let a, b be Element of ExWALattice; :: thesis: ( a = 2 & b = 3 implies a "/\" b = 2 )
reconsider aa = a, bb = b as Element of {0,1,2,3,4} ;
assume A1: ( a = 2 & b = 3 ) ; :: thesis: a "/\" b = 2
a "/\" b = aa ex1234"/\" bb by EXNDef
.= min (aa,bb) by A1, ExMeetDef
.= aa by A1, XXREAL_0:def 9 ;
hence a "/\" b = 2 by A1; :: thesis: verum