let a, b be Real; ( a < b implies [.a,b.] \/ {b} = [.a,b.] )
assume A1:
a < b
; [.a,b.] \/ {b} = [.a,b.]
then [.a,b.] =
[.a,b.[ \/ {b}
by XXREAL_1:129
.=
([.a,b.[ \/ {b}) \/ {b}
by XBOOLE_1:6
;
hence
[.a,b.] \/ {b} = [.a,b.]
by A1, XXREAL_1:129; verum