let C be Simple_closed_curve; for S being Segmentation of C
for p being Point of (TOP-REAL 2) st p in C holds
ex i being Nat st
( i in dom S & p in Segm (S,i) )
let S be Segmentation of C; for p being Point of (TOP-REAL 2) st p in C holds
ex i being Nat st
( i in dom S & p in Segm (S,i) )
let p be Point of (TOP-REAL 2); ( p in C implies ex i being Nat st
( i in dom S & p in Segm (S,i) ) )
assume A1:
p in C
; ex i being Nat st
( i in dom S & p in Segm (S,i) )
set X = { i where i is Nat : ( i in dom S & LE S /. i,p,C ) } ;
A2:
{ i where i is Nat : ( i in dom S & LE S /. i,p,C ) } c= dom S
A3:
1 in dom S
by FINSEQ_5:6;
A4:
W-min C = S /. 1
by Def3;
then
LE S /. 1,p,C
by A1, JORDAN7:3;
then
1 in { i where i is Nat : ( i in dom S & LE S /. i,p,C ) }
by A3;
then reconsider X = { i where i is Nat : ( i in dom S & LE S /. i,p,C ) } as non empty finite Subset of NAT by A2, XBOOLE_1:1;
reconsider mX = max X as Nat by TARSKI:1;
take
mX
; ( mX in dom S & p in Segm (S,mX) )
A5:
max X in X
by XXREAL_2:def 8;
hence
mX in dom S
by A2; p in Segm (S,mX)
A6:
1 <= max X
by A2, A5, FINSEQ_3:25;
A7:
max X <= len S
by A2, A5, FINSEQ_3:25;
A8:
ex i being Nat st
( max X = i & i in dom S & LE S /. i,p,C )
by A5;
per cases
( max X < len S or max X = len S )
by A7, XXREAL_0:1;
suppose A9:
max X < len S
;
p in Segm (S,mX)A10:
1
<= (max X) + 1
by NAT_1:11;
(max X) + 1
<= len S
by A9, NAT_1:13;
then A11:
mX + 1
in dom S
by A10, FINSEQ_3:25;
A12:
S is
one-to-one
by Def3;
(max X) + 1
>= 1
+ 1
by A6, XREAL_1:6;
then
(max X) + 1
<> 1
;
then A13:
S /. ((max X) + 1) <> S /. 1
by A3, A11, A12, PARTFUN2:10;
A14:
S /. ((max X) + 1) in rng S
by A11, PARTFUN2:2;
A15:
rng S c= C
by Def3;
then
LE p,
S /. ((max X) + 1),
C
by A1, A14, A15, JORDAN16:7;
then
p in { p1 where p1 is Point of (TOP-REAL 2) : ( LE S /. (max X),p1,C & LE p1,S /. ((max X) + 1),C ) }
by A8;
then
p in Segment (
(S /. (max X)),
(S /. ((max X) + 1)),
C)
by A4, A13, JORDAN7:def 1;
hence
p in Segm (
S,
mX)
by A6, A9, Def4;
verum end; end;