' ((VAL g) . H2(f /^ n))let f be
FinSequence of
LTLB_WFF ;
(VAL g) . H2(f) = ((VAL g) . H2(f | n)) '&' ((VAL g) . H2(f /^ n))
defpred S1[
Nat]
means (VAL g) . H2(
f)
= ((VAL g) . H2(f | $1)) '&' ((VAL g) . H2(f /^ $1));
len (f | 0) = 0
;
then A3:
con (f | 0) = <*TVERUM*>
by Def2;
then
len (con (f | 0)) = 1
by FINSEQ_1:39;
then A4:
(con (f | 0)) /. (len (con (f | 0))) = TVERUM
by FINSEQ_4:16, A3;
A5:
for
f being
FinSequence of
LTLB_WFF for
g being
Function of
LTLB_WFF,
BOOLEAN holds
(VAL g) . H2(
f)
= ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))
proof
let f be
FinSequence of
LTLB_WFF ;
for g being Function of LTLB_WFF,BOOLEAN holds (VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))let g be
Function of
LTLB_WFF,
BOOLEAN;
(VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))
defpred S2[
Nat]
means for
f being
FinSequence of
LTLB_WFF st
len f = $1 holds
(VAL g) . H2(
f)
= ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1));
A6:
len f = len f
;
A7:
now for n being Nat st S2[n] holds
S2[n + 1]let n be
Nat;
( S2[n] implies S2[n + 1] )assume A8:
S2[
n]
;
S2[n + 1]thus
S2[
n + 1]
verumproof
let f be
FinSequence of
LTLB_WFF ;
( len f = n + 1 implies (VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1)) )
set v =
VAL g;
set fp1 =
f | 1;
set fk1 =
f /^ 1;
set fn =
f | n;
set fn1 =
f | (n + 1);
assume A9:
len f = n + 1
;
(VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))
then A10:
n < len f
by NAT_1:13;
A11:
len (con f) = n + 1
by Def2, A9;
A12:
1
<= len f
by A9, NAT_1:25;
then A13:
len (f /^ 1) =
(len f) - 1
by RFINSEQ:def 1
.=
n
by A9
;
len (f | 1) = 1
by A12, FINSEQ_1:59;
then A14:
len (con (f | 1)) = 1
by Def2;
A15:
n <= len f
by A9, NAT_1:13;
then A16:
len (f | n) = n
by FINSEQ_1:59;
A17:
len (f | (n + 1)) = n + 1
by FINSEQ_1:59, A9;
then A18:
1
<= len (f | (n + 1))
by NAT_1:11;
A19:
1
<= n + 1
by NAT_1:11;
then A20:
len ((f | (n + 1)) /^ 1) =
(len (f | (n + 1))) - 1
by A17, RFINSEQ:def 1
.=
n
by A17
;
per cases
( n = 0 or n > 0 )
;
suppose A23:
n > 0
;
(VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))then A24:
1
<= len (f | n)
by NAT_1:25, A16;
A25:
1
<= n
by A23, NAT_1:25;
len (con (f | n)) = len (f | n)
by A23, A16, Def2;
then
(con f) /. n = H2(
f | n)
by A16, Th13, A25, A15;
then
H2(
f)
= H2(
f | n)
'&&' (f /. (n + 1))
by Th7, A25, A10, A11;
then A26:
(VAL g) . H2(
f) =
((VAL g) . H2(f | n)) '&' ((VAL g) . (f /. (n + 1)))
by LTLAXIO1:31
.=
(((VAL g) . H2((f | n) | 1)) '&' ((VAL g) . H2((f | n) /^ 1))) '&' ((VAL g) . (f /. (n + 1)))
by A8, A16
.=
(((VAL g) . ((con (f | 1)) /. (len (con ((f | n) | 1))))) '&' ((VAL g) . H2((f | n) /^ 1))) '&' ((VAL g) . (f /. (n + 1)))
by A25, FINSEQ_1:82
.=
(((VAL g) . H2(f | 1)) '&' ((VAL g) . H2((f | n) /^ 1))) '&' ((VAL g) . (f /. (n + 1)))
by A25, FINSEQ_1:82
.=
((VAL g) . H2(f | 1)) '&' (((VAL g) . H2((f | n) /^ 1)) '&' ((VAL g) . (f /. (n + 1))))
.=
((VAL g) . H2(f | 1)) '&' ((VAL g) . (H2((f | n) /^ 1) '&&' (f /. (n + 1))))
by LTLAXIO1:31
;
per cases
( n = 1 or 1 < n )
by A23, NAT_1:25;
suppose A27:
n = 1
;
(VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))then A28:
1
in dom (f /^ 1)
by A13, FINSEQ_3:25;
A29:
len (con (f /^ 1)) = 1
by Def2, A13, A27;
thus (VAL g) . H2(
f) =
(VAL g) . (((con f) /. 1) '&&' (f /. (1 + 1)))
by Th7, A27, A9, A11
.=
(VAL g) . (((con (f | 1)) /. 1) '&&' (f /. (1 + 1)))
by Th13, A27, A9
.=
((VAL g) . ((con (f | 1)) /. 1)) '&' ((VAL g) . (f /. (1 + 1)))
by LTLAXIO1:31
.=
((VAL g) . ((con (f | 1)) /. 1)) '&' ((VAL g) . ((f /^ 1) /. 1))
by FINSEQ_5:27, A28
.=
((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))
by A14, A29, Th6, A27, A13
;
verum end; suppose A30:
1
< n
;
(VAL g) . H2(f) = ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))A31:
(f | (n + 1)) /^ 1
= (f /^ 1) | n
proof
set f1 =
(f /^ 1) | n;
set g =
(f | (n + 1)) /^ 1;
A32:
len ((f /^ 1) | n) = len ((f | (n + 1)) /^ 1)
by A20, FINSEQ_1:59, A13;
now for x being Nat st x in dom ((f /^ 1) | n) holds
((f /^ 1) | n) . x = ((f | (n + 1)) /^ 1) . xlet x be
Nat;
( x in dom ((f /^ 1) | n) implies ((f /^ 1) | n) . x = ((f | (n + 1)) /^ 1) . x )A33:
dom ((f /^ 1) | n) c= dom (f /^ 1)
by FINSEQ_5:18;
assume A34:
x in dom ((f /^ 1) | n)
;
((f /^ 1) | n) . x = ((f | (n + 1)) /^ 1) . xthen A35:
x in dom ((f | (n + 1)) /^ 1)
by FINSEQ_3:29, A32;
x <= len ((f /^ 1) | n)
by A34, FINSEQ_3:25;
then A36:
x <= n
by FINSEQ_1:59, A13;
hence ((f /^ 1) | n) . x =
(f /^ 1) . x
by FINSEQ_3:112
.=
f . (x + 1)
by RFINSEQ:def 1, A33, A34, A12
.=
(f | (n + 1)) . (x + 1)
by FINSEQ_3:112, A36, XREAL_1:6
.=
((f | (n + 1)) /^ 1) . x
by RFINSEQ:def 1, A18, A35
;
verum end;
hence
(f | (n + 1)) /^ 1
= (f /^ 1) | n
by FINSEQ_2:9, A32;
verum
end; A37:
n + (- 1) > 1
+ (- 1)
by A30, XREAL_1:8;
then A38:
(n -' 1) + 1 =
(n - 1) + 1
by XREAL_0:def 2
.=
n
;
len (con (f /^ 1)) = len (f /^ 1)
by A13, A30, Def2;
then A39:
len (con (f /^ 1)) =
(len f) -' 1
by RFINSEQ:29
.=
n
by NAT_D:34, A9
;
A40:
n in dom ((f | (n + 1)) /^ 1)
by FINSEQ_3:25, A30, A20;
A41:
n - 1
> 0
by A37;
then
n -' 1
> 0
by XREAL_0:def 2;
then A42:
1
<= n -' 1
by NAT_1:25;
A43:
f /. (n + 1) =
f . (n + 1)
by A19, A9, FINSEQ_4:15
.=
(f | (n + 1)) . (n + 1)
by FINSEQ_3:112
.=
((f | (n + 1)) /^ 1) . n
by RFINSEQ:def 1, A40, A19, A17
.=
((f | (n + 1)) /^ 1) /. ((n -' 1) + 1)
by A38, PARTFUN1:def 6, A40
;
A44:
(- 1) + n < n
by XREAL_1:30;
then A45:
n -' 1
< len ((f | (n + 1)) /^ 1)
by A20, XREAL_0:def 2, A41;
A46:
len ((f | n) /^ 1) = n - 1
by RFINSEQ:def 1, A24, A16;
then A47:
len (con ((f | n) /^ 1)) =
len ((f | n) /^ 1)
by A37, Def2
.=
n -' 1
by XREAL_0:def 2, A46
;
then
len (con ((f | n) /^ 1)) = n - 1
by A46, XREAL_0:def 2;
then A48:
1
<= len (con ((f | n) /^ 1))
by A37, NAT_1:25;
A49:
len ((f | n) /^ 1) = n -' 1
by XREAL_0:def 2, A46;
A50:
((f | (n + 1)) /^ 1) | (n -' 1) = (f | n) /^ 1
proof
set f1 =
((f | (n + 1)) /^ 1) | (n -' 1);
set g =
(f | n) /^ 1;
A51:
len (((f | (n + 1)) /^ 1) | (n -' 1)) = len ((f | n) /^ 1)
by A49, FINSEQ_1:59, A45;
now for x being Nat st x in dom (((f | (n + 1)) /^ 1) | (n -' 1)) holds
(((f | (n + 1)) /^ 1) | (n -' 1)) . x = ((f | n) /^ 1) . xA52:
dom (((f | (n + 1)) /^ 1) | (n -' 1)) c= dom ((f | (n + 1)) /^ 1)
by FINSEQ_5:18;
let x be
Nat;
( x in dom (((f | (n + 1)) /^ 1) | (n -' 1)) implies (((f | (n + 1)) /^ 1) | (n -' 1)) . x = ((f | n) /^ 1) . x )A53:
n <= n + 1
by XREAL_1:31;
assume A54:
x in dom (((f | (n + 1)) /^ 1) | (n -' 1))
;
(((f | (n + 1)) /^ 1) | (n -' 1)) . x = ((f | n) /^ 1) . xthen A55:
x in dom ((f | n) /^ 1)
by FINSEQ_3:29, A51;
x <= len (((f | (n + 1)) /^ 1) | (n -' 1))
by A54, FINSEQ_3:25;
then A56:
x <= n -' 1
by FINSEQ_1:59, A45;
then A57:
x + 1
<= n
by XREAL_1:6, A38;
thus (((f | (n + 1)) /^ 1) | (n -' 1)) . x =
((f | (n + 1)) /^ 1) . x
by FINSEQ_3:112, A56
.=
(f | (n + 1)) . (x + 1)
by RFINSEQ:def 1, A52, A54, A18
.=
f . (x + 1)
by FINSEQ_3:112, A53, XXREAL_0:2, A57
.=
(f | n) . (x + 1)
by FINSEQ_3:112, A56, XREAL_1:6, A38
.=
((f | n) /^ 1) . x
by RFINSEQ:def 1, A25, A16, A55
;
verum end;
hence
((f | (n + 1)) /^ 1) | (n -' 1) = (f | n) /^ 1
by FINSEQ_2:9, A51;
verum
end;
len (con ((f | n) /^ 1)) = len ((f | n) /^ 1)
by A46, A37, Def2;
then H2(
(f | n) /^ 1)
'&&' (f /. (n + 1)) =
((con ((f | (n + 1)) /^ 1)) /. (n -' 1)) '&&' (f /. (n + 1))
by A47, Th13, A48, A46, A44, A20, A50
.=
(con ((f | (n + 1)) /^ 1)) /. ((n -' 1) + 1)
by Th7, A45, A42, A43
.=
(con (f /^ 1)) /. (len (con (f /^ 1)))
by A39, A13, A25, Th13, A31, A38
;
hence
(VAL g) . H2(
f)
= ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))
by A26;
verum end; end; end; end;
end; end;
A58:
S2[
0 ]
for
n being
Nat holds
S2[
n]
from NAT_1:sch 2(A58, A7);
hence
(VAL g) . H2(
f)
= ((VAL g) . H2(f | 1)) '&' ((VAL g) . H2(f /^ 1))
by A6;
verum
end;
A61:
for
n being
Nat st
S1[
n] holds
S1[
n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume A62:
S1[
n]
;
S1[n + 1]
set v =
VAL g;
set fe =
f /^ n;
set fs1 =
f | (n + 1);
set fs =
f | n;
set fe1 =
f /^ (n + 1);
per cases
( len f = 0 or len f > 0 )
;
suppose A66:
len f > 0
;
S1[n + 1]then
len f >= 1
by NAT_1:25;
then A67:
len (f | 1) = 1
by FINSEQ_1:59;
then A68:
1
in dom (f | 1)
by FINSEQ_3:25;
A69:
len (f | (n + 1)) > 0
by A66, Th1;
then
len (f | (n + 1)) >= 1
by NAT_1:25;
then A70:
1
in dom (f | (n + 1))
by FINSEQ_3:25;
A71:
len (con (f | 1)) = 1
by A67, Def2;
A72:
1
<= n + 1
by XREAL_1:31;
per cases
( len (f | (n + 1)) = 1 or len (f | (n + 1)) > 1 )
by A69, NAT_1:25;
suppose A77:
len (f | (n + 1)) > 1
;
S1[n + 1]per cases
( n + 1 > len f or n + 1 <= len f )
;
suppose A80:
n + 1
<= len f
;
S1[n + 1]then A81:
len (f | (n + 1)) = n + 1
by FINSEQ_1:59;
then A82:
n + 1
in dom (f | (n + 1))
by FINSEQ_3:25, A72;
A83:
(
n + 1
= len (con (f | (n + 1))) &
n < len (f | (n + 1)) )
by A81, Def2, XREAL_1:145;
A84:
(n + 1) + (- n) <= (len f) + (- n)
by A80, XREAL_1:6;
A85:
len (f /^ n) =
(len f) -' n
by RFINSEQ:29
.=
(len f) - n
by XREAL_0:def 2, A84
;
then A86:
len ((f /^ n) | 1) = 1
by A84, FINSEQ_1:59;
then A87:
1
in dom ((f /^ n) | 1)
by FINSEQ_3:25;
A88:
1
in dom (f /^ n)
by A85, A84, FINSEQ_3:25;
len (con ((f /^ n) | 1)) = 1
by A86, Def2;
then A89:
H2(
(f /^ n) | 1) =
((f /^ n) | 1) /. 1
by Th6, A86
.=
(f /^ n) /. 1
by A87, FINSEQ_4:70
.=
f /. (n + 1)
by FINSEQ_5:27, A88
.=
(f | (n + 1)) /. (n + 1)
by FINSEQ_4:70, A82
;
A90:
(f /^ n) /^ 1
= f /^ (n + 1)
by FINSEQ_6:81;
A91:
(n + 1) + (- 1) > 1
+ (- 1)
by A77, A81, XREAL_1:8;
then A92:
n >= 1
by NAT_1:25;
A93:
n <= n + 1
by XREAL_1:31;
then
len (f | n) = n
by XXREAL_0:2, A80, FINSEQ_1:59;
then A94:
len (con (f | n)) = n
by Def2, A91;
A95:
H2(
f | n) =
(con ((f | (n + 1)) | n)) /. (len (con (f | n)))
by FINSEQ_5:77, A93
.=
(con (f | (n + 1))) /. n
by A94, Th13, A93, A81, A92
;
A96:
1
<= n
by NAT_1:25, A91;
thus (VAL g) . H2(
f) =
((VAL g) . H2(f | n)) '&' (((VAL g) . H2((f /^ n) | 1)) '&' ((VAL g) . H2((f /^ n) /^ 1)))
by A5, A62
.=
(((VAL g) . H2(f | n)) '&' ((VAL g) . H2((f /^ n) | 1))) '&' ((VAL g) . H2(f /^ (n + 1)))
by A90
.=
((VAL g) . (H2(f | n) '&&' H2((f /^ n) | 1))) '&' ((VAL g) . H2(f /^ (n + 1)))
by LTLAXIO1:31
.=
((VAL g) . H2(f | (n + 1))) '&' ((VAL g) . H2(f /^ (n + 1)))
by A83, Th7, A96, A95, A89
;
verum end; end; end; end; end; end;
end;
f /^ 0 = f
by FINSEQ_5:28;
then (VAL g) . H2(
f) =
TRUE '&' ((VAL g) . H2(f /^ 0))
.=
((VAL g) . H2(f | 0)) '&' ((VAL g) . H2(f /^ 0))
by A4, Th4
;
then A97:
S1[
0 ]
;
for
n being
Nat holds
S1[
n]
from NAT_1:sch 2(A97, A61);
hence
(VAL g) . H2(
f)
= ((VAL g) . H2(f | n)) '&' ((VAL g) . H2(f /^ n))
;
verum
end;
Seg (len f) c= dom f
by FINSEQ_1:def 3;
then (f ^ f1) | (len f) =
f | (len f)
by FINSEQ_6:11
.=
f
by FINSEQ_1:58
;
hence
(VAL g) . H2(f ^ f1) = ((VAL g) . H2(f)) '&' ((VAL g) . H2(f1))
by A1, A2; verum