set j = perm . i;
set P = Permutations n;
set p = perm;
set n1 = n + 1;
reconsider N = n as Element of NAT by ORDINAL1:def 12;
reconsider p9 = perm as Permutation of (Seg (n + 1)) by MATRIX_1:def 12;
A2:
dom p9 = Seg (n + 1)
by FUNCT_2:52;
defpred S1[ object , object ] means for k being Nat st k in Seg n & $1 = k holds
( ( k < i implies ( ( perm . k < perm . i implies $2 = perm . k ) & ( perm . k >= perm . i implies $2 = (perm . k) - 1 ) ) ) & ( k >= i implies ( ( perm . (k + 1) < perm . i implies $2 = perm . (k + 1) ) & ( perm . (k + 1) >= perm . i implies $2 = (perm . (k + 1)) - 1 ) ) ) );
A3:
rng p9 = Seg (n + 1)
by FUNCT_2:def 3;
then A4:
perm . i in Seg (n + 1)
by A1, A2, FUNCT_1:def 3;
A5:
for k9 being object st k9 in Seg n holds
ex y being object st
( y in Seg n & S1[k9,y] )
proof
let k9 be
object ;
( k9 in Seg n implies ex y being object st
( y in Seg n & S1[k9,y] ) )
assume
k9 in Seg n
;
ex y being object st
( y in Seg n & S1[k9,y] )
then consider k being
Nat such that A6:
k9 = k
and A7:
1
<= k
and A8:
k <= n
;
A9:
k < n + 1
by A8, NAT_1:13;
then A10:
k in Seg (n + 1)
by A7;
then A11:
perm . k in Seg (n + 1)
by A2, A3, FUNCT_1:def 3;
set k1 =
k + 1;
A12:
1
+ 0 <= k + 1
by NAT_1:13;
k + 1
<= n + 1
by A9, NAT_1:13;
then A13:
k + 1
in Seg (n + 1)
by A12;
then A14:
perm . (k + 1) in Seg (n + 1)
by A2, A3, FUNCT_1:def 3;
per cases
( ( k < i & perm . k < perm . i ) or ( k < i & perm . k >= perm . i ) or ( k >= i & perm . (k + 1) < perm . i ) or ( k >= i & perm . (k + 1) >= perm . i ) )
;
suppose A18:
(
k < i &
perm . k >= perm . i )
;
ex y being object st
( y in Seg n & S1[k9,y] )then
p9 . k <> p9 . i
by A1, A10, FUNCT_2:19;
then A19:
perm . k > perm . i
by A18, XXREAL_0:1;
then reconsider pk1 =
(perm . k) - 1 as
Element of
NAT by NAT_1:20;
A20:
S1[
k9,
pk1]
by A6, A18;
A21:
pk1 < pk1 + 1
by NAT_1:13;
perm . k <= n + 1
by A11, FINSEQ_1:1;
then
pk1 < n + 1
by A21, XXREAL_0:2;
then A22:
pk1 <= n
by NAT_1:13;
perm . i >= 1
by A4, FINSEQ_1:1;
then
pk1 + 1
> 1
by A19, XXREAL_0:2;
then
pk1 >= 1
by NAT_1:13;
then
pk1 in Seg n
by A22;
hence
ex
y being
object st
(
y in Seg n &
S1[
k9,
y] )
by A20;
verum end; suppose A26:
(
k >= i &
perm . (k + 1) >= perm . i )
;
ex y being object st
( y in Seg n & S1[k9,y] )then
i < k + 1
by NAT_1:13;
then
p9 . (k + 1) <> p9 . i
by A1, A13, FUNCT_2:19;
then A27:
perm . (k + 1) > perm . i
by A26, XXREAL_0:1;
then reconsider pk1 =
(perm . (k + 1)) - 1 as
Element of
NAT by NAT_1:20;
A28:
S1[
k9,
pk1]
by A6, A26;
A29:
pk1 < pk1 + 1
by NAT_1:13;
perm . (k + 1) <= n + 1
by A14, FINSEQ_1:1;
then
pk1 < n + 1
by A29, XXREAL_0:2;
then A30:
pk1 <= n
by NAT_1:13;
perm . i >= 1
by A4, FINSEQ_1:1;
then
pk1 + 1
> 1
by A27, XXREAL_0:2;
then
pk1 >= 1
by NAT_1:13;
then
pk1 in Seg n
by A30;
hence
ex
y being
object st
(
y in Seg n &
S1[
k9,
y] )
by A28;
verum end; end;
end;
consider q being Function of (Seg n),(Seg n) such that
A31:
for x being object st x in Seg n holds
S1[x,q . x]
from FUNCT_2:sch 1(A5);
for x1, x2 being object st x1 in dom q & x2 in dom q & q . x1 = q . x2 holds
x1 = x2
proof
let x1,
x2 be
object ;
( x1 in dom q & x2 in dom q & q . x1 = q . x2 implies x1 = x2 )
assume that A32:
x1 in dom q
and A33:
x2 in dom q
and A34:
q . x1 = q . x2
;
x1 = x2
A35:
dom q = Seg n
by FUNCT_2:52;
then consider k1 being
Nat such that A36:
x1 = k1
and A37:
1
<= k1
and A38:
k1 <= n
by A32;
A39:
0 + 1
<= k1 + 1
by NAT_1:13;
A40:
k1 < n + 1
by A38, NAT_1:13;
then A41:
k1 in Seg (n + 1)
by A37;
k1 + 1
<= n + 1
by A40, NAT_1:13;
then A42:
k1 + 1
in Seg (n + 1)
by A39;
consider k2 being
Nat such that A43:
x2 = k2
and A44:
1
<= k2
and A45:
k2 <= n
by A33, A35;
A46:
k2 < n + 1
by A45, NAT_1:13;
then A47:
k2 in Seg (n + 1)
by A44;
A48:
0 + 1
<= k2 + 1
by NAT_1:13;
k2 + 1
<= n + 1
by A46, NAT_1:13;
then A49:
k2 + 1
in Seg (n + 1)
by A48;
per cases
( ( k1 < i & perm . k1 < perm . i ) or ( k1 < i & perm . k1 >= perm . i ) or ( k1 >= i & perm . (k1 + 1) < perm . i ) or ( k1 >= i & perm . (k1 + 1) >= perm . i ) )
;
suppose A50:
(
k1 < i &
perm . k1 < perm . i )
;
x1 = x2then A51:
q . k1 = p9 . k1
by A31, A32, A36;
per cases
( ( k2 < i & perm . k2 < perm . i ) or ( k2 < i & perm . k2 >= perm . i ) or ( k2 >= i & perm . (k2 + 1) < perm . i ) or ( k2 >= i & perm . (k2 + 1) >= perm . i ) )
;
suppose
(
k2 < i &
perm . k2 < perm . i )
;
x1 = x2then
p9 . k2 = p9 . k1
by A31, A33, A34, A36, A43, A51;
hence
x1 = x2
by A2, A36, A43, A41, A47, FUNCT_1:def 4;
verum end; suppose A52:
(
k2 < i &
perm . k2 >= perm . i )
;
x1 = x2then
q . k2 = (perm . k2) - 1
by A31, A33, A43;
then
(perm . k1) + 1
= perm . k2
by A34, A36, A43, A51;
then
perm . k2 <= perm . i
by A50, NAT_1:13;
then
p9 . k2 = p9 . i
by A52, XXREAL_0:1;
hence
x1 = x2
by A1, A2, A47, A52, FUNCT_1:def 4;
verum end; suppose A53:
(
k2 >= i &
perm . (k2 + 1) < perm . i )
;
x1 = x2then
p9 . k1 = p9 . (k2 + 1)
by A31, A33, A34, A36, A43, A51;
then
k1 = k2 + 1
by A2, A41, A49, FUNCT_1:def 4;
hence
x1 = x2
by A50, A53, NAT_1:13;
verum end; suppose A54:
(
k2 >= i &
perm . (k2 + 1) >= perm . i )
;
x1 = x2then
perm . k1 = (perm . (k2 + 1)) - 1
by A31, A33, A34, A36, A43, A51;
then
(perm . k1) + 1
= perm . (k2 + 1)
;
then
perm . (k2 + 1) <= perm . i
by A50, NAT_1:13;
then
p9 . (k2 + 1) = perm . i
by A54, XXREAL_0:1;
then
k2 + 1
= i
by A1, A2, A49, FUNCT_1:def 4;
hence
x1 = x2
by A54, NAT_1:13;
verum end; end; end; suppose A55:
(
k1 < i &
perm . k1 >= perm . i )
;
x1 = x2then A56:
q . k1 = (perm . k1) - 1
by A31, A32, A36;
per cases
( ( k2 < i & perm . k2 < perm . i ) or ( k2 < i & perm . k2 >= perm . i ) or ( k2 >= i & perm . (k2 + 1) < perm . i ) or ( k2 >= i & perm . (k2 + 1) >= perm . i ) )
;
suppose A57:
(
k2 < i &
perm . k2 < perm . i )
;
x1 = x2then
q . k2 = p9 . k2
by A31, A33, A43;
then
perm . k1 = (perm . k2) + 1
by A34, A36, A43, A56;
then
perm . k1 <= perm . i
by A57, NAT_1:13;
then
perm . k1 = perm . i
by A55, XXREAL_0:1;
hence
x1 = x2
by A1, A2, A41, A55, FUNCT_1:def 4;
verum end; suppose
(
k2 < i &
perm . k2 >= perm . i )
;
x1 = x2then
(perm . k1) - 1
= (perm . k2) - 1
by A31, A33, A34, A36, A43, A56;
hence
x1 = x2
by A2, A36, A43, A41, A47, FUNCT_1:def 4;
verum end; suppose A58:
(
k2 >= i &
perm . (k2 + 1) < perm . i )
;
x1 = x2then
(perm . k1) - 1
= perm . (k2 + 1)
by A31, A33, A34, A36, A43, A56;
then
(perm . (k2 + 1)) + 1
= perm . k1
;
then
perm . k1 <= perm . i
by A58, NAT_1:13;
then
p9 . k1 = p9 . i
by A55, XXREAL_0:1;
hence
x1 = x2
by A1, A2, A41, A55, FUNCT_1:def 4;
verum end; suppose A59:
(
k2 >= i &
perm . (k2 + 1) >= perm . i )
;
x1 = x2then
(perm . k1) - 1
= (perm . (k2 + 1)) - 1
by A31, A33, A34, A36, A43, A56;
then
k1 = k2 + 1
by A2, A41, A49, FUNCT_1:def 4;
hence
x1 = x2
by A55, A59, NAT_1:13;
verum end; end; end; suppose A60:
(
k1 >= i &
perm . (k1 + 1) < perm . i )
;
x1 = x2then A61:
q . k1 = perm . (k1 + 1)
by A31, A32, A36;
per cases
( ( k2 < i & perm . k2 < perm . i ) or ( k2 < i & perm . k2 >= perm . i ) or ( k2 >= i & perm . (k2 + 1) < perm . i ) or ( k2 >= i & perm . (k2 + 1) >= perm . i ) )
;
suppose A62:
(
k2 < i &
perm . k2 < perm . i )
;
x1 = x2then
p9 . (k1 + 1) = p9 . k2
by A31, A33, A34, A36, A43, A61;
then
k1 + 1
= k2
by A2, A47, A42, FUNCT_1:def 4;
hence
x1 = x2
by A60, A62, NAT_1:13;
verum end; suppose A63:
(
k2 < i &
perm . k2 >= perm . i )
;
x1 = x2then
perm . (k1 + 1) = (perm . k2) - 1
by A31, A33, A34, A36, A43, A61;
then
perm . k2 = (perm . (k1 + 1)) + 1
;
then
perm . k2 <= perm . i
by A60, NAT_1:13;
then
p9 . k2 = p9 . i
by A63, XXREAL_0:1;
hence
x1 = x2
by A1, A2, A47, A63, FUNCT_1:def 4;
verum end; suppose
(
k2 >= i &
perm . (k2 + 1) < perm . i )
;
x1 = x2then
q . k2 = perm . (k2 + 1)
by A31, A33, A43;
then
k1 + 1
= k2 + 1
by A2, A34, A36, A43, A42, A49, A61, FUNCT_1:def 4;
hence
x1 = x2
by A36, A43;
verum end; suppose A64:
(
k2 >= i &
perm . (k2 + 1) >= perm . i )
;
x1 = x2then
perm . (k1 + 1) = (perm . (k2 + 1)) - 1
by A31, A33, A34, A36, A43, A61;
then
perm . (k2 + 1) = (perm . (k1 + 1)) + 1
;
then
perm . (k2 + 1) <= perm . i
by A60, NAT_1:13;
then
p9 . (k2 + 1) = p9 . i
by A64, XXREAL_0:1;
then
k2 + 1
= i
by A1, A2, A49, FUNCT_1:def 4;
hence
x1 = x2
by A64, NAT_1:13;
verum end; end; end; suppose A65:
(
k1 >= i &
perm . (k1 + 1) >= perm . i )
;
x1 = x2then A66:
q . k1 = (perm . (k1 + 1)) - 1
by A31, A32, A36;
per cases
( ( k2 < i & perm . k2 < perm . i ) or ( k2 < i & perm . k2 >= perm . i ) or ( k2 >= i & perm . (k2 + 1) < perm . i ) or ( k2 >= i & perm . (k2 + 1) >= perm . i ) )
;
suppose A67:
(
k2 < i &
perm . k2 < perm . i )
;
x1 = x2then
(perm . (k1 + 1)) - 1
= perm . k2
by A31, A33, A34, A36, A43, A66;
then
perm . (k1 + 1) = (perm . k2) + 1
;
then
perm . (k1 + 1) <= perm . i
by A67, NAT_1:13;
then
p9 . (k1 + 1) = p9 . i
by A65, XXREAL_0:1;
then
k1 + 1
= i
by A1, A2, A42, FUNCT_1:def 4;
hence
x1 = x2
by A65, NAT_1:13;
verum end; suppose A68:
(
k2 < i &
perm . k2 >= perm . i )
;
x1 = x2then
(perm . (k1 + 1)) - 1
= (perm . k2) - 1
by A31, A33, A34, A36, A43, A66;
then
k1 + 1
= k2
by A2, A47, A42, FUNCT_1:def 4;
hence
x1 = x2
by A65, A68, NAT_1:13;
verum end; suppose A69:
(
k2 >= i &
perm . (k2 + 1) < perm . i )
;
x1 = x2then
(perm . (k1 + 1)) - 1
= perm . (k2 + 1)
by A31, A33, A34, A36, A43, A66;
then
perm . (k1 + 1) = (perm . (k2 + 1)) + 1
;
then
perm . (k1 + 1) <= perm . i
by A69, NAT_1:13;
then
p9 . (k1 + 1) = p9 . i
by A65, XXREAL_0:1;
then
k1 + 1
= i
by A1, A2, A42, FUNCT_1:def 4;
hence
x1 = x2
by A65, NAT_1:13;
verum end; end; end; end;
end;
then A70:
q is one-to-one
by FUNCT_1:def 4;
card (finSeg N) = card (finSeg N)
;
then
( q is one-to-one & q is onto )
by A70, FINSEQ_4:63;
then reconsider q = q as Element of Permutations n by MATRIX_1:def 12;
take
q
; for k being Nat st k in Seg n holds
( ( k < i implies ( ( perm . k < perm . i implies q . k = perm . k ) & ( perm . k >= perm . i implies q . k = (perm . k) - 1 ) ) ) & ( k >= i implies ( ( perm . (k + 1) < perm . i implies q . k = perm . (k + 1) ) & ( perm . (k + 1) >= perm . i implies q . k = (perm . (k + 1)) - 1 ) ) ) )
thus
for k being Nat st k in Seg n holds
( ( k < i implies ( ( perm . k < perm . i implies q . k = perm . k ) & ( perm . k >= perm . i implies q . k = (perm . k) - 1 ) ) ) & ( k >= i implies ( ( perm . (k + 1) < perm . i implies q . k = perm . (k + 1) ) & ( perm . (k + 1) >= perm . i implies q . k = (perm . (k + 1)) - 1 ) ) ) )
by A31; verum