let n be Nat; for A being Subset of (Euclid n)
for B being non empty Subset of (Euclid n)
for C being Subset of ((Euclid n) | B) st A = C & C is bounded holds
A is bounded
let A be Subset of (Euclid n); for B being non empty Subset of (Euclid n)
for C being Subset of ((Euclid n) | B) st A = C & C is bounded holds
A is bounded
let B be non empty Subset of (Euclid n); for C being Subset of ((Euclid n) | B) st A = C & C is bounded holds
A is bounded
let C be Subset of ((Euclid n) | B); ( A = C & C is bounded implies A is bounded )
assume that
A1:
A = C
and
A2:
C is bounded
; A is bounded
consider r0 being Real such that
A3:
0 < r0
and
A4:
for x, y being Point of ((Euclid n) | B) st x in C & y in C holds
dist (x,y) <= r0
by A2;
for x, y being Point of (Euclid n) st x in A & y in A holds
dist (x,y) <= r0
proof
let x,
y be
Point of
(Euclid n);
( x in A & y in A implies dist (x,y) <= r0 )
assume A5:
(
x in A &
y in A )
;
dist (x,y) <= r0
then reconsider x0 =
x,
y0 =
y as
Point of
((Euclid n) | B) by A1;
( the
distance of
((Euclid n) | B) . (
x0,
y0)
= the
distance of
(Euclid n) . (
x,
y) & the
distance of
((Euclid n) | B) . (
x0,
y0)
= dist (
x0,
y0) )
by TOPMETR:def 1;
hence
dist (
x,
y)
<= r0
by A1, A4, A5;
verum
end;
hence
A is bounded
by A3; verum