set A = KurExSet ;
assume
{(Int KurExSet),(Int (Cl KurExSet)),(Int (Cl (Int KurExSet))),(Cl KurExSet),(Cl (Int KurExSet)),(Cl (Int (Cl KurExSet)))} meets {KurExSet}
; contradiction
then A1:
KurExSet in {(Int KurExSet),(Int (Cl KurExSet)),(Int (Cl (Int KurExSet))),(Cl KurExSet),(Cl (Int KurExSet)),(Cl (Int (Cl KurExSet)))}
by ZFMISC_1:50;