let X be non empty set ; for S being SigmaField of X
for M being sigma_Measure of S
for f being PartFunc of X,REAL st f in L1_Functions M & Integral (M,(abs f)) = 0 holds
f a.e.= X --> 0,M
let S be SigmaField of X; for M being sigma_Measure of S
for f being PartFunc of X,REAL st f in L1_Functions M & Integral (M,(abs f)) = 0 holds
f a.e.= X --> 0,M
let M be sigma_Measure of S; for f being PartFunc of X,REAL st f in L1_Functions M & Integral (M,(abs f)) = 0 holds
f a.e.= X --> 0,M
let f be PartFunc of X,REAL; ( f in L1_Functions M & Integral (M,(abs f)) = 0 implies f a.e.= X --> 0,M )
assume that
A1:
f in L1_Functions M
and
A2:
Integral (M,(abs f)) = 0
; f a.e.= X --> 0,M
set g = X --> 0;
defpred S1[ Element of NAT , set ] means ( $2 = great_eq_dom ((abs f),(1 / ($1 + 1))) & M . $2 = 0 );
consider f1 being PartFunc of X,REAL such that
A3:
f = f1
and
A4:
ex ND being Element of S st
( M . ND = 0 & dom f1 = ND ` & f1 is_integrable_on M )
by A1;
A5:
abs f is_integrable_on M
by A3, A4, Th44;
then
R_EAL (abs f) is_integrable_on M
;
then consider E being Element of S such that
A6:
E = dom (R_EAL (abs f))
and
A7:
R_EAL (abs f) is E -measurable
;
A8:
abs f is E -measurable
by A7;
then A9:
abs f is nonnegative
by MESFUNC6:52;
A10:
now for n being Element of NAT ex B being Element of S st S1[n,B]let n be
Element of
NAT ;
ex B being Element of S st S1[n,B]reconsider r = 1
/ (n + 1) as
Element of
REAL by XREAL_0:def 1;
reconsider Br =
E /\ (great_eq_dom ((abs f),r)) as
Element of
S by A6, A8, MESFUNC6:13;
set g =
Br --> r;
A11:
dom (Br --> r) = Br
by FUNCT_2:def 1;
A12:
for
x being
set st
x in dom (Br --> r) holds
(Br --> r) . x = r
by FUNCOP_1:7;
reconsider g =
Br --> r as
PartFunc of
X,
REAL by RELSET_1:7;
A13:
(abs f) | Br is_integrable_on M
by A5, MESFUNC6:91;
for
x being
object st
x in dom g holds
0 <= g . x
by A12;
then
g is
nonnegative
by MESFUNC6:52;
then A14:
0 <= Integral (
M,
g)
by A11, A12, Th52, MESFUNC6:84;
A15:
dom (abs g) = dom g
by VALUED_1:def 11;
A18:
dom ((abs f) | Br) =
(dom (abs f)) /\ Br
by RELAT_1:61
.=
Br
by A6, XBOOLE_1:17, XBOOLE_1:28
;
then A19:
dom g = dom ((abs f) | Br)
by FUNCT_2:def 1;
g is
Br -measurable
by A11, A12, Th52;
then
Integral (
M,
(abs g))
<= Integral (
M,
((abs f) | Br))
by A11, A18, A13, A20, MESFUNC6:96;
then A23:
Integral (
M,
g)
<= Integral (
M,
((abs f) | Br))
by A15, A16, PARTFUN1:5;
A24:
for
x being
object st
x in dom g holds
g . x = r
by A11, FUNCOP_1:7;
reconsider rr =
r as
R_eal by XXREAL_0:def 1;
AAA:
1
/ (n + 1) = 1
/ (n + 1)
;
Integral (
M,
((abs f) | Br))
<= Integral (
M,
((abs f) | E))
by A6, A8, A9, MESFUNC6:87, XBOOLE_1:17;
then
Integral (
M,
g)
= 0
by A2, A6, A23, A14, RELAT_1:68;
then
rr * (M . Br) = 0
by A11, A24, MESFUNC6:97;
then A25:
M . Br = 0
by AAA;
for
x being
object st
x in great_eq_dom (
(abs f),
r) holds
x in dom (abs f)
by MESFUNC6:6;
then
great_eq_dom (
(abs f),
r)
c= E
by A6;
hence
ex
B being
Element of
S st
S1[
n,
B]
by A25, XBOOLE_1:28;
verum end;
consider F being sequence of S such that
A26:
for n being Element of NAT holds S1[n,F . n]
from FUNCT_2:sch 3(A10);
then A35:
union (rng F) c= { x where x is Element of X : ( x in dom f & f . x <> 0 ) }
;
consider ND being Element of S such that
A36:
M . ND = 0
and
A37:
dom f1 = ND `
and
f1 is_integrable_on M
by A4;
reconsider EQ = (union (rng F)) \/ ND as Element of S ;
A38:
EQ ` = (ND `) /\ ((union (rng F)) `)
by XBOOLE_1:53;
then A39:
EQ ` c= dom f
by A3, A37, XBOOLE_1:17;
dom (X --> 0) = X
by FUNCOP_1:13;
then A40:
dom ((X --> 0) | (EQ `)) = EQ `
by RELAT_1:62;
A41:
dom (f | (EQ `)) = EQ `
by A3, A37, A38, RELAT_1:62, XBOOLE_1:17;
then
{ x where x is Element of X : ( x in dom f & f . x <> 0 ) } c= union (rng F)
;
then A48:
{ x where x is Element of X : ( x in dom f & f . x <> 0 ) } = union (rng F)
by A35, XBOOLE_0:def 10;
then A52:
f | (EQ `) = (X --> 0) | (EQ `)
by A39, A40, FUNCT_1:2, RELAT_1:62;
then A55:
union (rng F) is measure_zero of M
by MEASURE2:14;
ND is measure_zero of M
by A36, MEASURE1:def 7;
then
EQ is measure_zero of M
by A55, MEASURE1:37;
then
M . EQ = 0
by MEASURE1:def 7;
hence
f a.e.= X --> 0,M
by A52; verum