let n be Nat; for x being Real st n > 0 & x = 1 / (n + 1) holds
(n !) * (Sum (eseq ^\ (n + 1))) <= x / (1 - x)
let x be Real; ( n > 0 & x = 1 / (n + 1) implies (n !) * (Sum (eseq ^\ (n + 1))) <= x / (1 - x) )
assume that
A1:
n > 0
and
A2:
x = 1 / (n + 1)
; (n !) * (Sum (eseq ^\ (n + 1))) <= x / (1 - x)
deffunc H1( Nat) -> object = x ^ ($1 + 1);
consider seq being Real_Sequence such that
A3:
for k being Nat holds seq . k = H1(k)
from SEQ_1:sch 1();
A6: seq . 0 =
x ^ (0 + 1)
by A3
.=
x
;
A7:
eseq ^\ (n + 1) is summable
by Th23, SERIES_1:12;
n + 1 > 0 + 1
by A1, XREAL_1:6;
then A8:
x < 1
by A2, XREAL_1:212;
A9:
now for k being Nat holds seq . (k + 1) = x * (seq . k)let k be
Nat;
seq . (k + 1) = x * (seq . k)thus seq . (k + 1) =
x ^ ((k + 1) + 1)
by A3
.=
(x ^ 1) * (x ^ (k + 1))
by A2, POWER:27
.=
x * (x ^ (k + 1))
.=
x * (seq . k)
by A3
;
verum end;
|.x.| = x
by A2, ABSVALUE:def 1;
then
seq is summable
by A8, A9, SERIES_1:25;
then A10:
Sum ((n !) (#) (eseq ^\ (n + 1))) <= Sum seq
by A4, SERIES_1:20;
|.x.| < 1
by A2, A8, ABSVALUE:def 1;
then
Sum seq = x / (1 - x)
by A6, A9, SERIES_1:25;
hence
(n !) * (Sum (eseq ^\ (n + 1))) <= x / (1 - x)
by A7, A10, SERIES_1:10; verum