let P be non empty Subset of (TOP-REAL 2); for P1 being Subset of ((TOP-REAL 2) | P)
for f being Function of I[01],((TOP-REAL 2) | P)
for s being Real st s >= 0 & f is being_homeomorphism & P1 = { q0 where q0 is Point of (TOP-REAL 2) : ex ss being Real st
( s < ss & ss <= 1 & q0 = f . ss ) } holds
P1 is open
let P1 be Subset of ((TOP-REAL 2) | P); for f being Function of I[01],((TOP-REAL 2) | P)
for s being Real st s >= 0 & f is being_homeomorphism & P1 = { q0 where q0 is Point of (TOP-REAL 2) : ex ss being Real st
( s < ss & ss <= 1 & q0 = f . ss ) } holds
P1 is open
let f be Function of I[01],((TOP-REAL 2) | P); for s being Real st s >= 0 & f is being_homeomorphism & P1 = { q0 where q0 is Point of (TOP-REAL 2) : ex ss being Real st
( s < ss & ss <= 1 & q0 = f . ss ) } holds
P1 is open
let s be Real; ( s >= 0 & f is being_homeomorphism & P1 = { q0 where q0 is Point of (TOP-REAL 2) : ex ss being Real st
( s < ss & ss <= 1 & q0 = f . ss ) } implies P1 is open )
assume that
A1:
s >= 0
and
A2:
f is being_homeomorphism
and
A3:
P1 = { q0 where q0 is Point of (TOP-REAL 2) : ex ss being Real st
( s < ss & ss <= 1 & q0 = f . ss ) }
; P1 is open
( f is one-to-one & rng f = [#] ((TOP-REAL 2) | P) )
by A2, TOPS_2:def 5;
then A4:
(f ") " = f
by TOPS_2:51;
].s,1.] c= [.0,1.]
then reconsider Q = ].s,1.] as Subset of I[01] by TOPMETR:18, TOPMETR:20;
A6:
( [#] I[01] <> {} & Q is open )
by Th12;
A7:
f " is being_homeomorphism
by A2, TOPS_2:56;
then A8:
f " is one-to-one
by TOPS_2:def 5;
rng (f ") = [#] I[01]
by A7, TOPS_2:def 5;
then
f " is onto
by FUNCT_2:def 3;
then
(f ") " = (f ") "
by A8, TOPS_2:def 4;
then A9:
((f ") ") .: Q = (f ") " Q
by A8, FUNCT_1:85;
( P1 = f .: Q & f " is continuous )
by A1, A2, A3, Th14, TOPS_2:def 5;
hence
P1 is open
by A6, A4, A9, TOPS_2:43; verum