let C be Simple_closed_curve; for n being Nat st n is_sufficiently_large_for C holds
C misses RightComp (Span (C,n))
let n be Nat; ( n is_sufficiently_large_for C implies C misses RightComp (Span (C,n)) )
set f = Span (C,n);
RightComp (Span (C,n)) is_a_component_of (L~ (Span (C,n))) `
by GOBOARD9:def 2;
then A1:
ex L being Subset of ((TOP-REAL 2) | ((L~ (Span (C,n))) `)) st
( L = RightComp (Span (C,n)) & L is a_component )
by CONNSP_1:def 6;
LeftComp (Span (C,n)) is_a_component_of (L~ (Span (C,n))) `
by GOBOARD9:def 1;
then A2:
ex R being Subset of ((TOP-REAL 2) | ((L~ (Span (C,n))) `)) st
( R = LeftComp (Span (C,n)) & R is a_component )
by CONNSP_1:def 6;
assume A3:
n is_sufficiently_large_for C
; C misses RightComp (Span (C,n))
then A4:
C misses L~ (Span (C,n))
by Th8;
C c= the carrier of ((TOP-REAL 2) | ((L~ (Span (C,n))) `))
then reconsider C1 = C as Subset of ((TOP-REAL 2) | ((L~ (Span (C,n))) `)) ;
assume A6:
C meets RightComp (Span (C,n))
; contradiction
A7:
C1 is connected
by CONNSP_1:23;
C meets LeftComp (Span (C,n))
by A3, Th9;
hence
contradiction
by A6, A1, A2, A7, JORDAN2C:92, SPRECT_4:6; verum